Display Error Message On Same Popup Window
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Php Popup Error Message
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Php Popup Message Then Redirect
Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up How error message popup bootstrap to display error message inside a pop up window instead of moving to a new page? up vote 0 down vote favorite I'm new to php, and I'm new here and I don't know if it's right for me to ask a question in such a long manner. I'm sorry if that's not how it is done here. I have the following code which how to show message box in php is used to enter a question and it's four choices. 4 choices are entered in text boxes with a radio button corresponding to each. The button clicked out of those 4 will be the value of $correct $difflevel, $agegroup and $catId are again, the values from a set of radio buttons. The following is my code if(isset($_POST['submit'])) { extract($_POST); $question=mysqli_real_escape_string($con,$question); $option[0]=mysqli_real_escape_string($con,$option[0]); $option[1]=mysqli_real_escape_string($con,$option[1]); $option[2]=mysqli_real_escape_string($con,$option[2]); $option[3]=mysqli_real_escape_string($con,$option[3]); mysqli_query($con,"insert into questions(question, op1,op2,op3,op4,correct,difflevel,ageGroup,catId) values ('$question','$option[0]','$option[1]','$option[2]','$option[3]',$correct,$difflevel,$ageGroup,$catId)") or die("Some error"); $questionId = mysqli_insert_id($con); if($_POST['catId']=="")//QUESTIONS MUST CONTAIN AT LEAST ONE CATEGORY die("Please select category of the question entered."); if($_POST['difflevel']=="")//DIFFICULTY LEVEL SHOULD BE SET die("Please select difficulty of the question entered."); if($_POST['ageGroup']=="")//AGEGROUP SHOULD BE SET die("Please select age group of the question entered."); if($_POST['correct']=="")//CORRECT ANSWER SHOULD BE SET die("Please select correct answer for the question entered."); } Since all fields are mandatory, I need an error report if not all are filled(or clicked). Right now, when the error occur, it's taken to a new page, and hence all that I typed are lost and I have to type them again. So instead of going to the next page, is it possible to show a pop-up window with the err
Detected You currently have javascript disabled. Several functions may not work. Please re-enable javascript to access full functionality. Display error message on same popup window Started by jimsanghvi@hotmail.com, Jul
Javascript Popup Error Message
12 2011 05:21 AM Please log in to reply 1 reply to this php alert message example topic #1 jimsanghvi@hotmail.com jimsanghvi@hotmail.com Member Members 18 posts Posted 12 July 2011 - 05:21 AM I want to display message on
Create Popup Window Using Php
same customised popup window . Say for eg when i click on signin link a popup window comes and when i click on submit button , it get redirected to loginpage.php where php code http://stackoverflow.com/questions/18635358/how-to-display-error-message-inside-a-pop-up-window-instead-of-moving-to-a-new-p for connection is written and other code of php is wriiten for database fetching . and if login credential match it get redirected to main pageSo what i want to do is when some one click on signin link and popup window open up and when clicked on submit button , if the credential dont match it should throw error on same popup window before it closes Back to https://forums.phpfreaks.com/topic/241770-display-error-message-on-same-popup-window/ top #2 mikesta707 mikesta707 Advanced Member Staff Alumni 2,967 posts LocationNew York Posted 12 July 2011 - 05:33 AM PHP is a server side language, so in order to run the PHP code, an actual request must be made to the server (whether it be through a page load, or refresh, or whatever).What you will need to use is AJAX, which will allow you to send a request to the server, and get a response back without needed to refresh to page or load a different one on the client side.Here's an AJAX tutorial: http://www.tizag.com/ajaxTutorial/Note, AJAX is done via Javascript, so If you don't know any javascript, I suggest learning it http:www.pixelacademy.org Our Woes remain un-rectified, and our souls won't be exhumed Back to top Back to PHP Coding Help · Next Unread Topic → 0 user(s) are reading this topic 0 members, 0 guests, 0 anonymous users Reply to quoted postsClear PHP Freaks → PHP Coding → PHP Coding Help Privacy Policy Forum Rules & Terms of Service · Change Theme IP.Board Mobile PHP Freaks PHP Freaks - English (USA) English (USA) PHP Freaks - English (USA) Mark Community Read Forums Members Pages Mark all as read Help Community Forum Software by IP.BoardLice
is moved to the correct category. Anyway. I am pretty new with web design, and I am currently learning about the https://www.sitepoint.com/community/t/how-to-make-an-error-popup-message-after-submitting-a-form/15193 subject on high school. We work on software that is a bit outdated (Adobe CS3), but I still like doing it. As for web design, we use WAMP server, Dreamweaver CS3, MySQL Query Browser and PHP. I do, however, know little to nothing about coding in PHP, I just kind of know what it's for. I know how to make a functioning web page, how to create error message databases and connect them to the web page, and how to show these databases through a dynamic web page, but little else. So the thing I am trying to do now is that after using an "Record Insertion Form Wizard" in Dreamweaver CS3 (to which I've already made a database, a query and so on), I want two different popup messages to come after clicking "submit form", popup error message both one confirming that the entire process was successful, and one saying that the user entered invalid information. I already know how to do the former, by going under Tag , behaviors, clicking the plus-sign, clicking popup message and then just writing the message and hitting "OK". But how do I make a seperate one for if the submission failed? And is it possible if this box automatically tells the user exactly what went wrong? boatmark 2012-04-27 01:50:40 UTC #2 hmm, I think you should use javascript. attach onsubmit event, then do evaluation of the form content something like that: