Echo Mysql Error Message
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Echo Mysql Array
more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question echo mysql result php x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up mysql error message list how to display MySql error in php up vote 14 down vote favorite In PHP, I am trying to execute a long MySql query that depends on the user input. However, my query fails with the following message, "Query Failed". Actually I have printed this message whenever the query fails but I am having hard time looking for the reason behind this failure.
Mysql Error Message Language
Unfortunately, I couldn't find it because the error is not specified on the web page. My question is, is there any way to display the error message that caused the failure on the web page. Thank you. Here's my code, $from= "Findings"; $where=""; if($service!= null) { $from = $from . ", ServiceType_Lookup"; $where= "Findings.ServiceType_ID= ServiceType_Lookup.ServiceType_ID AND ServiceType_Name= ". $service; if($keyword!= null) $where= $where . " AND "; } if( $keyword != null) { $where= $where . "Finding_ID LIKE '%$keyword%' OR ServiceType_ID LIKE '%$keyword%' OR Title LIKE '%$keyword%' OR RootCause_ID LIKE '%$keyword%' OR RiskRating_ID LIKE '%$keyword%' OR Impact_ID LIKE '%$keyword%' OR Efforts_ID LIKE '%$keyword%' OR Likelihood_ID LIKE '%$keyword%' OR Finding LIKE '%$keyword%' OR Implication LIKE '%$keyword%' OR Recommendation LIKE '%$keyword%' OR Report_ID LIKE '%$keyword%'"; } $query = "SELECT Finding_ID, ServiceType_ID, Title, RootCause_ID, RiskRating_ID, Impact_ID, Efforts_ID, Likelihood_ID, Finding, Implication, Recommendation, Report_ID FROM ".$from . " WHERE " . $where; echo "wala 2eshiq"; $this->result = $this->db_link->query($query); if (!$this->result) { printf("Query failed: %s\n", mysqli_connect_error()); exit; } $r = mysqli_query($this->db_link, $query); if($r==false) printf("error: %s\n", mysqli_errno($this->db_link)); php mysql share|improve this question asked Sep 1 '12 at 12:16 Traveling Salesman 55631640 You can
& Database Submit Sign UP Login × Login Username Password Login Cancel Not a member? Sign Up Forgot Password? Contact Us PHP MySQL query with error printing How to write SQL using PHP to apache error message handle the data in MySQL database? In any database driven script we have to update, add, sql server error message modify, data in the tables. By using PHP we can do all this using different functions available in PHP. We will start with
How To Print Mysql Error In Php
very basic function, which will execute any query written in sql and can be applied to MySQL database. SQL Structured Query Language or popularly known as SQL is an universal language to handle database. An introduction and different http://stackoverflow.com/questions/12227626/how-to-display-mysql-error-in-php types of sql command like select, insert, update etc you will get in the sql section of this site. There are some advance SQL commands like left join, linking of tables etc to study. If you are not comfortable with SQL any time you can refer the materials in sql section. There are three steps invoved in this process. Connection to database Build the query and execute Display the data First ensure that you have established your mysql http://www.plus2net.com/php_tutorial/php_mysql_query.php connection through PHP. To get the full details on php mysql connection you can read the article here. If you are using PDO then start with PDO connection string here. PHP Functions & SQL Let us start with the function required to execute one query in PHP. Once you have connection established then we can execute sql command by using PHP function mysql_query(). Here is the syntax of the function. Let us first write the query and store in a variable. We will write a query to create table.$query="CREATE TABLE student ( id int(2) NOT NULL auto_increment, name varchar(50) NOT NULL default '', class varchar(10) NOT NULL default '', mark int(3) NOT NULL default '0', PRIMARY KEY (id) ) TYPE=MyISAM"; We have stored the sql create query in a variable $query and we will pass this as a parameter to the function like below. $rt=mysql_query($query); The above command will execute the query ( stored in variable $query) and we can check the status of the query ( successful or not ) by checking the status of $rt. $rt will be true of the query is successfully executed or it will return false. We will use php if command to check the status of the query. if($rt){echo " Command is successful ";} else {echo "Command is not successful ";} So from the above line we can know that the query has
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name or a keyword or something like that. By default, PHP will not show you exactly what the problem is, only that you wrote a query which is not entirely correct. Let's try writing a faulty query to see the response from PHP: $query = mysql_query("SELECT id, namme FROM test_users"); while($row = mysql_fetch_array($query)) echo $row['id'] . " - " . $row["name"] . " is from " . $row["country"] . "
"; This is the example we are using a lot in this part of the tutorial, but in this case, we have misspelled the name column to provoke an error, which we get: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in test.php on line 7 As you can see, the error is not thrown until we try using the resource returned by the mysql_query() function, which we do when we call the mysql_fetch_array() function, in my file located on line 7. The error is very generic and not very helpful. This is on purpose, because knowledge about your database structure makes your website more vulnerable to SQL injection attacks, a problem we will discuss later on. You might be able to spot the error and fix it in a lot of situations, but if not, you can use the mysql_error() function to get a bit more information abut the problem. This function simply returns any error returned from the last executed MySQL function. You should only use this function for finding and fixing problems, and then remove it again once the problem has been fixed. Here's the above example, but where we call the mysql_error() function to get more information: $query = mysql_query("SELECT id, namme FROM test_users"); while($row = mysql_fetch_array($query)) echo $row['id'] . " - " . $row["name"] . " is from " . $row["country"] . "
"; echo mysql_error(); This will give you a far more useful error message: Unknown column 'namme' in 'field list' Try making various errors in the SQL query and see the message that MySQL returns through the mysql_error() function, to see how it responds. This will help you identify SQL errors better in the future. The above one is very precise and easy to fix, while others can be a bit more cryptic to the untrained eye. PreviousNext Introduction About PHPRequirements IntroductionWebserverPHPUsing it The editor IntroductionPreviewingSyntax checkingDebuggingBasic PHP Hello worldPHP tagsVariablesIf statementsMore if statementsThe switch statementLoopsIncluding filesFunctionsData types IntroductionWorking with numbersWorking with stringsMore stringsWorking with arraysMore