Error Message Display In Java
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: OptionPane«Swing JFC«JavaJavaSwing JFCOptionPaneDisplay error message java error messages and solutions dialog with JOptionPane.ERROR_MESSAGE import javax.swing.JOptionPane; import javax.swing.JPanel; public class JOptionPaneERROR_MESSAGE
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{ public static void main(String[] args) { final JPanel panel = new JPanel(); JOptionPane.showMessageDialog(panel, "Could not java error messages best practices open file", "Error", JOptionPane.ERROR_MESSAGE); } } Related examples in the same category1.A Program that Uses the JOptionPane Class to Get User Input2.Demonstrates JoptionPane3.OptionPane Sample: simple dialog4.JOptionPane demo5.JOptionPane utilities6.Simple Input Dialog7.Demonstrate JOptionPane8.Display warning javascript error messages message dialog with JOptionPane.WARNING_MESSAGE9.Display question message dialog with JOptionPane.QUESTION_MESSAGE10.Display information message dialog with JOptionPane.INFORMATION_MESSAGE11.Show a message dialog with JOptionPane12.Create a message dialog box with different options13.Show message in two lines in a dialog box14.Modal dialog with yes/no button15.Modal dialog with OK/cancel and a text field16.Wait (forever) for a non-null click and then quit17.Create a Confirm Dialog Box18.Create a Message Dialog Box19.Use a JOptionPane20.Yes no cancel dialog21.OK cancel option dialog22.Dialog with default options23.Localize a JOptionPane dialog24.Customize JOptionPane buttons25.Exercise Options26.Modifiable JOptionPane27.Message dialog helper28.Exercise all JOptionPane based dialogsjava2s.com |Email:info at java2s.com|© Demo Source and Support. All rights reserved.
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of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Error messages with Java Swing up vote 4 down vote favorite 2 I have a query on http://www.java2s.com/Code/Java/Swing-JFC/DisplayerrormessagedialogwithJOptionPaneERRORMESSAGE.htm handling error conditions with Java Swing. I am using Netbeans to develop a simple Java Swing app. It is to load in a text file, then run calculation based on the numbers found in the text file. The main Swing class holds the JFrames and JPanels. I have the file loading code as a separate class file. It returns the number of lines read and a List of numbers back to http://stackoverflow.com/questions/11563555/error-messages-with-java-swing the main Swing app. I realised that if the file reading fails (i.e. try -> catch (Exception ex)), the entire app will crash. What's the best way to handle errors resulting from my scenario above? That is to say, the file loading code crashes and I don't want the entire program to crash. I want the program to say the file is corrupted and wait for user to load new file. Any thoughts? Yakult java swing netbeans share|improve this question edited Jul 19 '12 at 14:57 ewok 5,1301556124 asked Jul 19 '12 at 14:56 Poliquin 71821330 2 Maybe you should show some code to see what you do exactly? –Wim Deblauwe Jul 19 '12 at 14:58 add a comment| 3 Answers 3 active oldest votes up vote 4 down vote accepted when you catch the exception, run: JOptionPane.showMessageDialog("File is corrupted. Please select a new file."); Then display the file dialog again. It's probably best to do this as a loop that continues while the the file is not valid. If there is a corruption, then rather than throwing an exception, set a boolean flag and loop as long as the flag is set. That way, when a good file is found, the while loop will terminate. Example: public static void main(String[] ar
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow http://stackoverflow.com/questions/6270354/how-to-open-warning-information-error-dialog-in-swing the company Business Learn more about hiring developers or posting ads with us Stack http://stackoverflow.com/questions/3666879/java-how-can-i-println-an-error-message-when-the-comand-line-argument-is-not-a Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up how to open warning/information/error dialog in swing? up vote 17 down vote favorite 3 How to open warning/information/error error message dialog in swing? I need standard error dialog with "Ok" button and "red cross" image. I.e. analog of org.eclipse.jface.dialogs.MessageDialog.openError() java swing joptionpane share|improve this question edited Jun 26 '12 at 7:49 mKorbel 99.8k1384201 asked Jun 7 '11 at 19:10 javapowered 6,0002490202 add a comment| 3 Answers 3 active oldest votes up vote 29 down vote accepted See How to Make Dialogs. You can use: JOptionPane.showMessageDialog(frame, "Eggs are not supposed to be green."); java error messages And you can also change the symbol to an error message or an warning. E.g see JOptionPane Features. share|improve this answer answered Jun 7 '11 at 19:12 Jonas 34.1k69210303 add a comment| up vote 9 down vote import javax.swing.JFrame; import javax.swing.JOptionPane; public class ErrorDialog { public static void main(String argv[]) { String message = "\"The Comedy of Errors\"\n" + "is considered by many scholars to be\n" + "the first play Shakespeare wrote"; JOptionPane.showMessageDialog(new JFrame(), message, "Dialog", JOptionPane.ERROR_MESSAGE); } } share|improve this answer answered Jun 11 '14 at 13:36 Said Erraoudy 37536 add a comment| up vote 8 down vote JOptionPane.showOptionDialog JOptionPane.showMessageDialog .... Have a look on this tutorial on how to make dialogs. share|improve this answer answered Jun 7 '11 at 19:13 Heisenbug 26k1884155 thanks, this works –javapowered Jun 7 '11 at 19:20 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy and terms of service. Not the answer you're looking for? Browse other questions tagged java swing joptionpane or ask your own question. asked 5 years ago viewed 51492
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Java: How can I println an error message when the comand line argument is not a valid integer? up vote 2 down vote favorite 1 I made an application in Java that calculates the sum of all numbers up untill the input in the command line. But, if one would put in a double or string in the command line i need to display an error message that says only real numbers can be put in. How can i do this? I think it needs to be with exception or something? public static void main(String[] args) { right here? int n = Integer.parseInt(args[0]); thanks! java share|improve this question asked Sep 8 '10 at 10:43 sjaak 36125 add a comment| 4 Answers 4 active oldest votes up vote 7 down vote public static void main(String[] args) { try { int n = Integer.parseInt(args[0]); } catch (NumberFormatException e) { //here you print the error System.out.println("Error: only real numbers can be put in"); //or System.err.println("Error: only real numbers can be put in"); } } share|improve this answer answered Sep 8 '10 at 10:48 Tomas Narros 9,74212442 add a comment| up vote 2 down vote The call to Integer.parseInt(args[0]) does the hard work for you, it throws a NumberFormatException That you can simply catch and print any error message you like. public static void main(String[] args) { try { int n = Integer.parseInt(args[0]); } catch(NumberFormatException e){ System.out.println("The input value given is not a valid integer."); } } share|improve this answer edited Sep 8 '10 at 15:23 answered Sep 8 '10 at 11:32 Tendayi Mawushe 15.5k43549 add a comment| up vote 1 down vote Integer.parseInt(args[0]) will throw a NumberFormatException if it cannot parse the string to an int. Simply catch it