How To Create An Error Message In Java
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Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it java print exception message only takes a minute: Sign up Java. How to make an error message for when userInput is a string instead of an int? up vote 0 down vote favorite I'm working on a sort of test in Java, in which the user is given a question like this: " 4 + ? = 12". The numbers are randomised and so joptionpane input is the questionsmark. I need to make an error message for when the user input isn't an int. For example if the user types in the word "eight" instead of "8" an error message will show up. How can I do this? java user-input share|improve this question edited Feb 14 at 4:03 Joel Coehoorn 248k92440661 asked Sep 6 '14 at 12:22 Mikaela 912 3 Have you read about exception handling? –PakkuDon Sep 6 '14 at 12:23 2 You could try to convert the string response to an integer and catch the exception if the conversion fails (using a try ... catch block –ErstwhileIII Sep 6 '14 at 12:23 We can't do anything but guess without much more data. Are you making a GUI? Are you making a command-line program? –bmargulies Sep 6 '14 at 13:43 add a comment| 3 Answers 3 active oldest votes up vote 2 down vote Scanner scanner = new Scanner(System.in); String input = scanner.nextLine();//get the next input line scanner.close(); Integer value = null; try { value = Integer.valueOf(input); //if value ca
LDAPJPAJSPJSTLLanguage BasicsNetwork ProtocolPDF RTFReflectionRegular ExpressionsScriptingSecurityServletsSpringSwing ComponentsSwing JFCSWT JFace EclipseThreadsTiny ApplicationVelocityWeb Services SOAXMLError message dialog : Dialog«Swing JFC«JavaJavaSwing JFCDialogError message dialog import javax.swing.JFrame; import javax.swing.JOptionPane;
Jdialog Example
public class ErrorDialog { public static void main(String java try catch argv[]) { String message = "\"The Comedy of Errors\"\n" + "is
Exception Java
considered by many scholars to be\n" + "the first play Shakespeare wrote"; JOptionPane.showMessageDialog(new JFrame(), message, "Dialog", JOptionPane.ERROR_MESSAGE); } } Related http://stackoverflow.com/questions/25700196/java-how-to-make-an-error-message-for-when-userinput-is-a-string-instead-of-an examples in the same category1.Creating and using Dialog Boxes2.Dialog boxes and creating your own components3.A frame that can easily support internal frame dialogs4.An example of using the JOptionPane with a custom list of options in an5.See the differences between http://www.java2s.com/Code/Java/Swing-JFC/Errormessagedialog.htm various types of option panes6.Vote Dialog7.Create simple about dialog8.Dialog separator9.Message dialog10.Information dialog with customized logo11.Input dialog with user-defined logo12.Confirmation dialog13.Default button for dialog: press Enter to activate14.Simple dialog for asking a yes no question15.Class to Prompt the User for an ID and Password16.Simple Save Dialog demo17.Demonstrate JOptionPane18.Create Color Sample Popup19.Simple Input Dialog20.No button dialog21.Message Dialog demo 22.Escape Key close Dialog23.Dialog can be closed by pressing the escape key24.Dialog which displays indeterminate progress25.Dialog with Escape Key26.Modal Message Dialog27.A frame with a menu whose File->Connect action shows a password dialog28.A sample modal dialog that displays a message and waits for the user to click the Ok buttonjava2s.com |Email:info at java2s.com|© Demo Source and Support. All rights reserved.
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Exception HandlingIn java we have already defined exception classes such as ArithmeticException, ArrayIndexOutOfBoundsException, NullPointerException etc. There are certain conditions defined for these exceptions and on the occurrence of those conditions they are implicitly thrown by JVM(java virtual machine). Do you know that a programmer can create a new exception and throw it explicitly? These exceptions are known as user-defined exceptions. In order to throw user defined exceptions, throw keyword is being used. In this tutorial, we will see how to create a new exception and throw it in a program using throw keyword. You can also throw an already defined exception like ArithmeticException, IOException etc. Syntax of throw statement throw AnyThrowableInstance; Example: //A void method public void sample() { //Statements //if (somethingWrong) then IOException e = new IOException(); throw e; //More Statements } Note: A call to the above mentioned sample method should be always placed in a try block as it is throwing a checked exception - IOException. This is how it the call to above method should be done: MyClass obj = new MyClass(); try{ obj.sample(); }catch(IOException ioe) { //Your error Message here System.out.println(ioe); } Exceptions in java are compulsorily of type Throwable. If you attempt to throw an object that is not throwable, the compiler refuses to compile your program and it would show a compilation error. Flow of execution while throwing an exception using throw keyword Whenever a throw statement is encountered in a program the next statement doesn't execute. Control immediately transferred to catch block to see if the thrown exception is handled there. If the exception is not handled there then next catch block is being checked for exception and so on. If none of the catch block is handling the thrown exception then a system generated exception message is being populated on screen, same what we get for un-handled exceptions. E.g. class ThrowDemo{ public static void main(String args[]){ try{ char array[] = {'a','b','g','j'}; /*I'm displaying the value which does not * exist so this should throw an exception */ System.out.println(