Python Oserror Errno 8 Exec Format Error
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Oserror: [errno 8] Exec Format Error Selenium
more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags errno 8 exec format error ansible Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, "exec format error" linux helping each other. Join them; it only takes a minute: Sign up subprocess.Popen(): OSError: [Errno 8] Exec format error in python? up vote 3 down vote favorite 1 Yesterday, I wrote and ran a python script which executes
Enoexec
a shell using subprocess.Popen(command.split()) where command is string which constitutes .sh script and its argument. This script was working fine till yesterday. Today, I ran the same script and now i am contiguously hitting by this error. p=subprocess.Popen(shell_command.split()) File "/usr/lib/python2.7/subprocess.py", line 679, in __init__ errread, errwrite) File "/usr/lib/python2.7/subprocess.py", line 1249, in _execute_child raise child_exception OSError: [Errno 8] Exec format error I know there are similar questions has been asked before related to this question. But, in
Call Shell Script From Python
my case i tried everything which doesn't solve my purpose. Using shell=True is not able to work because my shell script calls an another shell script before which some environment has to be set in order to ran that script. I am badly stuck in this. ?? I just restart my system once. I am using ubuntu 12.04 EDIT: import subprocess import os import sys arg1=sys.argv[1] arg2=sys.argve[2] shell_command = 'my_path/my_shell.sh ' + arg1 + ' '+ arg2 P = subprocess.Popen(shell_command.split()) P.wait() my_shell.sh: arg1=$1 arg2=$2 cd $TOP setup the environment and run shell script build the kernel ... execute shell command ..... python linux shell share|improve this question edited Nov 7 '14 at 19:13 asked Nov 7 '14 at 18:42 Amit Sharma 8211516 Have you tried import shlex and using shlex.split(shell_command)? Docs: docs.python.org/2/library/shlex.html –Curtis Mattoon Nov 7 '14 at 18:52 Yes, it gives same error. :( –Amit Sharma Nov 7 '14 at 18:56 Can you post your shell_command and the rest of the (relevant) code? Also, the shebang line of your script? –Curtis Mattoon Nov 7 '14 at 19:00 @Curtis Matttoon ping.. –Amit Sharma Nov 7 '14 at 19:19 1 What's the first line of your script? (#!/usr/bin/...?) Does the shell script actually exist in the path indicated? You might be better served with using absolute paths in
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Bash Cannot Execute Binary File
more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us shebang bash Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like http://stackoverflow.com/questions/26807937/subprocess-popen-oserror-errno-8-exec-format-error-in-python you, helping each other. Join them; it only takes a minute: Sign up Is this the right way to run a shell script inside Python? up vote 28 down vote favorite 1 import subprocess retcode = subprocess.call(["/home/myuser/go.sh", "abc.txt", "xyz.txt"]) When I run these 2 lines, will I be doing exactly this?: /home/myuser/go.sh abc.txt xyz.txt Why do I http://stackoverflow.com/questions/4834483/is-this-the-right-way-to-run-a-shell-script-inside-python get this error? But when I run go.sh normally, I don't get that error. File "/usr/lib/python2.6/subprocess.py", line 480, in call return Popen(*popenargs, **kwargs).wait() File "/usr/lib/python2.6/subprocess.py", line 633, in __init__ errread, errwrite) File "/usr/lib/python2.6/subprocess.py", line 1139, in _execute_child raise child_exception OSError: [Errno 8] Exec format error python linux bash shell unix share|improve this question edited Jan 29 '11 at 1:30 asked Jan 29 '11 at 1:20 TIMEX 41.2k201525826 6 Does your shell script have the correct hashbang? –William Jan 29 '11 at 1:43 1 Did you ever solve this? –Johnsyweb May 10 '13 at 2:06 add a comment| 6 Answers 6 active oldest votes up vote 31 down vote OSError: [Errno 8] Exec format error This is an error reported by the operating system when trying to run /home/myuser/go.sh. It looks to me like the shebang (#!) line of go.sh is not valid. Here's a sample script that runs from the shell but not from Popen: #\!/bin/sh echo "You've just called $0 $@." Removing the \
Sign in Pricing Blog Support Search GitHub This repository Watch 49 Star 23 Fork 24 dronekit/dronekit-sitl Code Issues https://github.com/dronekit/dronekit-sitl/issues/93 37 Pull requests 0 Projects 0 Pulse Graphs New issue OSError: [Errno 8] Exec format error #93 Open alduxvm opened this Issue Jun 6, 2016 · 10 http://superuser.com/questions/869985/ansible-command-task-runs-into-exec-format-error comments Projects None yet Labels None yet Milestone No milestone Assignees No one assigned 4 participants alduxvm commented Jun 6, 2016 Hi! I exec format just did a fresh install of Ubuntu LTS 14.04 on a virtual machine, and installed using sudo pip install dronekit-sitl. When trying to open a instance, I get this error: aldux@ubuntu:~/Flight-Stack/simulator$ dronekit-sitl copter --home=55.870595,-4.287639,0,0 Using MAVLink 1.0 os: linux, apm: copter, release: stable Downloading SITL from http://dronekit-assets.s3.amazonaws.com/sitl/copter/sitl-linux-copter-3.3.tar.gz Extracted. Execute: /home/aldux/.dronekit/sitl/copter-3.3/apm --home=55.870595,-4.287639,0,0 --model=quad Traceback (most exec format error recent call last): File "/usr/local/bin/dronekit-sitl", line 9, in
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Super User Questions Tags Users Badges Unanswered Ask Question _ Super User is a question and answer site for computer enthusiasts and power users. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top Ansible command-task runs into “Exec format error” up vote 1 down vote favorite I wrote this ansible task to run a process on a remote vagrant box. (Well, actually the ansible file itself is much longer, but this is a reproducer that only runs the start script.) --- - hosts: myappname_server vars_files: - install_myappname_vars.yaml gather_facts: false sudo: true sudo_user: "{{ project_name }}" tasks: - name: Restart application command: "{{ project_target_dir_env }}/run" args: chdir: "{{ project_target_dir_env }}" It works with these vars in the included vars file: --- project_name: myappname project_source_dir_files: files/myappname project_source_dir_env: "{{ project_source_dir_files }}/environment_files" project_target_root: /home/myappname project_target_dir_env: "{{ project_target_root }}/bin" The idea is to use user "myappname" on the remote box (aliased correctly by "myappname_server", other plays I run against is work just fine) to run "/home/myappname/bin/run" after changing the directory to "/home/myappname/bin". If I do that manually, everything works fine, i.e. the dirs exist, the files are readable, the script works etc., all great. But if I execute the script, something seems to be wrong with the generation of the ansible execution code. Is it me and my config hope so)? Is it ansible? I ran it with -vvvv to get a lot of information: monsterkill@monsterkill-ub-dt:~/playbooks$ ansible-playbook install_myappname_resta