How To Fix Stack Overflow Error Java
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up What does StackOverflowError mean in Java? What is its fix? up vote 1 down vote favorite I'm encountering the following error: Exception in thread "main" java.lang.StackOverflowError at Account.draw(Account.java:47) This is the relevant section of code: public double draw(double c) { if (c > 0) { return c; } else if (c < 0 && c > AccBalance) { AccBalance=-c; return AccBalance; } java.lang.stackoverflowerror eclipse return draw(c); } How can I fix this? java stack-overflow share|improve this question edited Sep 24 '13 at 19:30 thegrinner 5,94512750 asked Sep 24 '13 at 19:21 Abdul Moeed 93 1 It means you've recursed too deep and have run out of space in the stack. –thegrinner Sep 24 '13 at 19:24 okay, so how do I fix it ? –Abdul Moeed Sep 24 '13 at 19:25 2 Oh, come on downvoter, this is a perfectly legitimate question. –Tenner Sep 24 '13 at 19:25 1 @Tenner I didn't down vote it, but I have no idea why it's being upvoted. This question is easily google-able. –CyberneticTwerkGuruOrc Sep 24 '13 at 19:28 2 A StackOverflowError is Google-able, sure, but if you're new to programming like the submitter is, something like Wikipedia's first sentence, "In software, a stack overflow occurs when the stack pointer exceeds the stack bound" probably doesn't mean anything to you. We can still help the poor guy. –Tenner Sep 24 '13 at 19:30 | show 4 more comments 3 Answers 3 active oldest votes up vote 4 down v
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How To Resolve Java Lang Stackoverflowerror
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Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a java.lang.stackoverflowerror: null minute: Sign up What is a StackOverflowError? up vote 221 down vote favorite 73 What is a StackOverflowError, what causes it, and how should I deal with them? java exception-handling stack-overflow share|improve this question edited Jun 19 '15 at 4:55 asked http://stackoverflow.com/questions/18990232/what-does-stackoverflowerror-mean-in-java-what-is-its-fix Oct 18 '08 at 8:13 Ziggy 7,384165375 add a comment| 11 Answers 11 active oldest votes up vote 229 down vote accepted Parameters and local variables are allocated on the stack (with reference types the object lives on the heap and a variable references that object). The stack typically lives at the upper end of your address space and as it is used up it heads towards the bottom of the address space (i.e. towards zero). Your process also has a heap, which http://stackoverflow.com/questions/214741/what-is-a-stackoverflowerror lives at the bottom end of your process. As you allocate memory this heap can grow towards the upper end of your address space. As you can see, there is the potential for the heap to "collide" with the stack (a bit like tectonic plates!!!). The common cause for a stack overflow is a bad recursive call. Typically this is caused when your recursive functions doesn't have the correct termination condition, so it ends up calling itself forever. However, with GUI programming it's possible to generate indirect recursion. For example, your app may be handling paint messages and whilst processing them it may call a function that causes the system to send another paint message. Here you've not explicitly called yourself, but the OS/VM has done it for you. To deal with them you'll need to examine your code. If you've got functions that call themselves then check that you've got a terminating condition. If you have then check than when calling the function you have at least modified one of the arguments, otherwise there'll be no visible change for the recursively called function and the terminating condition is useless. If you've got no obvious recursive functions then check to see if you're calling any library functions that indirectly will cause your function to be called (like the implicit case above). share|improve this answer edited Jul 22 '14 at 3:05 CandiedOrange 3,5251037 answered Oct 18 '08 at 8:34 Sean 34.8k952101 1 Original poster: h
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