Java Lang Stackoverflowerror Error
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How To Solve Stack Overflow Error In Java
Stack Overflow the company Business Learn more about hiring developers or posting ads with java.lang.stackoverflowerror eclipse us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is how to resolve java lang stackoverflowerror a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up What is a StackOverflowError? up vote 221 down vote favorite 74 What is a https://examples.javacodegeeks.com/java-basics/exceptions/java-lang-stackoverflowerror-how-to-solve-stackoverflowerror/ StackOverflowError, what causes it, and how should I deal with them? java exception-handling stack-overflow share|improve this question edited Jun 19 '15 at 4:55 asked Oct 18 '08 at 8:13 Ziggy 7,384165475 add a comment| 11 Answers 11 active oldest votes up vote 230 down vote accepted Parameters and local variables are allocated on the stack (with reference types the object lives on the heap and a variable references that object). The http://stackoverflow.com/questions/214741/what-is-a-stackoverflowerror stack typically lives at the upper end of your address space and as it is used up it heads towards the bottom of the address space (i.e. towards zero). Your process also has a heap, which lives at the bottom end of your process. As you allocate memory this heap can grow towards the upper end of your address space. As you can see, there is the potential for the heap to "collide" with the stack (a bit like tectonic plates!!!). The common cause for a stack overflow is a bad recursive call. Typically this is caused when your recursive functions doesn't have the correct termination condition, so it ends up calling itself forever. However, with GUI programming it's possible to generate indirect recursion. For example, your app may be handling paint messages and whilst processing them it may call a function that causes the system to send another paint message. Here you've not explicitly called yourself, but the OS/VM has done it for you. To deal with them you'll need to examine your code. If you've got functions that call themselves then check that you've got a terminating condition. If you have then check than when calling the function you have at least modified one of the a
My Publications Saturday, July 4, 2009 Diagnosing and Resolving StackOverflowError A recent JavaWorld Community forum message (Stack Overflow after instantiating new object) reminded me that http://marxsoftware.blogspot.com/2009/07/diagnosing-and-resolving.html the basics of the StackOverflowError are not always understood well by people new to Java. Fortunately, the StackOverflowError is one of the easier of the runtime errors https://coderanch.com/t/551455/java/java/Exception-java-lang-StackOverflowError to debug and in this blog posting I will demonstrate how easy it often is to diagnose a StackOverflowError. Note that the potential for stack overflow is how to not limited to Java.Diagnosing the cause of a StackOverflowError can be fairly straightfoward if the code has been compiled with the debug option turned on so that line numbers are available in the resulting stack trace. In such cases, it is typically simply a matter of finding the repeating pattern of line numbers in stack overflow error the stack trace. The pattern of repeating line numbers is helpful because a StackOverflowError is often caused by unterminated recursion. The repeating line numbers indicate the code that is being directly or indirectly recursively called. Note that there are situations other than unbounded recursion in which a stack overflow might occur, but this blog posting is limited to StackOverflowError caused by unbounded recursion.The relationship of recursion gone bad to StackOverflowError is noted in the Javadoc description for StackOverflowError that states that this Error is "Thrown when a stack overflow occurs because an application recurses too deeply." It is significant that StackOverflowError ends with the word Error and is an Error (extends java.lang.Error via java.lang.VirtualMachineError) rather than a checked or runtime Exception. The difference is significant. The Error and Exception are each a specialized Throwable, but their intended handling is quite different. The Java Tutorial points out that Errors are typically external to the Java application and thus normally cannot an
Certification Databases Caching Books Engineering Languages Frameworks Products This Site Careers Other all forums Forum: Beginning Java Exception -- java.lang.StackOverflowError Mustafa Dasorwala Greenhorn Posts: 29 posted 5 years ago Hi, This is my first post to any forum, hope I've posted it in the right place ............... The following is a program to solve a sudoku, the program has some bugs that I am not able to figure out. I've also give the (error) at the end................. (It definitely is the most inefficient implementation of Sudoku solver) //__________________________________________________________________________ /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package sudokumain; /** * * @author Mustafa */ public class SudokuMain { /** * @param args the command line arguments */ public static void main(String[] args){ // TODO code application logic here try { Sudoku s = new Sudoku(); s.go(); }catch(Exception e) { System.out.println("WWWWWWWW"); } } } //___________________________________________________________________________ package sudokumain; public class Cell { int value = 0; Boolean canChange = true; //make it false in case of predefined nos on the board } //_______________________________________________________________________________ /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package sudokumain; /** * * @author Mustafa */ public class Sudoku { Cell[][] board = new Cell[9][9]; int firstChangableCell = 0; int x, y; Boolean goback = false; public void go() { // create board start String input = "360000000004230800000004200070460003820000014500013020001900000007048300000000045"; int k = 0; for (int i = 0; i < 9; i++) { for (int j = 0; j < 9; j++) { Cell c = new Cell(); //System.out.println(Integer.parseInt(((Character) input.charAt(k)).toString())); c.value = Integer.parseInt(((Character) input.charAt(k)).toString()); if (c.value != 0) { c.canChange = false; } k++; board[i][j] = c; } } display(); SudokuSolver(0, 0); //display(); //create board ends } public void display() { for (int i = 0; i < 9; i++) { for (int j = 0; j < 9; j++) { System.out.print(board[i][j].value + " "); } System.out.println(""); } } void SudokuSolver(int i, int j) { try { if(i == 7 && j == 7) { System.out.println("XXXXXXXXX"); } if (board[i][j].canChange == false) { if (firstChangableCell == 0) { x = i; y = j; } } else { firstChangableCell = 1; Boolean checkReturn = false; int val = board[i][j].value; val++; for (int k = val; k <= 9; k++) { if (k == 10) { break; } checkReturn = check(i, j, k); if (checkReturn == tru