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Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs php mysqli error Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join http://php.net/manual/en/function.mysql-error.php them; it only takes a minute: Sign up how to display MySql error in php up vote 14 down vote favorite In PHP, I am trying to execute a long MySql query that depends on the user input. However, my query fails with the following message, "Query Failed". Actually I have printed this message whenever the query fails but I http://stackoverflow.com/questions/12227626/how-to-display-mysql-error-in-php am having hard time looking for the reason behind this failure. Unfortunately, I couldn't find it because the error is not specified on the web page. My question is, is there any way to display the error message that caused the failure on the web page. Thank you. Here's my code, $from= "Findings"; $where=""; if($service!= null) { $from = $from . ", ServiceType_Lookup"; $where= "Findings.ServiceType_ID= ServiceType_Lookup.ServiceType_ID AND ServiceType_Name= ". $service; if($keyword!= null) $where= $where . " AND "; } if( $keyword != null) { $where= $where . "Finding_ID LIKE '%$keyword%' OR ServiceType_ID LIKE '%$keyword%' OR Title LIKE '%$keyword%' OR RootCause_ID LIKE '%$keyword%' OR RiskRating_ID LIKE '%$keyword%' OR Impact_ID LIKE '%$keyword%' OR Efforts_ID LIKE '%$keyword%' OR Likelihood_ID LIKE '%$keyword%' OR Finding LIKE '%$keyword%' OR Implication LIKE '%$keyword%' OR Recommendation LIKE '%$keyword%' OR Report_ID LIKE '%$keyword%'"; } $query = "SELECT Finding_ID, ServiceType_ID, Title, RootCause_ID, RiskRating_ID, Impact_ID, Efforts_ID, Likelihood_ID, Finding, Implication, Recommendation, Report_ID FROM ".$from . " WHERE " . $where; echo "wala 2eshiq"; $this->result = $this->db_link->query($query); if (!$this->result) { printf("Query failed: %s\n", mysqli_connect_error()); exit; } $r = mysqli_query($this
Login Cancel Not a member? Sign Up Forgot Password? Contact Us Error message displaying after execution of a query We can http://www.plus2net.com/sql_tutorial/mysql_error.php display error message in case of an error generated by mysql query. https://www.drupal.org/node/825798 This meaning full error message gives idea one the problem or bugs in the script. We can print the error message by using mysql function mysql_error(). This function returns the error message associated with most recently executed query. So it is a good idea to check for error before going mysql error to next query. We can even add the error number returned by mysql to this error message. This way we can generate a meaningful detail on the bugs on the script. MySQL Error MySQL Error No Error Message Error Mail $querry = mysql_query("SELECT new_field FROM student"); echo "Error message = ".mysql_error(); In our student table there is no field as new_field. Here mysql error message here is the message we will get Error message = Unknown column 'new_field' in 'field list' Note that mysql_error() is deprecated as of PHP 5.5.0 so better to avoid using this function. So if you are using PDO then we can use errorInfo() to display the returned error message from MySQL Here is a sample code in PHP using PDO to display record and on failure to display error message. require 'config-pdo.php'; // database connection string $pdo=$dbo->prepare('Select no_name from student'); if($pdo->execute()){ echo 'Success
'; $row = $pdo->fetch(PDO::FETCH_OBJ); echo "Name : $row->name "; }else{ print_r($pdo->errorInfo()); } In the above code there is an error in sql , there is no column by name no_name. The output will be Array ( [0] => 42S22 [1] => 1054 [2] => Unknown column 'no_name' in 'field list' ) So to get correct result change the sql part like this . $pdo=$dbo->prepare('Select * from student'); With this you will get desired output. Handling PDO errors If such error occurs what is to be done ? We have three options to handle in case of errors. We can stop the execution
all over the world. Join today Community Community Home Getting Involved Chat Forum SupportPost installation How to gracefully display an occasional MySQL error when it occurs inside my .module (and avoid a "white screen") Posted by contractor on June 12, 2010 at 5:35pm I have written a simple .module that successfully displays data inside a Drupal block using data retrieved from a remote MySQL database. However, if some error occurs (such as the remote server changes passwords or perhaps the connection is down) I get the dreaded white screen. But, if I hit the BACK button on my browser then I see my Drupal page and within it I find the unformatted MySQL error message that usually looks something like this: warning: mysql_connect() [function.mysql-connect]: Access denied for user 'blah blah blah'@'blah blah.com' (using password: YES) in /home/blah.blah/public_html/...blahblah...../modules/my_list/my_list.module on line 77. NOTE: actually GETTING the MySQL error is NOT my problem - since I expect to occasionally have a connection error. My problem is: how do I gracefully intercept the error and display it to the user in a friendly manner (and the "white screen" is certainly not friendly)? When I get these errors I can simply hit the BACK button and see the error, so I know that the MySQL error is being sent to my themed Drupal page, but apparently after that occurs an additional "white screen" is sent to my browser (so two screens are sent to my browser: one with my themed page that contains an unformatted MySQL error message, and one that is the "white screen"). After some research, I thought the "white screen" effect was to be expected if I am using an external database and exit the module without restoring the 'default' Drupal database, however my code shows that I am doing that and yet the "white screen" still occurs: function _my_remote_mysql_list() { $save_url = $db_url; // save active Drupal database in case we need to restore db_set_active('sample'); $server = "remotehostname"; $username = "username"; $password = "mysqlpassword"; $dbase = "test"; $table = "sampletable"; $link = mysql_connect($server,$username,$password); if (!$link) { db_set_active($save_url); die(mysql_error()); } ... My questions are: 1. How can I avoid displaying the "white screen" effect whenever I encounter an occasional MySQL error inside of my block module, and 2. How can I intercept and nicely format the actual MySQL error message - OR - (even better) how can I display a message that says "Try again