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& Database Submit Sign UP Login × Login Username Password Login Cancel Not a member? Sign Up Forgot Password? Contact Us PHP MySQL query with error printing How to write SQL using PHP to handle the data in MySQL http://www.plus2net.com/php_tutorial/php_mysql_query.php database? In any database driven script we have to update, add, modify, data in the tables. By using PHP we can do all this using different functions available in PHP. We will start with very basic function, which will execute any http://www.php5-tutorial.com/mysql/handling-errors/ query written in sql and can be applied to MySQL database. SQL Structured Query Language or popularly known as SQL is an universal language to handle database. An introduction and different types of sql command like select, insert, update etc you mysql error will get in the sql section of this site. There are some advance SQL commands like left join, linking of tables etc to study. If you are not comfortable with SQL any time you can refer the materials in sql section. There are three steps invoved in this process. Connection to database Build the query and execute Display the data First ensure that you have established your mysql connection through PHP. To get the full details on php mysql connection you can display mysql error read the article here. If you are using PDO then start with PDO connection string here. PHP Functions & SQL Let us start with the function required to execute one query in PHP. Once you have connection established then we can execute sql command by using PHP function mysql_query(). Here is the syntax of the function. Let us first write the query and store in a variable. We will write a query to create table.$query="CREATE TABLE student ( id int(2) NOT NULL auto_increment, name varchar(50) NOT NULL default '', class varchar(10) NOT NULL default '', mark int(3) NOT NULL default '0', PRIMARY KEY (id) ) TYPE=MyISAM"; We have stored the sql create query in a variable $query and we will pass this as a parameter to the function like below. $rt=mysql_query($query); The above command will execute the query ( stored in variable $query) and we can check the status of the query ( successful or not ) by checking the status of $rt. $rt will be true of the query is successfully executed or it will return false. We will use php if command to check the status of the query. if($rt){echo " Command is successful ";} else {echo "Command is not successful ";} So from the above line we can know that the query has worked or failed. But we will not come to know what the error is if the query has failed. To get the error message we have to use another
name or a keyword or something like that. By default, PHP will not show you exactly what the problem is, only that you wrote a query which is not entirely correct. Let's try writing a faulty query to see the response from PHP: $query = mysql_query("SELECT id, namme FROM test_users"); while($row = mysql_fetch_array($query)) echo $row['id'] . " - " . $row["name"] . " is from " . $row["country"] . "
"; This is the example we are using a lot in this part of the tutorial, but in this case, we have misspelled the name column to provoke an error, which we get: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in test.php on line 7 As you can see, the error is not thrown until we try using the resource returned by the mysql_query() function, which we do when we call the mysql_fetch_array() function, in my file located on line 7. The error is very generic and not very helpful. This is on purpose, because knowledge about your database structure makes your website more vulnerable to SQL injection attacks, a problem we will discuss later on. You might be able to spot the error and fix it in a lot of situations, but if not, you can use the mysql_error() function to get a bit more information abut the problem. This function simply returns any error returned from the last executed MySQL function. You should only use this function for finding and fixing problems, and then remove it again once the problem has been fixed. Here's the above example, but where we call the mysql_error() function to get more information: $query = mysql_query("SELECT id, namme FROM test_users"); while($row = mysql_fetch_array($query)) echo $row['id'] . " - " . $row["name"] . " is from " . $row["country"] . "
"; echo mysql_error(); This will give you a far more useful error message: Unknown column 'namme' in 'field list' Try