Error 1235 Trigger Mysql
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Mysql Trigger Error Handling
reports error when inserting up vote 0 down vote favorite 1 I've created a trigger on a table to insert values into one of the columns in the same table after a row is inserted. What gets inserted into the column depends on a set of validations as you can see from the below code. CREATE TRIGGER `FMY_NUM` AFTER INSERT ON `table_1` FOR EACH mysql trigger error log ROW BEGIN DECLARE LC_VAR INTEGER; CASE WHEN table_1. txt_avl>= 7 THEN SET LC_VAR = 5; WHEN table_1.txt_avl > 9 AND table_1.txt_avl < 5000 THEN SET LC_VAR = 3; WHEN table_1.txt_avl > 11 AND table_1.txt_avl < 3000 THEN SET LC_VAR = 2; ELSE SET LC_VAR = 1; END CASE; UPDATE table_1 set table_1.v1order = LC_VAR WHERE v1Pkey = NEW.v1Pkey; END The problem I have is, when I run an insert into table statement, I get the error, MySQL said: Documentation #1109 - Unknown table 'table_1' in field list I've never worked on triggers in MySQL before. Trying to get my head around this. Could someone please help me here? mysql share|improve this question edited May 23 '15 at 11:23 Luke Woodward 32.7k85374 asked May 23 '15 at 10:26 User12345 12110 add a comment| 2 Answers 2 active oldest votes up vote 3 down vote accepted There are a number of things wrong with your trigger. Firstly, the error about Unknown table 'table_1' in field list refers to your use of table_1.txt_avl in the WHEN clauses of your CASE statement. It seems you want to access the value of txt_avl in t
trying to restore a database was error 1235: ERROR 1235 (42000) at line 1408: This version mysql error code 1241 of MySQL doesn't yet support ‘multiple triggers with the same action time
This Version Of Mysql Doesn't Yet Support 'multiple Triggers With The Same Action Time
and event for one table' I scoured Google for about an hour, and came to the conclusion that
Error Code: 1235. This Version Of Mysql Doesn't Yet Support 'limit & In/all/any/some Subquery'
there is multiple reasons this error may appear. I explain these reasons and provide solutions for them below. First of all, I suggest you get a list of all http://stackoverflow.com/questions/30411576/mysql-trigger-reports-error-when-inserting triggers by running the following command: SELECT trigger_schema, trigger_name FROM information_schema.triggers WHERE trigger_schema = 'NAME_OF_YOUR_DATABASE'; Reason #1: You can't combine both BEFORE/AFTER with INSERT/UPDATE/DELETE This PDF describes this issue. The problem is simple: You can't have BEFORE_INSERT and AFTER_INSERT for the same table. You may have been updating a column BEFORE insert and updating some other table AFTER http://www.lemiffe.com/5-solutions-for-mysql-error-1235/ insert with the ID. I suggest you move some of this logic (maybe the BEFORE trigger) to your code. Reason #2: AFTER_DELETE sometimes fails with error 1235 You should avoid using AFTER_DELETE triggers. Move the logic to a BEFORE_DELETE trigger if you are going to use the OLD variable. No idea why this happens, maybe it is my specific MySQL version. Reason #3: You can't have triggers with the same name (duplicate triggers) Sometimes you get another error code when doing this, but other times you get the same error 1235 with no explanation. Run the "show triggers" query I stated above and look for any triggers with the same name. Always run DROP TRIGGER before creating/modifying a trigger. Reason #4: You can't reference the SAME TABLE you are updating/inserting to in a trigger For example, if you wanted to set the default password for a user through a trigger upon creating a new user record, you might have tried to do this: UPDATE users SET password = ‘newPassword'; The correct way to do this is
Community Podcasts MySQL.com Downloads Documentation Section Menu: MySQL Forums :: Triggers :: ERROR 1235 (42000) while executing a trigger New Topic Advanced Search ERROR 1235 (42000) http://forums.mysql.com/read.php?99,404596,404596 while executing a trigger Posted by: Omindu Dishan Rathnaweera () Date: January https://forums.phpfreaks.com/topic/146758-solved-help-with-a-trigger/ 25, 2011 12:23PM Hi! I've tried a trigger something similar to below mention CREATE TRIGGER t3 AFTER INSERT ON tbl1 FOR EACH ROW BEGIN DECLARE val INTEGER; SELECT COUNT(id) INTO val FROM tbl2 t2 WHERE t2.id = NEW.id IF val = 0 THEN UPDATE tbl3 t3 SET mysql error t3.status = 1 WHERE t3.id = NEW.id; ELSE UPDATE tbl3 t3 SET t3.status = 0 WHERE t3.id = NEW.id; END IF; END// after executing I got the error message: ERROR 1235 (42000): This version of MySQL doesn't yet support 'multiple triggers with the same action time and event for one table' I'm currently using mysql 5.1.34-community. Will updating the mysql mysql trigger error version help ? Thank you :) Navigate:Previous Message•Next Message Options:Reply•Quote Subject Views Written By Posted ERROR 1235 (42000) while executing a trigger 6970 Omindu Dishan Rathnaweera 01/25/2011 12:23PM Re: ERROR 1235 (42000) while executing a trigger 3032 Peter Brawley 01/25/2011 03:47PM Re: ERROR 1235 (42000) while executing a trigger 1901 Omindu Dishan Rathnaweera 01/25/2011 04:41PM Sorry, you can't reply to this topic. It has been closed. powered by phorum Content reproduced on this site is the property of the respective copyright holders. It is not reviewed in advance by Oracle and does not necessarily represent the opinion of Oracle or any other party. Contact Sales USA: +1-866-221-0634 Canada: +1-866-221-0634 Germany: +49 89 143 01280 France: +33 1 57 60 83 57 Italy: +39 02 249 59 120 UK: +44 207 553 8447 Japan: 0120-065556 China: 10800-811-0823 India: 0008001005870 More Countries» Contact Us Online» Products MySQL Enterprise Edition MySQL Standard Edition MySQL Classic Edition MySQL Cluster CGE MySQL Embedded (OEM/ISV) Services Training Certification Consulting Support Downloads MySQL Community Server MySQL Cluster MySQL Fabric MySQL Utilities MySQL Workbe
Detected You currently have javascript disabled. Several functions may not work. Please re-enable javascript to access full functionality. [SOLVED] help with a trigger Started by Darkmatter5, Feb 24 2009 09:04 PM Please log in to reply 10 replies to this topic #1 Darkmatter5 Darkmatter5 Advanced Member Members 422 posts Posted 24 February 2009 - 09:04 PM I have 2 tableslvl2prodlevelproduction0215plotsplot_idlevelprodvalue102215Now I'm wanting to create a trigger for the prodvalue in plots. I want it to get the production value from lvl2prod and update that value into prodvalue when level in plots is updated.Can you have it pull data from another table to use as what to update a field to? Back to top #2 Darkmatter5 Darkmatter5 Advanced Member Members 422 posts Posted 24 February 2009 - 09:52 PM I've got this so far, but it's not working. CREATE TRIGGER calc_prodvalue AFTER UPDATE ON plots FOR EACH ROW BEGIN DECLARE pv INTEGER; SELECT l.production INTO pv FROM lvls2prod l, plots p WHERE p.level=l.level; SET p.prodvalue=pv; END; I get this error, "#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 5 ". Back to top #3 fenway fenway MySQL Si-Fu / PHP Resident Alien Staff Alumni 16,199 posts LocationToronto, ON Posted 25 February 2009 - 07:02 AM Where did you reset the delimeter? Seriously... if people don't start reading this before posting, I'm going to consider not answering at all. Back to top #4 Darkmatter5 Darkmatter5 Advanced Member Members 422 posts Posted 25 February 2009 - 02:09 PM I uhh, I guess I didn't I'm just trying to figure this out from a tutorial online. I copied their code and modified it to suit my needs. Back to top #5 Darkmatter5 Darkmatter5 Advanced Member Members 422 posts Posted 25 February 2009 - 03:12 PM Okay I've come up with this DELIMITER | CREATE TRIGGER calc_prodvalue AFTER