Mysql Error Report Php
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Mysql_query Error
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Mysql Show Last Error
Discuss the workings and policies of this site About Us Learn more or die mysql_error about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack mysql get error message in stored procedure Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, http://www.w3schools.com/Php/func_error_reporting.asp helping each other. Join them; it only takes a minute: Sign up how to display MySql error in php up vote 14 down vote favorite In PHP, I am trying to execute a long MySql query that depends on the user input. However, my query fails with the following message, "Query Failed". Actually I have printed this message http://stackoverflow.com/questions/12227626/how-to-display-mysql-error-in-php whenever the query fails but I am having hard time looking for the reason behind this failure. Unfortunately, I couldn't find it because the error is not specified on the web page. My question is, is there any way to display the error message that caused the failure on the web page. Thank you. Here's my code, $from= "Findings"; $where=""; if($service!= null) { $from = $from . ", ServiceType_Lookup"; $where= "Findings.ServiceType_ID= ServiceType_Lookup.ServiceType_ID AND ServiceType_Name= ". $service; if($keyword!= null) $where= $where . " AND "; } if( $keyword != null) { $where= $where . "Finding_ID LIKE '%$keyword%' OR ServiceType_ID LIKE '%$keyword%' OR Title LIKE '%$keyword%' OR RootCause_ID LIKE '%$keyword%' OR RiskRating_ID LIKE '%$keyword%' OR Impact_ID LIKE '%$keyword%' OR Efforts_ID LIKE '%$keyword%' OR Likelihood_ID LIKE '%$keyword%' OR Finding LIKE '%$keyword%' OR Implication LIKE '%$keyword%' OR Recommendation LIKE '%$keyword%' OR Report_ID LIKE '%$keyword%'"; } $query = "SELECT Finding_ID, ServiceType_ID, Title, RootCause_ID, RiskRating_ID, Impact_ID, Efforts_ID, Likelihood_ID, Finding, Implication, Recommendation, Report_ID FROM ".$from . " WHERE " . $where; echo "wala 2eshiq"; $this->result = $this->db_link->query($query);
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow http://stackoverflow.com/questions/6090500/how-to-get-a-detailed-error-report-when-a-php-mysql-script-fails the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 http://stackoverflow.com/questions/21645499/php-connection-to-mysql-error-reporting million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up how to get a detailed error report when a php-mysql script fails? up vote 1 down vote favorite How mysql error do i get a detailed error description during a php-mysql script run? I have the following statements where the script fails and displays the custom error message - the contents of the "or die". I want to get the actual error from MySQL (instead of the custom error i have mentioned), which would give better idea about the scenario - whether its a database issue or server connectivity issue etc.. this is or die mysql the code i have where i need to enhance the error reporting $query = "SELECT * FROM table_name"; $result = mysqli_query($db_conn, $query) or die('Connected to database, but querying failed'); thanks! php mysql report die share|improve this question edited May 23 '11 at 8:17 chiborg 11.8k54974 asked May 22 '11 at 20:14 arun nair 1,131102544 add a comment| 4 Answers 4 active oldest votes up vote 1 down vote accepted Have a look at the manual page for mysqli_error. In the section "Procedural style" you'll find a complete example that shows how to set up the database connection and querying the database, both steps with error handling. If you want detailed error information from your scripts you can put the lines error_reporting( E_ALL ); ini_set('log_errors', true); ini_set('error_log', '/tmp/php-errors.log'); at the start of your code. That way all errors coming from PHP will be written into the log file. Make sure that the path to the log file exists (/tmp is only an example) and is writable by the web server, otherwise the errors will be silently discarded. As a side note: While the "or die()" pattern is good for small examples, you should not use it in production code. share|improve this answer answered May 23 '11 at 8:22 chiborg 11.8k54974 thanks for the direction, @chibo
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up PHP connection to MySql error reporting up vote -1 down vote favorite This seems to be very simple but I am having trouble with this php error reporting. I am trying to connect to a DB and if the connection fails I want to report a simple message e.g "Connection to db failed". But using the code below I get those php warning messages. How can I display only the user friendly message? Thanks guys function mySqlConnection($host, $username, $pass, $dbname){ $connection = mysqli_connect($host, $username, $pass, $dbname) or die ('Connection to db failed'); } php mysqli share|improve this question asked Feb 8 '14 at 11:34 user2257461 217 paste the whole code –CS GO Feb 8 '14 at 11:38 add a comment| 3 Answers 3 active oldest votes up vote 0 down vote accepted You can prefix the function with an @ to suppress the warnings. function mySqlConnection($host, $username, $pass, $dbname){ $connection = @mysqli_connect($host, $username, $pass, $dbname) or die ('Connection to db failed'); } You can also use ini_set('display_errors','0'); which will suppress all warnings and errors though, this is probably not what you want. (It can get annoying later when debugging) In production you should disable the error display though and log them to a file. share|improve this answer answered Feb 8 '14 at 11:47 omnidan 2551212 This answer contradicts with itself –Your Common Sense Feb 8 '14 at 11:49 but it works... the @ at the begin of the mysqli_connect does remove the warning messages. –user2257461 Feb 8 '14 at 11:50 it doesn't. you don't need to gag error message while debugging, yet you will turn off displaying errors on production anyway. –Your Common Sense Feb 8 '14 at 11:51 @YourCommonSense There's a difference between production and debug mod