Mysqli Error Checking
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Mysqli_error() Expects Exactly 1 Parameter
ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million http://php.net/manual/en/mysqli.error.php programmers, just like you, helping each other. Join them; it only takes a minute: Sign up How to display errors for my mysqli query [duplicate] up vote 18 down vote favorite 8 This question already has an answer here: How to get mysqli error in different environments? 1 answer I am using the following script http://stackoverflow.com/questions/17053466/how-to-display-errors-for-my-mysqli-query to process a form that I add info to my website with, the problem I am having it when I press submit nothing gets submitted to the database, also there are no errors. How can I add error reporting to my query ?. php mysql insert mysqli share|improve
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us http://stackoverflow.com/questions/2552545/mysqli-prepared-statements-error-reporting Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up MySQLi prepared statements error reporting up vote 41 down mysql error vote favorite 28 I'm trying to get my head around MySQli and I'm confused by the error reporting. I am using the return value of the MySQLi 'prepare' statement to detect errors when executing SQL, like this: $stmt_test = $mysqliDatabaseConnection->stmt_init(); if($stmt_test->prepare("INSERT INTO testtable VALUES (23,44,56)")) { $stmt_test->execute(); $stmt_test->close(); } else echo("Statement failed: ". $stmt_test->error . "
"); But, is the return value of the prepare statement only detecting mysqli error checking if there is an error in the preperation of the SQL statement and not detecting execution errors? If so should I therefore change my execute line to flag errors as well like this: if($stmt_test->execute()) $errorflag=true; And then just to be safe should I also do the following after the statement has executed: if($stmt_test->errno) {$errorflag=true;} ...Or was I OK to start with and the return value on the MySQLi prepare' statement captures all errors associated with the complete execution of the query it defines? Thanks C php mysql mysqli prepared-statement share|improve this question edited May 5 '12 at 15:24 MPelletier 10.3k106296 asked Mar 31 '10 at 11:43 Columbo 1,19342646 Why do you use prepare/execute() instead of query() in the first place when there is no variable part in your query string? Or is this just an oversimplified example? –VolkerK Mar 31 '10 at 14:20 Yes, sorry. It was simplified to show how I was having difficulty understanding where to get definitive error reporting from a prepared staement. –Columbo Mar 31 '10 at 14:25 add a comment| 3 Answers 3 active oldest votes up vote 82 down vote accepted I wrote this twice before in the last two d