Php Mysql Error Checking
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This help j Next menu item k Previous menu item g p Previous man page g n Next man page G Scroll to bottom g g Scroll to top g h Goto homepage g s Goto search(current page) / Focus search box mysqli::$field_count » « mysqli::$error_list PHP Manual Function Reference Database Extensions Vendor Specific Database Extensions MySQL MySQLi mysqli Change language: English Brazilian Portuguese Chinese (Simplified) French German Japanese Korean Romanian Russian Spanish Turkish Other Edit Report a Bug mysqli::$error mysqli_error (PHP 5, PHP 7)mysqli::$error -- mysqli_error — Returns a string description of the last error Description Object oriented style string $mysqli->error; Procedural style string mysqli_error ( mysqli $link ) Returns the last error message for the most recent MySQLi function call that can succeed or fail. Parameters link Procedural style only: A link identifier returned by mysqli_connect() or mysqli_init() Return Values A string that describes the error. An empty string if no error occurred. Examples Example #1 $mysqli->error example Object oriented style $mysqli=new here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company i cannot select mysql database Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a http://php.net/manual/en/mysqli.error.php minute: Sign up How to check if a MySQL query using the legacy API was successful? up vote 30 down vote favorite 5 How do I check if a MySQL query is successful other than using die() I'm trying to achieve... mysql_query($query); if(success){ //move file } else if(fail){ //display error } php mysql share|improve this question edited Jun 13 at 8:52 Álvaro http://stackoverflow.com/questions/11918797/how-to-check-if-a-mysql-query-using-the-legacy-api-was-successful González 81.2k20133201 asked Aug 12 '12 at 0:27 JohnSmith 3872921 add a comment| 6 Answers 6 active oldest votes up vote 50 down vote accepted This is the first example in the manual page for mysql_query: $result = mysql_query('SELECT * WHERE 1=1'); if (!$result) { die('Invalid query: ' . mysql_error()); } If you wish to use something other than die, then I'd suggest trigger_error. share|improve this answer edited Aug 12 '12 at 1:01 answered Aug 12 '12 at 0:29 Mark Byers 449k8810961194 3 Or simply if (!mysql_query('SELECT * WHERE 1=1')) { ... } –Rune Aug 12 '12 at 0:32 1 @Rune: Right, but then you won't be able to use the query resource for further actions (i.e. for fetching actual data using mysql_fetch_* functions). –Amal Murali May 21 '14 at 13:36 @AmalMurali hmm, good point. I'm not sure where I was with my head at the time of posting that comment.. –Rune May 22 '14 at 19:44 1 Use $result === false not !$result. REASON: There may be queries for which $result is a VALID (non-error) value tha here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss http://stackoverflow.com/questions/12227626/how-to-display-mysql-error-in-php the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each mysql error other. Join them; it only takes a minute: Sign up how to display MySql error in php up vote 14 down vote favorite In PHP, I am trying to execute a long MySql query that depends on the user input. However, my query fails with the following message, "Query Failed". Actually I have printed this message whenever the php mysql error query fails but I am having hard time looking for the reason behind this failure. Unfortunately, I couldn't find it because the error is not specified on the web page. My question is, is there any way to display the error message that caused the failure on the web page. Thank you. Here's my code, $from= "Findings"; $where=""; if($service!= null) { $from = $from . ", ServiceType_Lookup"; $where= "Findings.ServiceType_ID= ServiceType_Lookup.ServiceType_ID AND ServiceType_Name= ". $service; if($keyword!= null) $where= $where . " AND "; } if( $keyword != null) { $where= $where . "Finding_ID LIKE '%$keyword%' OR ServiceType_ID LIKE '%$keyword%' OR Title LIKE '%$keyword%' OR RootCause_ID LIKE '%$keyword%' OR RiskRating_ID LIKE '%$keyword%' OR Impact_ID LIKE '%$keyword%' OR Efforts_ID LIKE '%$keyword%' OR Likelihood_ID LIKE '%$keyword%' OR Finding LIKE '%$keyword%' OR Implication LIKE '%$keyword%' OR Recommendation LIKE '%$keyword%' OR Report_ID LIKE '%$keyword%'"; } $query = "SELECT Finding_ID, ServiceType_ID, Title, RootCause_ID, RiskRating_ID, Impact_ID, Efforts_ID, Likelihood_ID, Finding, Implication, Recommendation, Report_ID FROM ".$from . " WHERE " . $where; echo "wala 2eshiq"; $this->result = $this->db_link->query($query); if (!$this->result) { prMysql_query Error
Die(mysql_error())