Php Return Mysql Error
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Login Cancel Not a member? Sign Up Forgot Password? Contact Us Error message displaying after execution of a query We can display error message http://www.plus2net.com/sql_tutorial/mysql_error.php in case of an error generated by mysql query. This meaning full error message gives idea one the problem or bugs in the script. We can print the error message by using mysql http://dba.stackexchange.com/questions/72115/mysql-php-returning-blank-error-message function mysql_error(). This function returns the error message associated with most recently executed query. So it is a good idea to check for error before going to next query. We can even mysql error add the error number returned by mysql to this error message. This way we can generate a meaningful detail on the bugs on the script. MySQL Error MySQL Error No Error Message Error Mail $querry = mysql_query("SELECT new_field FROM student"); echo "Error message = ".mysql_error(); In our student table there is no field as new_field. Here here is the message we will get Error message php return mysql = Unknown column 'new_field' in 'field list' Note that mysql_error() is deprecated as of PHP 5.5.0 so better to avoid using this function. So if you are using PDO then we can use errorInfo() to display the returned error message from MySQL Here is a sample code in PHP using PDO to display record and on failure to display error message. require 'config-pdo.php'; // database connection string $pdo=$dbo->prepare('Select no_name from student'); if($pdo->execute()){ echo 'Success
'; $row = $pdo->fetch(PDO::FETCH_OBJ); echo "Name : $row->name "; }else{ print_r($pdo->errorInfo()); } In the above code there is an error in sql , there is no column by name no_name. The output will be Array ( [0] => 42S22 [1] => 1054 [2] => Unknown column 'no_name' in 'field list' ) So to get correct result change the sql part like this . $pdo=$dbo->prepare('Select * from student'); With this you will get desired output. Handling PDO errors If such error occurs what is to be done ? We have three options to handle in case of errors. We can stop the execution of the script. ( Fatal error : stop execution of code ) We can display warning message ( Warni
log in tour help Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Database Administrators Questions Tags Users Badges Unanswered Ask Question _ Database Administrators Stack Exchange is a question and answer site for database professionals who wish to improve their database skills and learn from others in the community. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top MySQL/PHP Returning Blank Error Message [closed] up vote 1 down vote favorite I am using the following code to delete a record. It works fine, but MySQL always returns a blank error message. PHP returns "Error: " instead of "1 Record Dropped". $eventid = intval(mysqli_real_escape_string($dbconnect, $_POST['eventid'])); mysqli_query($dbconnect,"DELETE FROM Events WHERE EventID='$eventid' LIMIT 1"); if (!mysqli_query($dbconnect,$sql)) { die('Error: ' . mysqli_error($dbconnect)); } echo "1 Record Dropped"; When I use the same PHP code and change the SQL to a SELECT or INSERT INTO command instead of a DELETE command, I receive the correct response from PHP. mysql php share|improve this question asked Jul 23 '14 at 5:29 Justin 285 closed as off-topic by ypercubeᵀᴹ, Paul White♦, Max Vernon, Mark Storey-Smith, RolandoMySQLDBA Jul 25 '14 at 15:21 This question appears to be off-topic. The users who voted to close gave this specific reason:"Too localized - this could be because your code has a typo, basic error, or is not relevant to most of our audience. Consider revising your question so that it appeals to a broader audience. As it stands, the question is unlikely to help other users (regarding typo questions, see this meta question for background)." – Paul White, Max Vernon, Mark Storey-SmithIf this question can be reworded to fit the rules in the help center, please edit the question. 1 There is something wrong on that code: you are querying mysql twice, only check for errors once, and you do not show the actual query text of the second one ($sql). You can also print the number of records dropped with mysqli_affected_rows(). –jynus Jul 23 '14 at 8:34 add a commen