Php Sql Insert Error
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or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a http://php.net/manual/en/function.mysql-error.php community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up PHP SQL Insert Error up vote 1 down vote favorite I have an error when inserting into the database. Code: dbquery("INSERT INTO site_news_comments (articleid,title,short,comment,timestamp,userid,main,type,topstory) VALUES ($article,'".clean($commentss['title'])."','','".mysql_real_escape_string($_POST['comment'])."',current_timestamp,'".USER_ID."','0','".$commentss['type']."','')"); Ignore the dbquery, works exactly as mysql_query. http://stackoverflow.com/questions/12719831/php-sql-insert-error The error I am receiving is: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''title','short',' No idea why this error is being thrown! php sql database share|improve this question edited Oct 4 '12 at 3:19 Ja͢ck 122k19157203 asked Oct 4 '12 at 3:18 zuc0001 4231618 why dont u put all the data into variable first. much more easier to INSERT later. e.g: $title = clean($commentss['title']) –s3polz Oct 4 '12 at 3:21 can you print just the query and see how it is built before executing –Deepak Oct 4 '12 at 3:23 add a comment| 4 Answers 4 active oldest votes up vote 2 down vote accepted Teaching a man how to fish. If a query fails, the first thing you should do is to echo the query you're about to send: $sql = "INSERT INTO site_news_comments (articleid,title,shor
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of http://stackoverflow.com/questions/15588986/php-insert-into-mysql-syntax-error this site About Us Learn more about Stack Overflow the company Business http://stackoverflow.com/questions/16782740/success-error-message-for-insert-into-mysql-database Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign mysql error up PHP Insert into MySQL syntax error [closed] up vote -1 down vote favorite I'm having trouble submitting some data to MySQL via php, i get the following error: "Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''student' (UID, FirstName, LastName, DOB, EmergencyContact, Address, City, php sql insert State' at line 1" I'm not sure where i've gone wrong, any help would be great. query($sql) === TRUE) { echo 'users entry saved successfully'; } else { echo 'Error: '. $con->error; } mysqli_close($con); ?> If you need more info i'd be happy to provide it, thanks again for the help. php mysql sql phpmyadmin share|improve this question edited Apr 23 '13 at 18:50 Chris Laplante 21.4k1167112 asked Mar 23 '13 at 16:12 Staleyr 90249 closed as too localized by Chris Laplante, andrewsi, Mario Sannum, syb0rg, nickhar Apr
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up success/error message for insert into mysql database up vote 1 down vote favorite 1 when the info is successfully inserted, it's displaying the error message and saying that it's a duplicate entry for a primary key...I can't figure out why! $email=$_POST['email']; $pw=$_POST['pw']; mysql_connect('***','***','***'); @mysql_select_db('***') or die('Unable to select database'); $query = "INSERT INTO test_table VALUES ('','$email','$pw')"; mysql_query($query) or die(mysql_error()); if(mysql_query($query)) { echo 'success'; } else { echo 'failure' .mysql_error(); } mysql_close(); ?> php mysql share|improve this question asked May 28 '13 at 1:54 Dan w 761112 3 Please, don't use mysql_* functions in new code. They are no longer maintained and are officially deprecated. See the red box? Learn about prepared statements instead, and use pdo or mysqli. –hjpotter92 May 28 '13 at 1:55 add a comment| 3 Answers 3 active oldest votes up vote 6 down vote You are executing the query twice: first, in mysql_query($query) or die(mysql_error()); and second, in if(mysql_query($query)). So the second time the query executes the record is already there and thus the insertion fails. share|improve this answer edited May 28 '13 at 2:05 Shankar Damodaran 52.1k115395 answered May 28 '13 at 1:58 heap underrun 32119 this makes sense...what is the best way to fix it? –Dan w May 28 '13 at 2:10 Just does not called twice. –Ricardo Dec 7 '13 at 13:52 add a comment| up vote 2 down vote You are executing same query twice. $query_result = mysql_query($query) or die(mysql_error()); if ($query_result) { echo 'success'; } else { echo 'failure' . mysql_error(); } Write this way, hope it will work. share|improve this answer answered May 28 '13 at 1:59 Tahmina Khatoon 544422 add a comment| up vote 1 down vote Just delete this code from your php script and it will be fine. if(mysql_query($query)) { echo 'success'; } else { echo 'failure' .mysql_error(); } You make it running error twice in a time. You can also use m