Print Out Mysql Error Php
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Php Mysql Error Handling
more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x or die mysql error Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up how mysql_query error to display MySql error in php up vote 14 down vote favorite In PHP, I am trying to execute a long MySql query that depends on the user input. However, my query fails with the following message, "Query Failed". Actually I have printed this message whenever the query fails but I am having hard time looking for the reason behind this failure. Unfortunately, I
Die(mysql_error())
couldn't find it because the error is not specified on the web page. My question is, is there any way to display the error message that caused the failure on the web page. Thank you. Here's my code, $from= "Findings"; $where=""; if($service!= null) { $from = $from . ", ServiceType_Lookup"; $where= "Findings.ServiceType_ID= ServiceType_Lookup.ServiceType_ID AND ServiceType_Name= ". $service; if($keyword!= null) $where= $where . " AND "; } if( $keyword != null) { $where= $where . "Finding_ID LIKE '%$keyword%' OR ServiceType_ID LIKE '%$keyword%' OR Title LIKE '%$keyword%' OR RootCause_ID LIKE '%$keyword%' OR RiskRating_ID LIKE '%$keyword%' OR Impact_ID LIKE '%$keyword%' OR Efforts_ID LIKE '%$keyword%' OR Likelihood_ID LIKE '%$keyword%' OR Finding LIKE '%$keyword%' OR Implication LIKE '%$keyword%' OR Recommendation LIKE '%$keyword%' OR Report_ID LIKE '%$keyword%'"; } $query = "SELECT Finding_ID, ServiceType_ID, Title, RootCause_ID, RiskRating_ID, Impact_ID, Efforts_ID, Likelihood_ID, Finding, Implication, Recommendation, Report_ID FROM ".$from . " WHERE " . $where; echo "wala 2eshiq"; $this->result = $this->db_link->query($query); if (!$this->result) { printf("Query failed: %s\n", mysqli_connect_error()); exit; } $r = mysqli_query($this->db_link, $query); if($r==false) printf("error: %s\n", mysqli_errno($this->db_link)); php mysql share|improve this question asked Sep 1 '12 at 12:16 Traveling Salesman 56131640 You can just use: $this->db_link->error
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Mysql Get Error Message In Stored Procedure
x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up http://stackoverflow.com/questions/12227626/how-to-display-mysql-error-in-php Display error message PHP Mysql up vote 1 down vote favorite 2 i am unable to get the last 2 echos to work, even if the update query fails it still displays success. If anyone has any suggestions on this code to be improved on any line, please do! http://stackoverflow.com/questions/13909391/display-error-message-php-mysql username ='$username'") //check it or die(mysql_error()); $fetched = mysql_fetch_array($idfetch); $id = $fetched['id']; //get users id for checking $answer = $_POST['answer']; $password = (mysql_real_escape_string($_POST['password'])); $confpass = (mysql_real_escape_string($_POST['confpass'])); if ($password != $confpass) { echo ("Passwords do not match, please try again."); exit; } $updatequery = mysql_query("UPDATE users SET PASSWORD='$password' WHERE id='$id' AND username='$username' AND answer='$answer'"); if($updatequery) { echo "
Success
"; echo "Your account password was successfully changed. Please click here to login.
"; } else { echo "Error
"; echo "Sorry, but a field was incorrect.
"; } } ?> Thanks in advance! php mysql share|improve this question edited Dec 17 '12 at 6:42 Sterling Archer 13.5k104173 asked Dec 17 '12 at 6:34 sparkones 26118 Please don't use mysql_query in new applications. It's terribly dangerous if not used perfectly which is an enormous nuisance to do, though I've seen you're at least trying here. You escaped two out of three variables and introduced a gigantic injection hole, though. Close enough is not good enough on the public internet. At the very least you should be using PDO unless you have a very good reason because when using SQL placeholders thesehere for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site http://stackoverflow.com/questions/10930415/mysql-query-shows-die-error-in-php About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join http://www.dummies.com/programming/databases/how-to-handle-mysql-errors/ the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up MySQL query shows die mysql error error in PHP up vote 1 down vote favorite The following is my test.php page which gets redirected from registration.php page. everything over here works very fine except sql query. All the alert tags show session variable values perfectly well, but this page gives 'Error, insert query failed' error. Tried all possibilities like quotes to variables in query, etc., But nothing is working.. Please someone print out mysql help.. "; echo "scriptalert('$comp')"; echo "scriptalert('$yr')"; echo "scriptalert('$no')"; echo "scriptalert('$addr')"; if($ser=='designing'){ $ser=1; }else if($ser=='webdev'){ $ser=2; }else{ $ser=3; } echo "scriptalert('$ser')"; $sql= "insert into login values ('$uname','xxxx',$ser,'$comp',$yr,'$addr','$per',$no,'$email')"; mysql_query($sql) or die('Error, insert query failed'); ?> Your Registration is successful...
Our team will contact you at the earliest... php mysql share|improve this question edited Jun 8 '12 at 15:09 Sanath 1,53152250 asked Jun 7 '12 at 10:56 mano 28126 6 Well, you might want to inspect the output of mysql_error().... Just a thought... –Wrikken Jun 7 '12 at 10:58 Can you show the output of echo $sql; and echo mysql_error();? –Mark Byers Jun 7 '12 at 10:58 3 replace die('Error, ...') with die('Error: '. mysql_error() ) to get specific details about the error. –Aziz Jun 7 '12 at 10:58 mysql_error ? –triclosan Jun 7 '12 at 10:58 I tried all your suggestions now, but echo mysql_error(); echoes nothing at all & with all this my error page shows this way:: insert into login values ('pra','xxxx',1,'xyz.com',2011,'Hyd','xy
WorkSocial MediaSoftwareProgrammingWeb Design & DevelopmentBusinessCareersComputers Online Courses B2B Solutions Shop for Books San Francisco, CA Brr, it´s cold outside Search Submit RELATED ARTICLES How to Handle MySQL Errors Database Development For Dummies Electronic Health Records For Dummies Microsoft SQL Server 2008 For Dummies Crystal Reports 10 For Dummies Load more ProgrammingDatabasesHow to Handle MySQL Errors How to Handle MySQL Errors Related Book PHP, MySQL, JavaScript & HTML5 All-in-One For Dummies By Steve Suehring, Janet Valade You use the mysqli functions of the PHP language, such as mysqli_connect and mysqli_query, to interact with the MySQL database. Things will sometimes go wrong when you use the statements. You may make an error in your typing, such as mistyping a database name. Sometimes, problems arise that you can't avoid, such as the database or the network being down. You need to include code in your script that handles error situations. You usually want to make your error handling more descriptive to assist with troubleshooting problems during development, but you don't want the extra information displayed to the public. For instance, suppose that you're using an account called root to access your database and you make a typo, as in the following statements: $host = "localhost"; $user = "rot"; $password = "; $cxn = mysqli_connect($host,$user,$password) Because you type "rot" rather than "root", you see a warning message similar to this one: Warning: Access denied for user: 'rot@localhost' (Using password: NO) ... The preceding error message contains the information that you need to figure out the problem -- it shows your account name that includes the typo. However, after your script is running and customers are using it, you don't want your users to see a technical error message that shows your user ID. You want to turn the PHP errors off or send them to an error log file. You could then use a die statement to stop the script and display a polite message to the user, as follows: $cxn = mysqli_connect($host,$user,$password) or die("The Catalog is not available at the moment. Please try again later."); When a mysqli_query() function fails, MySQL returns an error message that contains information about the cause of the failure. However, this message isn't displayed unless you specifically display it. Again, you may want to see these messages when you're developing the script, but you may not want to display them to the public. You can display the MySQL error that's returned by using the following function: mysqli_error($cxn) For example, you might include the function in your c