No Such Property Id For Class Play.mvc.results.error
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up how to implements find() or findById() methods for embeddedId in Play framework up vote 2 down vote favorite I have worked with play framework lately for creating project, thanks you so much for my friends in this forum for your assist. Now days i have a problem in play again. I have some model classes that having unique id (not incremental/default id), thereby i extend GenericModel than Model in my Model class. I feel confuse how to use GenericMOdel's find() or findById() methods for EmbeddedId field. This is my snippet codes: Models class 1: @Entity @Table(name="DATKAPJMLPST") public class Datkapjmlpst extends GenericModel { //private static final long serialVersionUID = 1L; @EmbeddedId public DatkapjmlpstPK id; @Column(name="BIAYAKAP") public BigDecimal biayakap; @Column(name="BPJ") public BigDecimal bpj; @Temporal( TemporalType.DATE) @Column(name="DtProses") public Date dtProses; public String flag; @Column(name="JmlPstKom") public BigDecimal jmlPstKom; @Column(name="JmlPstSos") public BigDecimal jmlPstSos; @Column(name="JmlPstTotal") public BigDecimal jmlPstTotal; @Column(name="KdDati2") public String kdDati2; //@Column(name="KdKC") @ManyToOne @JoinColumn(name="KDKC") public Refkc refKC; @Column(name="NOREG") public String noreg; public Datkapjmlpst() { } } Model class 2: @Embeddable public class DatkapjmlpstPK extends GenericModel { //default serial version id, required for serializable classes. //private static
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow http://stackoverflow.com/questions/7525538/how-to-implements-find-or-findbyid-methods-for-embeddedid-in-play-framework Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up No such property: id for http://stackoverflow.com/questions/30709885/no-such-property-id-for-class-java-lang-string class: java.lang.String up vote 1 down vote favorite 1 I am sending the employee object from the Project_level controller to the _add_members view and then from there I am sending the employee object to the Project_permission controller. while saving the id the following error is coming: No such property: id for class: java.lang.String in the line :proj_permission.setId_of_employee(emp.id) class Project_levelController { def auth_after_create_level(){ //creating a level under the above level def res=Project_level.findByLevel_nameAndLevel_no(params.level_name,params.level_no) // def res=null if(res) { flash.message='level name has already been taken' redirect(action:'_right') } else{ if(params.enter=="NEXT") { def proj_lev_right = new Project_level_right(params["project_level_right"]) proj_lev_right.save() proj_lev_right.errors.allErrors.each { println it } session.proj_lev_right = proj_lev_right def proj_lev = new Project_level(params["project_level"]) proj_lev.setProj_lev_right_id("${proj_lev_right.id}") proj_lev.id_of_project=session.id_of_project proj_lev.mem_added = 0 proj_lev.save() proj_lev.errors.allErrors.each { println it } session.proj_lev = proj_lev def emp = Employee.findAllByLevel(proj_lev.level_no) render(view: "add_members", model: [proj_lev:proj_lev , proj_lev_r
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Controllers Testing Controller Logic Areas 🔧 Working with the Application Model Testing Working with Data Client-Side Development Mobile Publishing and Deployment Guidance for Hosting Providers Security Performance Migration API Contribute ASP.NET Docs » MVC » Controllers » Routing to Controller Actions Edit on GitHub Routing to Controller Actions¶ By Ryan Nowak and Rick Anderson ASP.NET Core MVC uses the Routing middleware to match the URLs of incoming requests and map them to actions. Routes are defined in startup code or attributes. Routes describe how URL paths should be matched to actions. Routes are also used to generate URLs (for links) sent out in responses. This document will explain the interactions between MVC and routing, and how typical MVC apps make use of routing features. See Routing for details on advanced routing. Sections: Setting up Routing Middleware Conventional routing Multiple Routes Attribute Routing Token replacement in route templates ([controller], [action], [area]) Mixed Routing URL Generation Areas Understanding IActionConstraint Setting up Routing Middleware¶ In your Configure method you may see code similar to: app.UseMvc(routes => { routes.MapRoute("default", "{controller=Home}/{action=Index}/{id?}"); }); Inside the call to UseMvc, MapRoute is used to create a single route, which we'll refer to as the default route. Most MVC apps will use a route with a template similar to the default route. The route template "{controller=Home}/{action=Index}/{id?}" can match a URL path like /Products/Details/5 and will extract the route values { controller = Products, action = Details, id = 5 } by tokenizing the path. MVC will attempt to locate a controller named ProductsController an