C# Error Code 10022
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Socket Error 10049
them; it only takes a minute: Sign up C# socket error 10022 up vote 1 down vote favorite 1 I have an error 10022 in an application using sockets in C# .NET3.5. In my code, I bind the socket to the local IP adress. When I don"t need it anymore, I just Disconnect it ( reader.socket.Disconnect(true); ) with "true" socket error 10054 connection reset by peer to be able to re-use it. But when I call the "bind" method again, it crashes with the 10022 error (invalid argument). If I set the line with this method as a comment, it then crashes on the line "listen", saying that a connection is already set (although I called disconnect !) Any idea? Thanks Here is the part of code which fail : public void WaitConnexion(IPEndPoint localEP) { if (localEP.Port != 9000) { MessageBox.Show("Le port doit être 9000"); return; } LocalEndPoint = localEP; if (reader.socket.Connected) { MessageBox.Show("Vous êtes déjà connecté", "Conflit de connexion", MessageBoxButton.OK, MessageBoxImage.Exclamation); return; } // on bind le socket avec le endpoint local, et on le met en attente de connexion asynchrone // reader.socket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); reader.socket.Bind(localEP); reader.socket.Listen(1); reader.socket.BeginAccept(new AsyncCallback(WaitConnexionCallBack), reader.socket); } and here is the diconnect method with its callback : public void Disconnect() { if (!reader.socket.Connected) return; reader.socket.BeginDisconnect(true, new AsyncCallback(DisconnectCallBack), reader.socket); } private void DisconnectCallBack(IAsyncResult result) { reader.socket = (result.AsyncState as Socket); reader.socket.EndDisconnect(result); if (Disconnected != null) Disconnected(this, EventArgs.Empty); } c# sockets share|improve this question edited
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this socket error codes linux site About Us Learn more about Stack Overflow the company Business Learn more socket error 10061 connection refused about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss socket error 11001 Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Don't know why http://stackoverflow.com/questions/1707214/c-sharp-socket-error-10022 I'm getting Error Code 10022 (Invalid Argument) when setting socket options in my C# sniffer up vote 3 down vote favorite 2 I'm writing a packet sniffer as an exercise in learning .Net 4 socket development on in C#. My goal is to sniff IP packets coming in and out out my computer. My problem is that I'm getting error code 10022, invalid argument, http://stackoverflow.com/questions/5145923/dont-know-why-im-getting-error-code-10022-invalid-argument-when-setting-sock on my call to SetSocketOption. I don't see where I have an invalid argument. I have some admin privs on my computer, but perhaps I don't have enough. It's my work computer and the IT department is pretty strict. With that said, if it was a permissions problem I would expect a different exception. I'm not sure what my next step should be to debug this problem. Anyone have an idea? Here's the code follows: public Sniffer() { try { socket = new Socket( AddressFamily.InterNetwork, SocketType.Raw, ProtocolType.IP); IPAddress[] ipAddresses = Dns.GetHostEntry( Dns.GetHostName()).AddressList; socket.Bind(new IPEndPoint(ipAddresses[0], 0)); socket.SetSocketOption( SocketOptionLevel.IP, SocketOptionName.HeaderIncluded, true); byte[] inputData = new byte[4] { 1, 0, 0, 0 }; byte[] outValue = new byte[4]; socket.IOControl(IOControlCode.ReceiveAll, inputData, outValue); } catch (SocketException ex) { string ErrorMessage = ex.Message; } } c# sockets packet-sniffers share|improve this question edited Apr 1 at 17:36 Shaun Luttin 20.1k1481138 asked Feb 28 '11 at 18:21 Don 2171516 I don't see IP as one of the arguments in this documentation (?) msdn.microsoft.com/en-us/library/600stss7.aspx –Shoban Feb 28 '11 at 18:27 Are you running win7 or vista? If that's the case you might just need to elevate privile
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