Awk Syntax Error At Or Near If
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Awk If Else Syntax
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Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only awk print if takes a minute: Sign up awk syntax error: awk: line 29: syntax error at or near : up vote 1 down vote favorite I have written a awk script and I keep on getting the following error: awk: line 29: syntax error at or near : I do not understand why I keep on getting this error. The script is below(script awk: line 1: syntax error at or near print is large but the error is only at the top section. Just added the script for completeness. A flag has been marked for the line a error). #!/bin/sh tshark -V -r $1 > .pcap_out1_ver.txt tshark -r $1 > .pcap_out_summ.txt awk -F ":" ' BEGIN { #Packet types and subtypes. frame_id[0] = "Association Request"; frame_id[1] = "Association Response"; frame_id[2] = "Association Response"; frame_id[3] = "Reassociation Response"; frame_id[4] = "Probe Request"; frame_id[5] = "Probe Response"; frame_id[6] = "Reserved"; frame_id[7] = "Reserved"; frame_id[8] = "Beacon"; frame_id[9] = "ATIM"; frame_id[10] = "Disassociation"; frame_id[11] = "Authentication"; frame_id[12] = "Deauthentication"; frame_id[13] = "Action"; for(x=14; x<24; ++x) { frame_id[x] = "Reserved"; } frame_id[24] = "Block Ack Request"; frame_id[25] = "Block Ack"; frame_id[26] = "PS-Poll"; frame_id[27] = "RTS"; #******Error here**** frame_id[28] = "CTS"; frame_id[29] = "ACK"; frame_id[30] = "CF-end"; frame_id[31] = "CF-end + CF-ack"; frame_id[32] = "Data"; frame_id[33] = "Data + CF-ack"; frame_id[34] = "Data + CF-poll"; frame_id[35] = "Data + CF-ack +CF-poll"; frame_id[36] = "Null"; frame_id[37] = "CF-ack"; frame_id[38] = "CF-poll"; frame_id[39] = "CF-ack + CF-poll"; frame_id[40] = "QoS data"; frame_id[41] = "QoS data + CF-ack"; fra
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Awk If Else
near line 1 ERROR User Name Remember Me? Password Linux - Newbie This Linux awk print forum is for members that are new to Linux. Just starting out and have a question? If it is not in the man pages or the how-to's this is the place! Notices Welcome to LinuxQuestions.org, a friendly and active Linux Community. You are currently viewing LQ as a guest. By joining our community you http://stackoverflow.com/questions/14779671/awk-syntax-error-awk-line-29-syntax-error-at-or-near will have the ability to post topics, receive our newsletter, use the advanced search, subscribe to threads and access many other special features. Registration is quick, simple and absolutely free. Join our community today! Note that registered members see fewer ads, and ContentLink is completely disabled once you log in. Are you new to LinuxQuestions.org? Visit the following links: Site Howto | Site FAQ | Sitemap | Register http://www.linuxquestions.org/questions/linux-newbie-8/need-solution-for-awk-syntax-error-near-line-1-error-4175431628/ Now If you have any problems with the registration process or your account login, please contact us. If you need to reset your password, click here. Having a problem logging in? Please visit this page to clear all LQ-related cookies. Introduction to Linux - A Hands on Guide This guide was created as an overview of the Linux Operating System, geared toward new users as an exploration tour and getting started guide, with exercises at the end of each chapter. For more advanced trainees it can be a desktop reference, and a collection of the base knowledge needed to proceed with system and network administration. This book contains many real life examples derived from the author's experience as a Linux system and network administrator, trainer and consultant. They hope these examples will help you to get a better understanding of the Linux system and that you feel encouraged to try out things on your own. Click Here to receive this Complete Guide absolutely free. Search this Thread 10-11-2012, 03:56 AM #1 Vthimmap Member Registered: Oct 2012 Posts: 32 Rep: Need solution for awk: syntax error near line 1 ERROR Using awk in kron shell gives the error awk: syntax erro
awk articles, we discussed about awk print, awk user-defined variables, awk built-in variables, and awk operators. In this http://www.thegeekstuff.com/2010/02/awk-conditional-statements awk tutorial, let us review awk conditional if statements with practical examples. Awk supports lot of conditional statements to control the flow of the program. Most of the Awk conditional statement syntax are looks like ‘C' programming language. Normally conditional statement checks the condition, before performing any action. If the condition is true action(s) are performed. Similarly action can be performed if syntax error the condition is false. Conditional statement starts with the keyword called ‘if'. Awk supports two different kind of if statement. Awk Simple If statement Awk If-Else statement Awk If-ElseIf-Ladder Awk Simple If Statement Single Action: Simple If statement is used to check the conditions, if the condition returns true, it performs its corresponding action(s). Syntax: if (conditional-expression) action if is a keyword conditional-expression syntax error at - expression to check conditions action - any awk statement to perform action. Multiple Action: If the conditional expression returns true, then action will be performed. If more than one action needs to be performed, the actions should be enclosed in curly braces, separating them into a new line or semicolon as shown below. Syntax: if (conditional-expression) { action1; action2; } If the condition is true, all the actions enclosed in braces will be performed in the given order. After all the actions are performed it continues to execute the next statements. Awk If Else Statement In the above simple awk If statement, there is no set of actions in case if the condition is false. In the awk If Else statement you can give the list of action to perform if the condition is false. If the condition returns true action1 will be performed, if the condition is false action 2 will be performed. Syntax: if (conditional-expression) action1 else action2 Awk also has conditional operator i.e ternary operator ( ?: ) whose feature is similar to the awk If Else Statement. If the conditional-expres