Awk Syntax Error In Regular Expression
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Awk Syntax Error Near Unexpected Token ('
Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. awk syntax error at source line 1 Join them; it only takes a minute: Sign up Syntax error in awk script up vote 1 down vote favorite I'm getting a syntax error when running an awk script, the script is: awk -F\" 'for( i = awk syntax error at source line 1 context is 1 ; i <= NF; i++){if ($i == "^[0-9]+$"){ gsub(.,,,$1) }}' A sample of how the actual data may look like is this (enclosed and pipe separated): "data"|"data"|"data"|"data"|"data" What i want to do, as you can see from the code is: read all fields, if a field is numeric (will always be decimal), replace the point with a comma. I have also tried to escape the comma in the gsub function: awk -F\" 'for( i = 1 ;
Syntax Error In Regular Expression Javascript
i <= NF; i++){if ($i == "^[0-9]+$"){ gsub(.,\,,$1) }}' But its not solving the issue, do you have any idea where the problem is? the comparison against a regex it looks fine, the loop and the if statements also, the error message is awk: cmd. line:1: for( i = 1 ; i <= NF; i++){if ($i == "^[0-9]+$"){ gsub(.,,,$1) }} awk: cmd. line:1: ^ syntax error awk: cmd. line:1: for( i = 1 ; i <= NF; i++){if ($i == "^[0-9]+$"){ gsub(.,,,$1) }} awk: cmd. line:1: ^ syntax error awk: cmd. line:1: for( i = 1 ; i <= NF; i++){if ($i == "^[0-9]+$"){ gsub(.,,,$1) }} awk: cmd. line:1: ^ syntax error awk: cmd. line:1: for( i = 1 ; i <= NF; i++){if ($i == "^[0-9]+$"){ gsub(.,,,$1) }} awk: cmd. line:1: ^ syntax error awk: cmd. line:1: for( i = 1 ; i <= NF; i++){if ($i == "^[0-9]+$"){ gsub(.,,,$1) }} awk: cmd. line:1: ^ syntax error awk: cmd. line:1: for( i = 1 ; i <= NF; i++){if ($i == "^[0-9]+$"){ gsub(.,,,$1) }} awk: cmd. line:1: ^ syntax error awk: cmd. line:1: for( i = 1 ; i <= NF; i++){if ($i == "^[0-9]+$"){ gsub(.,,,$1) }} awk: cmd. line:1: ^ syntax error awk: cmd. line:1: for( i = 1 ; i <= NF; i++){if ($i == "^[0-9]+$"){ gsub(.,,,$1) }} awk: cmd. line:1: ^ 1 is invalid as number of argume
Scripting Unix shell scripting - KSH, CSH, SH, BASH, PERL, PHP, SED, AWK and shell scripts and shell scripting languages here. Search Forums Show Threads Show Posts Tag Search Advanced Search Unanswered Threads Find All Thanked Posts Go to Page... learn awk regular expression replace unix and linux commands Help with awk script (syntax error in regular expression) Shell Programming awk regular expression capture and Scripting Tags awk, regular expression escaping, search and replace Thread Tools Search this Thread Display Modes
Awk Regular Expression Extract Substring
#1 10-18-2012 spacegoose Registered User Join Date: Mar 2010 Last Activity: 7 February 2015, 12:35 AM EST Posts: 12 Thanks: 4 Thanked 1 Time in 1 Post Help with awk script (syntax error in regular expression) I've http://stackoverflow.com/questions/13930310/syntax-error-in-awk-script found this script which seems very promising to solve my issue: To search and replace many different database passwords in many different (.php, .pl, .cgi, etc.) files across my filesystem. The passwords may or may not be contained within quotes, single quotes, etc. Code: #!/bin/bash f="passwords.csv" find /path -type f -name "*.txt" | while read FILE do awk 'BEGIN{ FS="," } FNR==NR{ s[$1]=$2; next } { for(i in s){ if( $0 ~ i ){ gsub(i,s[i]) } } print $0 }' http://www.unix.com/shell-programming-and-scripting/204069-help-awk-script-syntax-error-regular-expression.html $f $FILE > temp mv temp $FILE done My passwords.csv file contains old passwords and new ones, comma delimited. I've altered the find command within this script to find the files I want. The script works if the first column (old password) has no special characters, but since these are passwords, there are lots of special characters. It seems the second column (new password) can contain special characters ... I've tested this by having the find command (within the script) find a specific file, with a password that has no special characters, and using a test passwords.csv with the non-special password (in the first column), and the new password (in the second column) having special characters, and it does the substitution. However, if the reverse is true (and in most cases it is), I receive the error: Quote: awk: syntax error in regular expression !@#$%))*#$%^ at )*#$%^ Is there something I can do to the script that will treat both columns (or matches), as literals? I say matches because I'm actually not sure if it is my passwords.csv file containing the special character password, or the file that contains it, that is breaking this. Whatever it is, I'd like to have this script work. Thanks for any assistance, Bill Remove advertisements Sponsored Links spacegoose View Public Profile Find all posts by spacegoose #2 10-18-2012 rdrtx1 Registered User Join Date: Sep
slashes). It may be any expression. The expression is evaluated and converted to a string if necessary; the contents of the string are then used as the regexp. A regexp computed in this way https://www.gnu.org/s/gawk/manual/html_node/Computed-Regexps.html is called a dynamic regexp or a computed regexp: BEGIN { digits_regexp = "[[:digit:]]+" } $0 ~ digits_regexp { print } This sets digits_regexp to a regexp that describes one or more digits, and tests http://www.thegeekstuff.com/2010/01/awk-introduction-tutorial-7-awk-print-examples whether the input record matches this regexp. NOTE: When using the ‘~’ and ‘!~’ operators, be aware that there is a difference between a regexp constant enclosed in slashes and a string constant enclosed syntax error in double quotes. If you are going to use a string constant, you have to understand that the string is, in essence, scanned twice: the first time when awk reads your program, and the second time when it goes to match the string on the lefthand side of the operator with the pattern on the right. This is true of any string-valued expression (such as digits_regexp, shown in the previous awk syntax error example), not just string constants. What difference does it make if the string is scanned twice? The answer has to do with escape sequences, and particularly with backslashes. To get a backslash into a regular expression inside a string, you have to type two backslashes. For example, /\*/ is a regexp constant for a literal ‘*’. Only one backslash is needed. To do the same thing with a string, you have to type "\\*". The first backslash escapes the second one so that the string actually contains the two characters ‘\’ and ‘*’. Given that you can use both regexp and string constants to describe regular expressions, which should you use? The answer is “regexp constants,” for several reasons: String constants are more complicated to write and more difficult to read. Using regexp constants makes your programs less error-prone. Not understanding the difference between the two kinds of constants is a common source of errors. It is more efficient to use regexp constants. awk can note that you have supplied a regexp and store it internally in a form that makes pattern matching more efficient. When using a string constant, awk must first convert the string into this internal form and then perform the pattern mat
awk in the upcoming weeks that will cover all features of awk with practical examples. In this article, let us review the fundamental awk working methodology along with 7 practical awk print examples. Note: Make sure you review our earlier Sed Tutorial Series. Awk Introduction and Printing Operations Awk is a programming language which allows easy manipulation of structured data and the generation of formatted reports. Awk stands for the names of its authors "Aho, Weinberger, and Kernighan" The Awk is mostly used for pattern scanning and processing. It searches one or more files to see if they contain lines that matches with the specified patterns and then perform associated actions. Some of the key features of Awk are: Awk views a text file as records and fields. Like common programming language, Awk has variables, conditionals and loops Awk has arithmetic and string operators. Awk can generate formatted reports Awk reads from a file or from its standard input, and outputs to its standard output. Awk does not get along with non-text files. Syntax: awk '/search pattern1/ {Actions} /search pattern2/ {Actions}' file In the above awk syntax: search pattern is a regular expression. Actions - statement(s) to be performed. several patterns and actions are possible in Awk. file - Input file. Single quotes around program is to avoid shell not to interpret any of its special characters. Awk Working Methodology Awk reads the input files one line at a time. For each line, it matches with given pattern in the given order, if matches performs the corresponding action. If no pattern matches, no action will be performed. In the above syntax, either search pattern or action are optional, But not both. If the search pattern is not given, then Awk performs the given actions for each line of the input. If the action is not given, print all that lines that matches with the given patterns which is the default action. Empty braces with out any action does no