Error Near Syntax Error
Contents |
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss error near syntax error sqlite3 the workings and policies of this site About Us Learn more
Syntax Error At Or Near Perform
about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow syntax error at or near postgres Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each
Syntax Error At Or Near Extension
other. Join them; it only takes a minute: Sign up sqlite near syntax error up vote 0 down vote favorite I am new to sql and trying to create a table that has a foreign key reference to another table. I keep getting a near syntax error and can't figure out why. See sql statements below First table syntax error at or near createuser sqlite> CREATE TABLE nl_central_teams ( ...> id INTEGER PRIMARY KEY AUTOINCREMENT, ...> team_name VARCHAR(64) NOT NULL, ...> city VARCHAR(64) NOT NULL, ...> main_color VARCAR(64) NOT NULL, ...> created_at DATETIME NOT NULL, ...> updated_at DATETIME NOT NULL ...> ); first table works fine. Second table sqlite> CREATE TABLE managers( ...> id INTEGER PRIMARY KEY AUTOINCREMENT, ...> first_name VARCHAR(64) NOT NULL, ...> last_name VARCHAR(64) NOT NULL, ...> team_id INTEGER, ...> FOREIGN KEY(team_id) REFERENCES nl_central_teams(id), ...> created_at DATETIME NOT NULL, ...> updated_at DATETIME NOT NULL ...> ); Error: near "created_at": syntax error I feel like my syntax is correct but can't figure out why I am getting this error. Any help would be appreciated, sql sqlite share|improve this question edited Sep 4 '14 at 17:14 tadman 108k12137170 asked Sep 4 '14 at 16:56 xeroshogun 18812 Is this MySQL or SQLite? –tadman Sep 4 '14 at 17:13 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted Foreign key constraints should be at the end of the CREATE
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company
Syntax Error At Or Near Distinct
Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs
Syntax Error At Or Near Psql
Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just syntax error at or near pgdmp like you, helping each other. Join them; it only takes a minute: Sign up sqlite3: near “.” : syntax error up vote 3 down vote favorite I have two tables already created: create table movies(id integer, name http://stackoverflow.com/questions/25671056/sqlite-near-syntax-error text, score integer); create table cast(movie_id integer, cast_id integer, cast_name text); I need the first 10 (distinct, alphabetically by cast_name) cast members and their average movie scores, so I tried: select movie_id,cast_id,cast_name,id,score from cast,movies where movies.id=cast.movie_id and cast_name in (select distinct cast_name from cast order by cast_name limit 10); But then I got an error message: near "." : syntax error After that, I tried to make it simpler: select cast_name, score from cast,movies http://stackoverflow.com/questions/21356420/sqlite3-near-syntax-error where movies.id=cast.movie_id; I still got the same error. I guess this might be because '.' is a special command in sqlite3, but cannot figure out how to solve this problem. Any help will be appreciated. sql sqlite3 share|improve this question edited Jan 26 '14 at 11:32 Martin Schröder 1,72131734 asked Jan 25 '14 at 21:23 Billy Wang 1814 add a comment| 1 Answer 1 active oldest votes up vote 3 down vote accepted cast is a reserved word. The list of reserved words is here. select cast_name, score from `cast` c join movies m on m.id = c.movie_id; You can escape it using backticks or double quotes. This query uses table aliases to simplify the query and more modern syntax for the join. share|improve this answer answered Jan 25 '14 at 21:28 Gordon Linoff 466k20138212 Thanks a lot. It's working! –Billy Wang Jan 25 '14 at 21:41 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy and terms of service. Not the answer you're looking for? Browse other questions tagged sql sqlite3 or ask your own quest
post in threaded view ♦ ♦ | Report Content as Inappropriate ♦ ♦ Error Message near ".": syntax error I am receiving the following error message when running a query against a http://sqlite.1065341.n5.nabble.com/Error-Message-near-quot-quot-syntax-error-td31579.html sqlite db: Error Message near ".": syntax error What does this mean? and how do I debug it? I'm new to sqlite and don't understand the 'near'. Is it saying that I have syntax https://github.com/couchbase/couchbase-lite-ios/issues/935 error somewhere involving '.'? Thanks _______________________________________________ sqlite-users mailing list [hidden email] http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users Puneet Kishor-2 Reply | Threaded Open this post in threaded view ♦ ♦ | Report Content as Inappropriate ♦ ♦ Re: syntax error Error Message near ".": syntax error On Oct 8, 2011, at 8:28 PM, James Brison wrote: > I am receiving the following error message when running a query against a sqlite db: > > Error Message near ".": syntax error > > What does this mean? and how do I debug it? I'm new to sqlite and don't understand the 'near'. Is it saying that I have syntax error syntax error at somewhere involving '.'? > Wouldn't it have been super-easy to actually show us your query? How can anyone divine what is wrong when no knows what your query is. You are likely missing a comma, or have an extra space... please resend with the actual query that causes the above error. -- Puneet Kishor _______________________________________________ sqlite-users mailing list [hidden email] http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users Simon Slavin-3 Reply | Threaded Open this post in threaded view ♦ ♦ | Report Content as Inappropriate ♦ ♦ Re: Error Message near ".": syntax error In reply to this post by James Brison On 9 Oct 2011, at 2:28am, James Brison wrote: > I am receiving the following error message when running a query against a sqlite db: > > Error Message near ".": syntax error > > What does this mean? and how do I debug it? I'm new to sqlite and don't understand the 'near'. Is it saying that I have syntax error somewhere involving '.'? In your SQL command you have a '.'. Either that dot, or very soon after it, is a character that SQLite doesn't know what to do with. If you can't figure it out, post the command and we'll tell you. Simon. _____
Sign in Pricing Blog Support Search GitHub This repository Watch 94 Star 1,114 Fork 217 couchbase/couchbase-lite-ios Code Issues 105 Pull requests 3 Projects 0 Wiki Pulse Graphs New issue Syntax error attempting to encrypt using SQLCipher #935 Closed brendand opened this Issue Oct 3, 2015 · 3 comments Projects None yet Labels None yet Milestone No milestone Assignees No one assigned 2 participants brendand commented Oct 3, 2015 Hi, I've built SQLCipher as a dynamic library and removed the standard SQLite library reference from the CBL Mac target and put libsqlcipher.dylib in its place. I also added the requisite SQLCipher flags to the Other Objective C Flags build setting: -DSQLITE_ENABLE_FTS3=1 -DSQLITE_ENABLE_FTS3_PARENTHESIS -DSQLITE_ENABLE_FTS4_UNICODE61 -DSQLITE_HAS_CODEC I'm not convinced the SQLCipher library is being used though because when my app starts up, CBL outputs the following debug statement: Couchbase Lite using SQLite version 3.8.10.2 (2015-05-20 18:17:19 2ef4f3a5b1d1d0c4338f8243d40a2452cc1f7fe4) I built SQLCipher just now so the date should be today's date I would think. Unless I'm mistaken what the above log output is telling me. The version number is correct though. When I attempt to encrypt, I get the following log output: