Eval Syntax Error Ie
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Javascript Eval Syntax Error
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Syntax Error At Eval 1 Line 1 Near
eval() “syntax error” on parsing a function string up vote 11 down vote favorite 2 I have a bit of JavaScript code that is specified in a configuration file on the server-side. Since I can't specify a JavaScript function in the configuration language (Lua), I have it as a string. The server returns the string in some JSON and I have the client interpret script1002 syntax error ie it using a clean-up function: parse_fields = function(fields) { for (var i = 0; i < fields.length; ++i) { if (fields[i].sortType) { sort_string = fields[i].sortType; fields[i].sortType = eval(sort_string); } return fields; } }; So basically it just evaluates sortType if it exists. The problem is that Firebug is reporting a "Syntax error" on the eval() line. When I run the same steps on the Firebug console, it works with no problems and I can execute the function as I expect. I've tried some different variations: window.eval instead of plain eval, storing the sortType as I've done above, and trying small variations to the string. A sample value of fields[i].sortType is "function(value) { return Math.abs(value); }". Here's the testing I did in Firebug console: >>> sort_string "function(value) { return Math.abs(value); }" >>> eval(sort_string) function() >>> eval(sort_string)(-1) 1 and the error itself in Firebug: syntax error [Break on this error] function(value) { return Math.abs(value); } The last bit that may be relevant is that this is all wrapped in an Ext JS onReady() function, with an Ext.ns namespace change at the top. But I assumed the window.eval would call the glob
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Uncaught Syntaxerror Unexpected Identifier Eval
ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join javascript eval syntax error line number the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a javascript eval function minute: Sign up eval javascript, check for syntax error up vote 22 down vote favorite 4 I wanted to know if it is possible to find through javascript if a call to eval() has a syntax error or undefined variable, etc... http://stackoverflow.com/questions/2760953/javascript-eval-syntax-error-on-parsing-a-function-string so lets say I use eval for some arbitrary javascript is there a way to capture the error output of that eval? javascript eval share|improve this question asked Feb 7 '11 at 15:51 Jesus Ramos 18.1k53971 add a comment| 4 Answers 4 active oldest votes up vote 32 down vote accepted You can test to see if an error is indeed a SyntaxError. try { eval(code); } catch (e) { if (e instanceof SyntaxError) { alert(e.message); } } share|improve this answer answered http://stackoverflow.com/questions/4923316/eval-javascript-check-for-syntax-error Feb 7 '11 at 15:56 ChaosPandion 50.5k884126 I'm wondering why I didn't try this myself. Thanks a lot! –Jesus Ramos Feb 7 '11 at 16:37 2 @Jesus - The fact that you're wondering is a good thing. Anyway, good luck. –ChaosPandion Feb 7 '11 at 18:00 add a comment| up vote 7 down vote When using try catch for catching particular type of error one should ensure that other types of exceptions are not supressed. Otherwise if evaluated code would throw a different kind of exception it could disappear and cause unexpected behavior of code. I would suggest writting code like this: try { eval(code); } catch (e) { if (e instanceof SyntaxError) { alert(e.message); } else { throw( e ); } } Please note the "else" section. share|improve this answer answered Oct 13 '14 at 19:01 RandomX 7111 add a comment| up vote 2 down vote According to the Mozilla documentation for eval: eval returns the value of the last expression evaluated. So I think you may be out of luck. This same document also recommends against using eval: eval() is a dangerous function, which executes the code it's passed with the privileges of the caller. If you run eval() with a string that could be affected by a malicious party, you may end up running malicious code on the user's machine with the permissions of your webpage / extension. More importantly, third party code can see the scope in whi
& Guides Learn the Web Tutorials References Developer Guides Accessibility https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/SyntaxError Game development ...more docs Mozilla Docs Add-ons Firefox WebExtensions https://forum.jquery.com/topic/globaleval-syntax-error-in-ie9-with-temporary-fix Developer ToolsFeedback Get Firefox help Get web development help Join the MDN community Report a content problem Report a bug Search Search Languages Català (ca) Deutsch (de) Español (es) Français (fr) 日本語 (ja) 한국어 (ko) Português (do Brasil) syntax error (pt-BR) Русский (ru) 中文 (简体) (zh-CN) Add a translation Edit Advanced Advanced History Print this article MDN Web technology For developers JavaScript JavaScript reference Standard built-in objects SyntaxError Your Search Results fscholz Mingun arai Sheppy Potappo Sevenspade SyntaxError In This Article DescriptionSyntaxParametersPropertiesMethodsSyntaxError instancesPropertiesMethodsExamplesCatching a SyntaxErrorCreating a SyntaxErrorSpecificationsBrowser compatibilitySee eval syntax error also The SyntaxError object represents an error when trying to interpret syntactically invalid code. Description A SyntaxError is thrown when the JavaScript engine encounters tokens or token order that does not conform to the syntax of the language when parsing code. Syntax new SyntaxError([message[, fileName[, lineNumber]]]) Parameters message Optional. Human-readable description of the error fileName Optional. The name of the file containing the code that caused the exception lineNumber Optional. The line number of the code that caused the exception Properties SyntaxError.prototype Allows the addition of properties to a SyntaxError object. Methods The global SyntaxError contains no methods of its own, however, it does inherit some methods through the prototype chain. SyntaxError instances Properties SyntaxError.prototype.constructor Specifies the function that created an instance's prototype. SyntaxError.prototype.message Error message. Although ECMA-262 specifies that SyntaxError should provide its own message property, in SpiderMonkey, it inherits Error.pr
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