Java Syntax Error On Token Expected
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Syntax Error On Token Expected After This Token In Eclipse
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Eclipse Javascript Syntax Error On Token ":", ( Expected
a minute: Sign up Syntax error on token “;”, , expected Java Programming up vote 0 down vote favorite 1 I have this error while coding in Eclipse for android: Syntax error on token ";", , expected and Multiple markers at this line - Syntax error on token ")", { expected after this token - Return type for the method is
Syntax Error On Token Expected After This Token Android
missing - Syntax error on token ".", ... expected - Syntax error, insert ";" to complete FieldDeclaration And I don't really see why i'm having so much trouble figuring what it is. Eclipse only says where there is an error, not why, and its "Quick fixes" never work. If anyone knows how to fix this plase help me :) package com.example.apptest; import android.app.Activity; import android.os.Bundle; import android.view.Menu; import android.widget.Button; import android.widget.CheckBox; import android.widget.EditText; import android.widget.RadioGroup; import android.widget.TextView; import android.widget.Toast; public class MainActivity extends Activity { private final String defaut = "Vous devez cliquer sur le bouton « Calculer l'IMC » pour obtenir un résultat."; private final String megaString = "Vous faites un poids parfait ! Wahou ! Trop fort ! On dirait Brad Pitt (si vous êtes un homme)/Angelina Jolie (si vous êtes une femme)/Willy (si vous êtes un orque) !"; Button envoyer = null; Button raz = null; EditText poids = null; EditText taille = null; RadioGroup group = null; TextView result = null; CheckBox mega = null; /*Error here with the semicolon, eclipse wants a ','*/ envoyer= (Button) findViewById(R.id.ca
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Syntax Error On Token Enum Interface Expected Eclipse
Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping syntax error on token identifier expected after this token each other. Join them; it only takes a minute: Sign up Syntax error on token “;”, { expected after this token in Random string creator up vote 1 down vote favorite I am writing code to generate a http://stackoverflow.com/questions/17796234/syntax-error-on-token-expected-java-programming random 3 letter strings using the letters a, b, and c. I am getting the error message "Syntax error on token ";", { expected after this token" after the line where i create the random variable (Random rand = new Random();). I do not know why I am getting this error when it looks fine to me. I am also getting the error message: Syntax error, insert "}" to complete ClassBody, after the last bracket in the http://stackoverflow.com/questions/18836404/syntax-error-on-token-expected-after-this-token-in-random-string-creator program. I am almost postive all my closing brackets match up so I do not know where this error is coming from. PLEASE HELP!! import java.util.*; public class Orders { String alphabet = "abc"; ArrayList
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us http://stackoverflow.com/questions/1755259/syntax-error-on-token-expected-after-this-token Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Syntax error on token “;”, { expected syntax error after this token up vote 3 down vote favorite why is there syntax error on this line ( shown below ) package org.temp2.cod1; import java.security.*; import javax.crypto.*; import javax.crypto.spec.*; import java.io.*; public class Code1 { byte[] plaintext = new byte[32]; // <<<<<<<<<<<<<<<<<<<<<<<<<< syntax error for (int i = 0; i < 32; i++) { plaintext[i] = (byte) (i % 16); } byte[] key = new byte[16]; SecureRandom syntax error on r = new SecureRandom(); r.nextBytes(key); Cipher c = Cipher.getInstance("AES"); SecretKeySpec k = new SecretKeySpec(key, "AES"); c.init(Cipher.ENCRYPT_MODE, k); byte[] encryptedData = c.doFinal(plaintext); } } java eclipse share|improve this question edited Sep 1 '11 at 19:09 Gray 78k12164228 asked Nov 18 '09 at 11:04 silverkid 2,370164981 add a comment| 2 Answers 2 active oldest votes up vote 11 down vote accepted You forgot the entry point method declaration. Try adding: public static void main(String[] args) { before the line where you got the error. share|improve this answer answered Nov 18 '09 at 11:09 Emil H 29.3k76082 eclipse suggested to add the public static void main(String[] args) throws NoSuchAlgorithmException, NoSuchPaddingException, InvalidKeyException, IllegalBlockSizeException, BadPaddingException { is that ok ? –silverkid Nov 18 '09 at 11:24 Yes - although you can omit the throws clause if you are not throwing any of those exceptions. –Chris Harcourt Nov 18 '09 at 11:31 add a comment| up vote 13 down vote your code should be inside a method. It appears to me that you have skipped the public void method(..) { line share|improve this answer answered Nov 18 '09 at 11:05 Bozho 385k82773945 add a comment| Your Answer draft saved draf