Java System.out.println Syntax Error
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System.out.println Syntax Error On Token(s) Misplaced Construct(s)
with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack syntax error on token expected after this token eclipse Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Java syntax error on `System.out.println()` method call [closed] up vote -1 down system.out.println(int songnum); vote favorite 1 I'm sorry for the extremely short question, but i don't even know why i have this error: Syntax error on token "println", = expected after this token In this code: static long start = System.currentTimeMillis(); public void testSort5() { Random random = new Random(); int number; int[] arr = new int[1000]; for (int counter = 1; counter < 1000; counter++) { number = 1 + random.nextInt(1000);
System Error On Token
arr[counter] = number; } int[] actual = MergeSort.sort(arr); } long end = System.currentTimeMillis(); System.out.println("Execution time was " + (end - start) + " ms."); java syntax-error share|improve this question edited Mar 19 '12 at 2:13 user155407 asked Mar 19 '12 at 0:23 Vladislav Bogdanov 410258 closed as off-topic by Patrick Hofman, Martijn Pieters♦, dav_i, Stijn, Qantas 94 Heavy Aug 18 '14 at 11:48 This question appears to be off-topic. The users who voted to close gave this specific reason:"This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – Patrick Hofman, Martijn Pieters, dav_i, StijnIf this question can be reworded to fit the rules in the help center, please edit the question. add a comment| 4 Answers 4 active oldest votes up vote 11 down vote You have statements outside your method body. share|improve this answer answered Mar 19 '12 at 0:25 Oliver Charlesworth 185k20366519 I already have like 50+ projects created in my current eclip
here for a quick overview of the site Help Center Detailed answers to any questions you might system.out.println multiple markers at this line have Meta Discuss the workings and policies of this site About system.out.println error in eclipse Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads
Syntax Error On Token Delete This Token
with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, http://stackoverflow.com/questions/9763584/java-syntax-error-on-system-out-println-method-call just like you, helping each other. Join them; it only takes a minute: Sign up System.out.print(“ ”); syntax error on token “.”, @ expected after this token up vote 0 down vote favorite I'm getting this error on this piece of code and I can't figure out what's wrong. public class enc { //The Look-Up http://stackoverflow.com/questions/26563939/system-out-print-syntax-error-on-token-expected-after-this-token Table with the position of all the available characters public static final String LUT="*, .abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"; Scanner sc=new Scanner(System.in); System.out.print("Input the sentence you want to encode."); String s= sc.nextLine(); } java share|improve this question edited Oct 25 '14 at 15:19 Fast Snail 7,85561847 asked Oct 25 '14 at 15:19 Lorena Sfăt 70111 1 For the close voter, this is a reproducible and is not a "simple" typing error. –CyberneticTwerkGuruOrc Oct 25 '14 at 15:26 add a comment| 4 Answers 4 active oldest votes up vote 2 down vote accepted You need to put the code inside a method: public class enc { //The Look-Up Table with the position of all the available characters public static final String LUT="*, .abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"; public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.print("Input the sentence you want to encode."); String s= sc.nextLine(); } } share|improve this answer answered Oct 25 '14 at 15:22 Pokechu22 3,61971843 add a comment| up vote 2 down vote The lines Scanner sc =
Certification Databases Caching Books Engineering Languages Frameworks Products This Site Careers Other all forums Forum: Beginning Java problem in System.out.println vinaykumar singh Greenhorn Posts: 13 posted 10 years ago hello all... i having a https://coderanch.com/t/402045/java/java/System-println problem in System.out.println(); see code and please guide me.(i m using Eclipse 3.0,and also tried https://coderanch.com/t/553699/java/java/Error-displayed-println-statement this code in diffrent editor) public class A { System.out.println("aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"); } i have a another main class where i calling class A. get error in class A System.out.println(); Multipal markers at this line -Syntax error on token ""aaaaaa"", delete this token -Syntax error on Token(s), misplaced construct(s) ----------------------------------------------------------- if i write only public class A { System.out.println(); syntax error } getting -Syntax error on token "println", Identifier expected after this token ------------------------------------------------------------------------- and if i decleared main method in class A there is no error like public class A { public static void main(String args[]){ System.out.println("aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"); } } -No Error ------------------------------------------------------------------------- please guide me why this is happening. thanks in advance... vinay kumar singh fred rosenberger lowercase baba Bartender Posts: 12225 36 I like... posted 10 years ago In error on token the first example, you can't have a statement that's not in a method. you could put the method in a constructor if you want it to print when the object is created, or you have to define a method like void printStuff(){ System.out.println("aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"); } and then call that method on the object. in the second example, i think it's because there is no version of println that takes no argument - you have to pass it SOMETHING. and, if you change it to pass in a parameter, you'll be back at the first example. in your third example, you have an enclosing method and a valid call to the println method. [ January 17, 2006: Message edited by: fred rosenberger ] There are only two hard things in computer science: cache invalidation, naming things, and off-by-one errors Layne Lund Ranch Hand Posts: 3061 posted 10 years ago Originally posted by fred rosenberger: in the second example, i think it's because there is no version of println that takes no argument - you have to pass it SOMETHING. Nope, the second example has the same problem as the first. You are only allowed to put variable declarations outside of a method. Any code that is to be executed must be inside a m
Certification Databases Caching Books Engineering Languages Frameworks Products This Site Careers Other all forums Forum: Beginning Java Error displayed at println statement. Joy Vergis Ranch Hand Posts: 54 posted 5 years ago i am new to java. I writing a program in eclipse. I get error at the println statement. Program: package package1; public class ClassA { String str1="a-b"; int a= str1.length(); //error at this line. System.out.println(); } Error displayed in eclipse: Syntax error on token "println", Identifier expected after this token. Please help fred rosenberger lowercase baba Bartender Posts: 12225 36 I like... posted 5 years ago you can't have code outside a method. you can declare variables, but you can't call methods or really 'do' stuff. There are only two hard things in computer science: cache invalidation, naming things, and off-by-one errors Pankaj Rathod Greenhorn Posts: 7 posted 5 years ago Also you are calling System.out.println() without any argument. Greg Brannon Bartender Posts: 563 posted 5 years ago You could start with the almost-obligatory "HelloWorld.java" program that teaches basic program structure and the elements required. You can find a tutorial using an appropriate Google search that either shows how to create and run the program using a basic text editor at the command line (recommended) or using Eclipse. If you've decided on Eclipse as your IDE, construct and run the HelloWorld program using both the command line and IDE approaches so that you see what Eclipse does for you and have an idea what you'll have to do without Eclipse. Always learning Java, currently using Eclipse on Fedora. Linux user#: 501795 Campbell Ritchie Sheriff Posts: 50581 82 posted 5 years ago Pankaj Rathod wrote:Also you are calling System.out.println() without any argument. What's wrong with that? Look in the documentation and see whether it is permissible. Campbell Ritchie Sheriff Posts: 50581 82 posted 5 years ago Don't use Eclipse or other IDEs at this stage. Post Reply Bookmark Topic Watch Topic New Topic Similar Threads Boxing/Unboxing and equality When to use keyword "const"? Just a reserved word. problem in System.out.println No suitable driver problem Getting exception with buffered loop... All times are in JavaRanch time: GMT-6 in summer, GMT-7 in winter Contact Us | advertise | mobile view | Powered by JForum | Copyright © 1998-2016 Paul Wheaton