Ms Access Sql Syntax Error In From Clause
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Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join syntax error in from clause access 2010 them; it only takes a minute: Sign up MS Access SQL Syntax error in FROM clause up vote 0 down vote favorite This is a long one. I've looked through archives for about 2 hours trying to see if there was anything close the issue I'm having so I wouldn't have to bother you guys. Sadly, I couldn't find syntax error in from clause sql anything. I thought that I was doing pretty good in learning SQL, but apparently I'm not as good as I thought. I'm in the vba editor of MS Access and I keep getting an error saying "Syntax error in FROM clause." I can't figure it out! I know the format((round(nz('s work. I've already tested those. I just cannot figure out why the FROM clause isn't working. I've got my code set up like this. Public Function strSQLForCalcFinal(qryString As String) strSQLForCalcFinal = "SELECT *," _ & "Nz(Format((Round(Nz([Punch_Time_1],0)*96)/96)*24,""Fixed""),0) AS Punch1, " _ & "Format((Round(Nz([Punch_Time_2],0)*96)/96)*24,""Fixed"") AS Punch2, " _ & "Format((Round(Nz([Punch_Time_3],0)*96)/96)*24,""Fixed"") AS Punch3, " _ & "Format((Round(Nz([Punch_Time_4],0)*96)/96)*24,""Fixed"") AS Punch4, " _ & "Format((Round(Nz([Punch_Time_5],0)*96)/96)*24,""Fixed"") AS Punch5, " _ & "Format((Round(Nz([Punch_Time_6],0)*96)/96)*24,""Fixed"") AS Punch6, " _ & "Format((Round(Nz([Punch_Time_7],0)*96)/96)*24,""Fixed"") AS Punch7, " _ & "Format((Round(Nz([Punch_Time_8],0)*96)/96)*24,""Fixed"") AS Punch8, " _ & "Format((Round(Nz([Punch_Time_9],0)*96)/96)*24,""Fixed"") AS Punch9, " _ & "Format((Round(Nz([Punch_Time_10],0)*96)/96)*24,""Fixed"") AS Punch10, " _ & "IIf(([punch2]-[punch1])>0,Format(([punch2]-[punch1]),""Fixed""),0) AS diff1, " _ & "IIf(([punch4]-[punch3])>0,Format(([punch4]-[punch3]),""Fixed""),0) AS diff2, " _ & "IIf(([punch6]-[punch5])>0,Format(([punch6]-[punch5]),""Fixed""),0) AS diff3, " _ & "IIf(([punch8]-[punch7])>0,Format(([punch8]-[punch7]),""Fixed""),0) AS diff4, " _ & "IIf(([punch10]-[punch9])>0,Format(([punch10]-[punch9]),""Fixed""),0) AS diff5, " _ & "CDbl([diff1])+CDbl([di
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Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping http://stackoverflow.com/questions/25295409/ms-access-sql-syntax-error-in-from-clause each other. Join them; it only takes a minute: Sign up MS Access syntax error in FROM clause up vote 0 down vote favorite I have the following query and I have no idea why I am getting the error Syntax error in FROM clause. SELECT * FROM t_object INNER JOIN ( SELECT * FROM t_objectproperties tag WHERE http://stackoverflow.com/questions/21465126/ms-access-syntax-error-in-from-clause tag.Property = 'Location' AND tag.Value = 'Queens' ) AS location ON t_object.Object_ID = location.Object_ID INNER JOIN ( SELECT * FROM t_objectproperties tag WHERE tag.Property = 'Room' AND tag.Value = 'King' ) AS type ON t_object.Object_ID = type.Object_ID ms-access share|improve this question edited Jan 30 '14 at 18:57 bluefeet♦ 147k33196278 asked Jan 30 '14 at 18:54 PeanutsMonkey 2,195123870 add a comment| 1 Answer 1 active oldest votes up vote 2 down vote accepted MS Access requires that you use parentheses around your multiple joins: SELECT * FROM (t_object INNER JOIN ( SELECT * FROM t_objectproperties as tag WHERE tag.Property = 'Location' AND tag.Value = 'Queens' ) AS location ON t_object.Object_ID = location.Object_ID) INNER JOIN ( SELECT * FROM t_objectproperties as tag WHERE tag.Property = 'Room' AND tag.Value = 'King' ) AS type ON t_object.Object_ID = type.Object_ID This could also be rewritten as: SELECT * FROM (t_object as o INNER JOIN t_objectproperties as location ON o.Object_ID = location.Object_ID) INNER JOIN t_objectproperties as type ON o.Object_ID = type.Object_ID WHERE location.Property = 'Location' AND l
here for a quick overview of the site Help Center http://stackoverflow.com/questions/35592305/syntax-error-in-from-clause-ms-access Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow https://bytes.com/topic/access/answers/208264-nested-sql-syntax-error-clause the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x syntax error Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Syntax error in FROM clause - MS ACCESS up vote 1 down vote favorite I am working with syntax error in a tool that would extract some data from an Access Database. So basically, i am working on a query to get this data. Below is the code i am currently working on. I am getting an error: Syntax error in FROM clause I can't seem to find where the query is going wrong. I would appreciate any help! Thank youu. EDIT: putting my actual query SELECT table_freq.*, IIF(table_freq.txn_ctr > (table_ave_freq.ave_freq * 3), "T", "F") as suspicious_flag FROM ( SELECT tbl_TransactionHistory.client_num, tbl_TransactionHistory.client_name, tbl_TransactionHistory.transaction_date, Count(tbl_TransactionHistory.client_num) AS txn_ctr FROM tbl_TransactionHistory GROUP BY tbl_TransactionHistory.client_num, tbl_TransactionHistory.client_name, tbl_TransactionHistory.transaction_date ) AS table_freq INNER JOIN ( SELECT table_total_freq.client_num, total_txn_ctr as TotalTransactionFrequency, total_no_days as TotalTransactionDays, (table_total_freq.total_txn_ctr)/(table_no_of_days.total_no_days) AS ave_freq FROM ( ( SELECT client_num, SUM(txn_ctr) AS total_txn_ctr FROM ( SELECT client_num, client_name, transaction_date, COUNT(client_num) AS txn_ctr FROM tbl_TransactionHistory GROUP BY client_num, client_name, transaction_date ) AS tabFreq GROUP BY client_num ) AS table_t
Need help? Post your question and get tips & solutions from a community of 418,595 IT Pros & Developers. It's quick & easy. Nested Sql - "Syntax Error in From Clause" P: n/a James Please help me with this sql: SELECT z005aNORTHEAST_3days_Formula.Region, z005aNORTHEAST_3days_Formula.DiffofClaimsAssignmen t FROM (SELECT [test].Region, ([test].[Date to Service Provider])-( [test].[Date Received By TNT]) AS DiffofClaimsAssignment FROM (SELECT [Claims Table 02_23_05].Region, [Claims Table 02_23_05].[Date received by TNT], [Claims Table 02_23_05].[Date To Service Provider], [Claims Table 02_23_05].[Date Acknowledged by DSP] FROM [Claims Table 02_23_05] WHERE ((([Claims Table 02_23_05].Region)="NORTHEAST"))) as test) AS z005aNORTHEAST_3days_Formula WHERE (((z005aNORTHEAST_3days_Formula.DiffofClaimsAssign ment)<=3 )); Access XP and 2003 returned correct data and correct nbr of records. After the query was saved and re-opened, it also provided correct data and nbr of records. Yet, whenever I revisited the design view and clicked on "Save", Access popped up an error msg: "Syntax Error in FROM Clause". Currently, I have only 400 records from the source table and the sql generates 4 rows of returned records. I do not know how to fix it & could not understand why Access automatically changed the sql after I reopend it (plz see below), but still show error msg. Thank you in advance. James in Plano SELECT z005aNORTHEAST_3days_Formula.Region, z005aNORTHEAST_3days_Formula.DiffofClaimsAssignmen t FROM [SELECT [test].Region, ([test].[Date to Service Provider])-( [test].[Date Received By TNT]) AS DiffofClaimsAssignment FROM (SELECT [Claims Table 02_23_05].Region, [Claims Table 02_23_05].[Date received by TNT], [Claims Table 02_23_05].[Date To Service Provider], [Claims Table 02_23_05].[Date Acknowledged by DSP] FROM [Claims Table 02_23_05] WHERE ((([Claims Table 02_23_05].Region)="NORTHEAST"))) as test]. AS z005aNORTHEAST_3days_Formula WHERE (((z005aNORTHEAST_3days_Formula.DiffofClaimsAssign ment)<=3 )); Nov 13 '05 #1 Post Reply Share this Questio