Operationalerror Near Syntax Error
Contents |
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this
Python Sqlite3 Operationalerror
site About Us Learn more about Stack Overflow the company Business Learn sqlite3.operationalerror syntax error more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question
Near Syntax Error Sqlite3
x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up sqlite3 sqlite3 operationalerror near text syntax error “OperationalError: near ”(“: syntax error” python up vote 2 down vote favorite simply put i am trying to make a sql database table and input data into it. I have it working in a simpler way, but when I put it into my script it results in this error. I'm hoping its something simple I missed. Any help/advice would be greatly appreciated. conn = sqlite3 syntax error sqlite3.connect('Data1.db') c = conn.cursor() # Create table c.execute('''CREATE TABLE Data_Output6 (date text, output6MV real)''') Averages_norm = [] for i, x in enumerate(Averages): Averages_norm.append(x*output_factor) c.execute("INSERT INTO Data_Output6 VALUES (%r,%r)" %(xdates[i],Averages_norm[-1])) conn.commit() results in the error: 57 for i, x in enumerate(Averages): 58 Averages_norm.append(x*output_factor) ---> 59 c.execute("INSERT INTO Data_Output6 VALUES (%r,%r)"%(xdates[i],Averages_norm[-1])) 60 conn.commit() 61 OperationalError: near "(": syntax error python sqlite3 share|improve this question edited May 15 '15 at 11:01 Martijn Pieters♦ 502k7513171472 asked May 15 '15 at 10:59 Ciaran 86111 So what data do you have in xdates? –Martijn Pieters♦ May 15 '15 at 11:02 3 Also, why are you using string interpolation instead of SQL parameters? –Martijn Pieters♦ May 15 '15 at 11:02 1 Try printing the statement before executing it. I'm sure you'll immediately spot the error. –Andrea Corbellini May 15 '15 at 11:57 2 You're inviting Booby Tables to tea... bobby-tables.com –LexyStardust May 15 '15 at 12:58 add a comment| 1 Answer 1 active oldest votes up vote 3 down vote accepted Simply put, let the DB API do that formatting: c.execute("INSERT INTO Data_Output6 VALUES (?, ?)", (xdates[i], Averages_norm[-1])) And refer to
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About
Sqlite3.operationalerror Unable To Open Database File
Us Learn more about Stack Overflow the company Business Learn more about hiring developers sqlite3.operationalerror no such table or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack
Sqlite3.operationalerror Database Is Locked
Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Python sqlite3 OperationalError: near “?”: syntax error http://stackoverflow.com/questions/30257826/sqlite3-operationalerror-near-syntax-error-python up vote 1 down vote favorite Trying to let users update column values on existing records for a specific table named "Scenario." The record being updated is identified by an index column called "Scenario_Key", unique to each instance of this class. The code I already have produces a dictionary of key, value pairs where key is the name of the column being updated and value is http://stackoverflow.com/questions/38577182/python-sqlite3-operationalerror-near-syntax-error the value being inserted into it. To update the sqlite database I'm trying the following: cursor.execute("""UPDATE Scenario SET ?=? WHERE Scenario_Key=?;""", (key, new_val, self.scenario_key)) But when I try to execute by clicking the "Save and Close" button, I get the following: Traceback (most recent call last): File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-tk/Tkinter.py", line 1536, in __call__ return self.func(*args) File "/Users/xxx/Documents/Consulting/DCA/Damage Control Assistant/EditScenarioWindow.py", line 91, in
Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the http://gis.stackexchange.com/questions/43590/why-is-sqlite-python-command-not-working company Business Learn more about hiring developers or posting ads with us Geographic Information Systems https://bytes.com/topic/python/answers/801071-sqlite-operationalerror-near Questions Tags Users Badges Unanswered Ask Question _ Geographic Information Systems Stack Exchange is a question and answer site for cartographers, geographers and GIS professionals. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top Why is SQLite python syntax error command not working? up vote 0 down vote favorite I am fairly new to python and am writing a code to read imagery and insert them into an SQLite database but I get the following error cur.execute(statement, (index,fullpath,filename)) sqlite3.OperationalError: near "index": syntax error. What is it that I am getting wrong? The following is the code: for root, dirnames, filenames in os.walk(basedir): print 'root is ' + root for filename in filenames: ext = os.path.splitext(filename)[1].lower() #extension as near syntax error lowercase if ext == extension: index = filename[:9] #tile ID filebase = os.path.splitext(filename)[0] #first part of filename fullpath = os.path.join(root,filebase) + ext #build up path again statement = "INSERT INTO %s (%s) VALUES " % (table,columns) + "(%s,%s,%s);" cur.execute(statement, (index,fullpath,filename)) print 'catalog entry: ' + index + ', ' + fullpath python sqlite share|improve this question edited Feb 12 '13 at 22:52 Fezter♦ 11.4k53980 asked Dec 10 '12 at 6:01 kartoza-geek 373210 Can you fix the indentation please? –BradHards Jan 13 '13 at 22:06 add a comment| 3 Answers 3 active oldest votes up vote 2 down vote It's not %s in your SQL prepared statements, it's ?. statement = "INSERT INTO %s (%s) VALUES (?, ?, ?);" % (table,columns) Also, you can define statement far earlier in your code (before the walk) and just reuse it. share|improve this answer answered Dec 14 '12 at 21:25 Jason Scheirer 14.8k23257 +1 It's an issue of sanitising inputs (in this case as they're strings, they need to be escaped by quotes in the code, which using ? will do for you). Better yet, if you can build a generator with yield you can use cursor.executemany(statement, iterator) –om_henners Feb 12 '13 at 23:25 add a comment| up vote 0 down vote I think: if ext == extension should be: if ext == "extension" unless extension i
and get tips & solutions from a community of 418,614 IT Pros & Developers. It's quick & easy. SQLite OperationalError near "?" P: n/a Hexade Hello I would like to use the safe "?" placeholder in my SQLite requests but I got the following error: Traceback (most recent call last): (...) cursor.execute("SELECT ? FROM ? WHERE name = ? ", (key, self.table, self.name)) OperationalError: near "?": syntax error key, self.table and self.name are standart strings. Any idea about how to solve this problem ? Thanks in advance, Hexade Jun 27 '08 #1 Post Reply Share this Question 2 Replies P: n/a John Machin On Apr 13, 8:45 am, Hexade