Parse Error Php Unexpected T_variable
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Parse Error: Syntax Error, Unexpected '$username' (t_variable)
only takes a minute: Sign up syntax error, unexpected T_VARIABLE [closed] up vote 7 down vote favorite I can't seem to find where my code has went wrong. Here is my full error: Parse error: syntax error, unexpected T_VARIABLE in
Parse Error Syntax Error Unexpected T_variable In Codeigniter
C:\xampp\htdocs\GigaLoad.com\register.php on line 102 But I've been looking a that line for hours. I will give you the entire code cause my newbie brain cant find the error: $query = mysql_query("SELECT * FROM users WHERE username='$username'") Hope you can help if you need more info just let me know. Here Is The Extra Code if (strstr($email, "@") && strstr($email, ".") && (strlen($email) >=6)){ require ("scripts/connect.php") $query = mysql_query("SELECT * FROM users WHERE username='$username'") // <-- Error here $numrows = mysql_num_rows syntax error, unexpected '$this' (t_variable) ($query) if ($numrows == 0){ /* ... */ EDIT: I am still getting major erros i will give the code and can you tell what i am missing php syntax-error share|improve this question edited Aug 30 '12 at 10:19 hakre 134k26216390 asked Feb 3 '12 at 21:32 Cory Fournier 41114 closed as too localized by Ryan♦, andrewsi, Sindre Sorhus, Vishal, hjpotter92 May 8 '13 at 3:24 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question. Can you give some of the surrounding code as well? The error might be because of a typo on a previous line. –templatetypedef Feb 3 '12 at 21:36 @templateypedef IPut The Extra Code Is That Enought –Cory Fournier Feb 3 '12 at 21:38 @CoryFournier You can edit your question. -_- –jsn Feb 3 '12 at 21:40 thanks @RiverC but i just go an error on the 103 line and i added the semi-colon –Cory Fournier Feb 3 '12 at 21:44 This fixed my error over a year later, idk why this was closed
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Parse Error: Syntax Error, Unexpected '$conn' (t_variable)
with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the syntax error, unexpected '$user' (t_variable) Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: parse error: syntax error, unexpected t_variable wordpress Sign up What is unexpected T_VARIABLE in PHP? up vote 41 down vote favorite 2 I get this PHP error: Parse error: syntax error, unexpected T_VARIABLE From this line: $list[$i][$docinfo['attrs']['@groupby']] = $docinfo['attrs']['@count']; Is there anything wrong with this line? php syntax-error http://stackoverflow.com/questions/9135784/syntax-error-unexpected-t-variable share|improve this question edited Aug 7 '14 at 20:24 Eric Leschinski 47.1k23221191 asked Sep 23 '09 at 9:26 omg 34.5k103235315 X-Ref: PHP Parse/Syntax Errors; and How to solve them? - Unexpected T_VARIABLE for the other common causes and context-specific fixes. –mario Aug 18 '15 at 14:56 add a comment| 2 Answers 2 active oldest votes up vote 89 down vote accepted There might be a semicolon or bracket missing a line before your pasted line. It seems fine to me, every http://stackoverflow.com/questions/1464919/what-is-unexpected-t-variable-in-php string is allowed as array index. share|improve this answer edited Aug 7 '14 at 20:09 Eric Leschinski 47.1k23221191 answered Sep 23 '09 at 9:30 knittl 107k26167227 Oh you reminded me,it's a bracket missed.Why it's called T_VARIABLE? –omg Sep 23 '09 at 9:32 1 The error message tells you what's there (unexpected), not what's missing. And there's a variable, so it tells you exactly that. –OregonGhost Sep 23 '09 at 9:34 1 Because the unexpected $list is a variable. –Michael Krelin - hacker Sep 23 '09 at 9:34 2 because php was expecting a bracket and found a variable, that's why it tells you ‘unexpected variable’ –knittl Sep 23 '09 at 9:37 add a comment| up vote 8 down vote It could be some other line as well, PHP is not always that exact. Probably you are just missing a semicolon on previous line. How to reproduce this error, put this in a file called a.php: Run it: eric@dev ~ $ php a.php PHP Parse error: syntax error, unexpected T_VARIABLE in /home/el/code/a.php on line 3 Explanation: The PHP parser converts your program to a series of tokens. A T_VARIABLE is a Token of type VARIABLE. When the parser processes tokens, it tries to make sense of them, and throws errors if it receives a variable where none is allowed. In the simple case above with variable $b, the pa
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the http://stackoverflow.com/questions/18768625/parse-error-in-php-code-unexpected-t-variable workings and policies of this site About Us Learn more about Stack https://www.codecademy.com/en/forum_questions/5211e84af10c607d6b000ff0 Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join syntax error them; it only takes a minute: Sign up Parse Error in PHP Code (unexpected T_VARIABLE) [closed] up vote -4 down vote favorite I am trying to run the following code: if ($result = $mysqli->query($query)) { /* fetch object array */ while ($row = $result->fetch_row()) { $query = "INSERT INTO Table2 SELECT s.* FROM Table1 s WHERE id=" . $row[1] syntax error, unexpected . ";" $mysqli->query($query); $query = "DELETE FROM Table1 WHERE id=" . $row[1] . ";" $mysqli->query($query); } /* free result set */ $result->close(); } But it's returning: $mysqli->query($query); Anyone know what it could be? Parse error: syntax error, unexpected T_VARIABLE ... php share|improve this question edited Sep 12 '13 at 15:41 Kermit 28k74881 asked Sep 12 '13 at 15:38 Satch3000 10.2k62148248 closed as off-topic by Boris Guéry, andrewsi, tereško, Sebastian, liyakat Sep 13 '13 at 3:42 This question appears to be off-topic. The users who voted to close gave this specific reason:"Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist" – andrewsi, tereško, Sebastian, liyakatIf this question can be reworded to fit the rules in the help center, please edit the question. 1 you forgot a ; in the line just before. –Hugo Dozois Sep 12 '13 at 15:40 HTML/CSS reputation. He's learning PHP I guess. @Satch3000 You need to learn ho
Forum View Course 176 points Submitted by James Barclay about 3 years ago Confusing error with PHP objects - Unexpected T_VARIABLE, expecting T_FUNCTION Whenever I create a new instance of an object I receive this error: Parse error: syntax error, unexpected TVARIABLE, expecting TFUNCTION on line ...(in the example to come, line 10) The code passes each task, however I just wanted to know whether this is actually a legitimate error in how I'm writing the code or whether it is a error not related to me. Below is the simplest code I have done that still produces the error.
` 1 vote permalink You're supposed to create the instance outside of the class: class Person{ } $me = new Person(); 322 points Submitted by DM about 3 years ago