Parse Error Syntax Error Unexpected T_string In Php
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T_string Php
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Expecting T_constant_encapsed_string
vote 1 down vote favorite I am getting a syntax error for this PHP code syntax error, unexpected T_STRING It says line 2, which is the include line:
Unexpected T_constant_encapsed_string Error In Php
// Firstly Lets build the Category List $result = mysql_query('SELECT category_id,category_name FROM gallery_category'); while($row = mysql_fetch_array($result)) { $photo_category_list .= <<<__HTML_END \n __HTML_END; } mysql_free_result( $result ); // Lets build the Image Uploading fields while($counter <= $number_of_fields) { $photo_upload_fields .= <<<__HTML_END
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Syntax Error Unexpected T_string Laravel
Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs parse error syntax error unexpected t_string expecting t_constant_encapsed_string Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join http://stackoverflow.com/questions/10783733/php-syntax-error-unexpected-t-string them; it only takes a minute: Sign up Parse error: syntax error, unexpected 'INTO' (T_STRING) on line 7 up vote -1 down vote favorite I get this error when running this code, im using it to add a specific filter to a database. http://stackoverflow.com/questions/25199444/parse-error-syntax-error-unexpected-into-t-string-on-line-7 mysqli_connect_error(); } // sql insertationerino $sql = INSERT INTO filterlist ('type_code', 'connector_type', 'construction_type', 'author', 'estimate_lead_time', 'last_update', 'confidence_level', 'passtype', 'start_passband', 'stop_passband', 'low_stopband', 'high_stopband', 'low_passband', 'high_passband', 'start_stopband', 'stop_stopband') VALUES ('".$_POST['type_code']."', '".$_POST['connector_type']."', '".$_POST['construction_type']."', '".$_POST['author']."', '".$_POST['estimate_lead_time']."', '".$_POST['last_update']."', '".$_POST['confidence_level']."', '".$_POST['passtype']."', '".$_POST['start_passband']."', '".$_POST['stop_passband`']."', '".$_POST['low_stopband']."', '".$_POST['high_stopband']."', '".$_POST['low_passband']."', '".$_POST['high_passband']."', '".$_POST['start_stopband']."', '".$_POST['start_stopband']."'); if (!mysqli_query($con,$sql)) { die('Error: ' . mysqli_error($con)); } echo "1 Filter Added"; mysqli_close($con); ?> The full error is: Parse error: syntax error, unexpected 'INTO' (T_STRING) in C:\xampp\htdocs\html\addprocess.php on line 7 php mysql phpmyadmin share|improve this question asked Aug 8 '14 at 8:50 thomasward1212 1815 4 Your SQL query should be a string as far as PHP is concerned, so quoted as a string –Mark Baker Aug 8 '14 at 8:51 add a comment| 3 Answers 3 active oldest votes up vote 1 down vote accepted First of all you need to learn basic of php. Any string should be inside quotation. You'll need to escape the values before you put them into query by using mysqli_real_escape_string() try like this: $sql = "INSERT INTO filterlist (`type_code`, `connector_type`, `construction_type`, `author`, `estimate_lead_time`, `last_update`, `confidence_level`, `passty
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack http://stackoverflow.com/questions/17200112/parse-error-syntax-error-unexpected-t-string-expecting Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community https://www.codecademy.com/en/forum_questions/52bb7913548c35e324005ed6 of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Parse error: syntax error, unexpected T_STRING, expecting ')' [closed] up vote -3 down vote favorite I am syntax error getting error on my site Parse error: syntax error, unexpected T_STRING, expecting ')' in /home/**/public_html/config.php on line 111 My PHP code in FROM line 107 TO 112 is: //PayPal Settings $config [ 'paypal' ] = array( 'url' => ' https://www.paypal.com/cgi-bin/webscr ' , //url na koeto da prashta formata 'business' => 'http://startmarketplace.com/themeforestclone-demo/, / Your PayPal ID or an email address ' currency ' => ' USD ' //valuta v koqto e cenata syntax error unexpected EUR, USD etc. ); Start line is 107. Last line is line 112. Line on which I am getting error is (111) is: ' currency ' => ' USD ' //valuta v koqto e cenata EUR, USD etc Plz help.. Thanks :) php share|improve this question edited Jun 19 '13 at 19:53 andrewsi 10.3k112543 asked Jun 19 '13 at 19:52 Ashish Srivastava 11111 closed as too localized by John Conde, andrewsi, nickb, Madara Uchiha♦, PeeHaa Jun 19 '13 at 23:17 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question. 7 I've put this in a code block for you. The highlighting should help you spot the error. –andrewsi Jun 19 '13 at 19:53 add a comment| 2 Answers 2 active oldest votes up vote 3 down vote This code should work: ' https://www.paypal.com/cgi-bin/webscr ' , //url na koeto da prashta format
PHP Forum View Course 508 points Submitted by bobfleming almost 3 years ago 5/10 Parse error: syntax error, unexpected T_STRING, expecting T_VARIABLE on line 16 In both 5/10 and 6/10 I ge the following parsing error: Parse error: syntax error, unexpected TSTRING, expecting TVARIABLE on line 16 This is line 16: public function_construct($firstname, $lastname, $age) { I can't find anything wrong. I know what strings and variables are, but what does the prefix "T" indicate in the error message? Despite the message, the m\code passes to go on to the next exercise, but there is no output. I am using the code from 1/10 as a guide, along with instructions and hints, and everything in my code looks right! $frustration = "unresolved errors!"; My complete code follows:
firstname = $firstname; $this->lastname = $lastname; $this->age = $age; public function $greet() { return "Hello, my name is " . $this->firstname . " " . $this->lastname . '. nice to meet you! :-)"; } } $teacher = new Person ("boring", "12345"' 12345); $student = new Person ("Bob", "Fleming", 77); echo greet($teacher); echo greet($student); echo $student->age; ?>
0 votes permalink Something I forgot to point out in my question above -- I see nothing in my constructor that looks anything like a string (enclosed in ' ' or " ")!!! One more thing is that since I posted my question I worked through the remaining exercises up through 10/10, and I got the same parsing error on the constructor in all of them, and none of them went, but all of them gave the "Way to go! and the green "Start next lesson" button. Go figure! This could be a bug in the parsing code. 508 points Submitted by bobfleming almost 3 years ago 0 votes permalink Hi Bob, you need to get a space in there before __construct. It also looks like the closing } is missing from that function. Getting a "Way to go!" is annoying with errors like that in the code. I'll check in the Buggy Exercises gro