Parse Error Syntax Error Unexpected T_var Php
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Parse Error Syntax Error Unexpected '$name' (t_variable)
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Syntax Error, Unexpected '$user' (t_variable)
it only takes a minute: Sign up what does Parse error: syntax error, unexpected T_VARIABLE acutally mean [duplicate] up vote 1 down vote favorite This question already has an answer here: Reference - What does this error mean in PHP? 29 answers hello I am getting this error Parse error: syntax error, unexpected T_VARIABLE in F:\xampp\htdocs\jim\home.php on line 6 $ses_id parse error syntax error unexpected t variable in php = session_id(); $user =$_SESSION['user'] $sesssion_id=$_SESSION['sessionid'] if($user == "" || $sesssion_id != $ses_id) { echo "go back"; } can anyone tell me what exactly this error mean ? and please see where i am doing wrong php share|improve this question edited Mar 16 '14 at 20:06 Kamehameha 4,5421924 asked Mar 16 '14 at 20:01 Mirza Sahaib 84110 marked as duplicate by Robbie Averill, Fred -ii-, Mark Parnell, Ed Cottrell♦, kinakuta Mar 16 '14 at 22:37 This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question. 1 add two ; semi-colons in this two statements ...$user =$_SESSION['user'] $sesssion_id=$_SESSION['sessionid'] –Tun Zarni Kyaw Mar 16 '14 at 20:04 if you are just looking what T_VARIABLE means ... view this one stackoverflow.com/questions/7640419/… –Tun Zarni Kyaw Mar 16 '14 at 20:09 add a comment| 3 Answers 3 active oldest votes up vote 2 down vote Unexpected T_VARIABLE usally means that php was parsing your code, but something unexpected came up as the next characters. So when
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Parse Error: Syntax Error, Unexpected T_constant_encapsed_string
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Parse Error: Syntax Error, Unexpected T_string
Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping parse error: syntax error, unexpected '' (t_encapsed_and_whitespace) each other. Join them; it only takes a minute: Sign up What is unexpected T_VARIABLE in PHP? up vote 41 down vote favorite 2 I get this PHP error: Parse error: syntax error, unexpected T_VARIABLE From this line: $list[$i][$docinfo['attrs']['@groupby']] http://stackoverflow.com/questions/22442208/what-does-parse-error-syntax-error-unexpected-t-variable-acutally-mean = $docinfo['attrs']['@count']; Is there anything wrong with this line? php syntax-error share|improve this question edited Aug 7 '14 at 20:24 Eric Leschinski 47.1k23221191 asked Sep 23 '09 at 9:26 omg 34.5k103235315 X-Ref: PHP Parse/Syntax Errors; and How to solve them? - Unexpected T_VARIABLE for the other common causes and context-specific fixes. –mario Aug 18 '15 at 14:56 add a comment| 2 Answers 2 active oldest votes up vote 89 down vote accepted There might be http://stackoverflow.com/questions/1464919/what-is-unexpected-t-variable-in-php a semicolon or bracket missing a line before your pasted line. It seems fine to me, every string is allowed as array index. share|improve this answer edited Aug 7 '14 at 20:09 Eric Leschinski 47.1k23221191 answered Sep 23 '09 at 9:30 knittl 107k26167227 Oh you reminded me,it's a bracket missed.Why it's called T_VARIABLE? –omg Sep 23 '09 at 9:32 1 The error message tells you what's there (unexpected), not what's missing. And there's a variable, so it tells you exactly that. –OregonGhost Sep 23 '09 at 9:34 1 Because the unexpected $list is a variable. –Michael Krelin - hacker Sep 23 '09 at 9:34 2 because php was expecting a bracket and found a variable, that's why it tells you ‘unexpected variable’ –knittl Sep 23 '09 at 9:37 add a comment| up vote 8 down vote It could be some other line as well, PHP is not always that exact. Probably you are just missing a semicolon on previous line. How to reproduce this error, put this in a file called a.php: Run it: eric@dev ~ $ php a.php PHP Parse error: syntax error, unexpected T_VARIABLE in /home/el/code/a.php on line 3 Explanation: The PHP parser converts your program to a series of tokens. A T_VARIABLE is a Token of type VARIABLE
If this is your first visit, be sure to http://board.phpbuilder.com/showthread.php?10376460-RESOLVED-Parse-error-syntax-error-unexpected-T_VARIABLE check out the FAQ by clicking the link above. https://forums.digitalpoint.com/threads/parse-error-syntax-error-unexpected-t_variable.497560/ You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. Results 1 to syntax error 5 of 5 Thread: [RESOLVED] Parse error: syntax error, unexpected T_VARIABLE Tweet Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Search Thread Advanced Search Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 10-27-2010,10:06 AM #1 LemonTea parse error syntax View Profile View Forum Posts Junior Member Join Date Oct 2010 Posts 3 [RESOLVED] Parse error: syntax error, unexpected T_VARIABLE Hello all! I'm very, very new in this PHP stuff [Just started this night!] And I was playing around when I got this error message: Parse error: syntax error, unexpected T_VARIABLE in C:\xampp\htdocs\bohoo\index.php on line 30 PHP Code: You can target relevant areas of the site and show ads based on geographical location of the user if you wish. Starts at just $1 per CPM or $0.10 per CPC. Parse error: syntax error, unexpected T_VARIABLE Discussion in 'PHP' started by leeno, Oct 1, 2007. 0 leeno Peon Messages: 2 Likes Received: 0 Best Answers: 0 Trophy Points: 0 #1 Hi there, Parse error: syntax error, unexpected T_VARIABLE in /home/username/public_html/website/bookstore/classes.php on line 69 I would be most grateful if someone could put me right on the error I have below. I did read that the error can be somewhere else on the page and maybe not on line 69 is that correct? I have included part of the codes below. Many thanks hope you can help. LINE 65 global $db,$prefix; LINE 66 LINE 67 LINE 68 LINE 69 $result = $db->query ("SELECT the_key, body FROM " $prefix ."email"); LINE 70 LINE 71 LINE 72 LINE 73 while($row = $result->fetch_array()) LINE 74 LINE 75 { LINE 76 LINE 77 $key = $row['the_key']; LINE 78 LINE 79 $EMAILS["$key"] = $row['body']; leeno, Oct 1, 2007 IP rickvb Active Member Messages: 150 Likes Received: 0 Best Answers: 0 Trophy Points: 53 #2 You forgot to end the while loop while($blah = mysql_fetch_rows($query)){ // do something in the loop } //close tag!! rickvb, Oct 1, 2007 IP TwistMyArm Peon Messages: 931 Likes Received: 44 Best Answers: 0 Trophy Points: 0 #3 Instead of: $result = $db->query ("SELECT the_key, body FROM " $prefix ."email"); it should be: $result = $db->query ("SELECT the_key, body FROM " . $prefix ."email"); You forgot to put the concatenator(sp?) before the $prefix variable. TwistMyArm, Oct 1, 2007 IP Ervee Peon Messages: 53 Likes Received: 1 Best Answers: 0 Trophy Points: 0 #4 this error most often means you forgot one of these ' ; ' " ) ( [ ] Ervee, Oct 1, 2007 IP dcjokerbx Peon Messages: 4 Likes Received: 0 Best Answers: 0 Trophy Points: 0 #5 I have a similar problem. I get the same error message on line 17. Here is my code. set_time_limit(0);
functionutime(){
$time=explode("",microtime());
$usec=(double)$time[0];
$sec=(double)$time[1];
return