Parse Error Syntax Error Unexpected T_variable In Php
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Unexpected T Variable Php
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Parse Error: Syntax Error, Unexpected T_variable Wordpress
more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags parse error syntax error unexpected t_variable in codeigniter Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Parse error: syntax error, unexpected T_VARIABLE on line 5 [closed] up parse error syntax error unexpected t variable in php vote 3 down vote favorite I am new to PHP and am encountering this parsing error. My code is: Line 5 starts at the %sql ="INSERT INTO... ends at camperSwimming) I am not sure what I am doing wrong. php sql wordpress share|improve this question edited Dec 5 '13 at 3:02 John Conde 156k70289364 asked Dec 5 '13 at 3:01 user3068434 closed as off-topic by meagar♦, andrewsi, Dukeling
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Parse Error: Syntax Error, Unexpected '$username' (t_variable)
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Syntax Error, Unexpected '$user' (t_variable)
Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping http://stackoverflow.com/questions/20390593/parse-error-syntax-error-unexpected-t-variable-on-line-5 each other. Join them; it only takes a minute: Sign up Parse error: syntax error, unexpected '$result' (T_VARIABLE) [closed] up vote -3 down vote favorite I got a problem when I run the below code: function newUser($email,$pwd,$pwd2,$firstname,$surname,$isAdmin=0){ $email = $this->verify('Email',$email,10,40); $pwd = $this->verify('Password',$pwd,6,20); $pwd2 = $this->verify('Password',$pwd2,6,20); $firstname = $this->strToTitle($this->verify('Name',$firstname,2,40)); $surname = $this->strToTitle($this->verify('Title',$surname,2,40)); if ($pwd != $pwd2) return http://stackoverflow.com/questions/13341057/parse-error-syntax-error-unexpected-result-t-variable -1; $key=md5("secure") $result = $this->query("INSERT INTO user (email, pw, firstname, surname, isAdmin) VALUES (".$email.", AES_ENCRYPT(".$pwd.",".$key."), ".$firstname.", ".$surname.", ".$isAdmin.")"); if (mysql_affected_rows()>0) return mysql_insert_id(); else return 0; } It always prompt "Parse error: syntax error, unexpected '$result' (T_VARIABLE) in F:\xampp\htdocs\sql.php on line 76" Any one can keep me some advise?? Many thanks!! php mysql share|improve this question edited Oct 11 '13 at 10:25 Aelios 5,79422345 asked Nov 12 '12 at 9:22 Art 20226 closed as too localized by deceze, Gordon, Petah, Leri, GBD Nov 12 '12 at 9:29 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question. The line 76 represent this line: $result = $this->query("INSERT INTO user (email, pw, fi
in PHP Forum View Course » View Exercise 578 points Submitted by Ruhi Mukherjee over 2 years ago Parse error: syntax error, unexpected T_VARIABLE, syntax error expecting T_FUNCTION on line 26 My Code is getting submitted but is showing the error on line 26th Challenge Time! name = $name; } public function meow() { return "Meow meow"; } $cat1 = new Cat("CodeCat"); //line 26 echo $cat1->meow(); } ?>