Php Parse Error Unexpected T_variable
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company parse error syntax error unexpected t_variable in php Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs unexpected t variable php Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, parse error syntax error unexpected '$name' (t_variable) just like you, helping each other. Join them; it only takes a minute: Sign up PHP Parse error: syntax error, unexpected T_VARIABLE [closed] up vote 1 down vote favorite I get this error: PHP Parse error: syntax parse error: syntax error, unexpected '$username' (t_variable) error, unexpected T_VARIABLE on line 47 The 47th line is: $queryb = "UPDATE `situation` SET `status`='" . $stats . "', `time`='" . $time . "', `name`='" . $name . "', `notes`='" . $notes . "'"; I just don't get it. Maybe script error or syntax error?
Parse Error Syntax Error Unexpected T_variable In Codeigniter
`message` (`name`, `time`, `body`) VALUES ('" . $name . "', '" . $time . "', '" . $body . "')"; mysqli_query($con,$query); mysqli_close($con); } elseif ($c = "setting") { $time = $_REQUEST['time']; $name = $_REQUEST['name']; $notes = $_REQUEST['notes']; $con = mysqli_connect("this,is,already,true"); $stats = $_REQUEST['status'] $queryb = "UPDATE `situation` SET `status`='" . $stats . "', `time`='" . $time . "', `name`='" . $name . "', `notes`='" . $notes . "'"; mysqli_query($con,$query); mysqli_close($con); }; }; ?> php mysql share|improve this question edited Jan 2 '14 at 10:39 veelen 1,437825 asked Jan 2 '14 at 10:19 Reinaldy Rafli 1861313 closed as off-topic by 웃웃웃웃웃, tereško, Sam Dufel, fvu, S.L. Barth Feb 28 '14 at 16:03 This question appears to be off-topic. The users who voted to close gave this specific reason:"This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – Sam Dufel, fvu, S.L. BarthIf this question can be reworded to fit the rules in the help center, please edit the question. 1 Probably a missing ; at the end of line 46.... and
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Syntax Error, Unexpected '$this' (t_variable)
policies of this site About Us Learn more about Stack Overflow the syntax error, unexpected '$user' (t_variable) company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags syntax error unexpected '$this' (t_variable) expecting function (t_function) Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes http://stackoverflow.com/questions/20880694/php-parse-error-syntax-error-unexpected-t-variable a minute: Sign up What is unexpected T_VARIABLE in PHP? up vote 41 down vote favorite 2 I get this PHP error: Parse error: syntax error, unexpected T_VARIABLE From this line: $list[$i][$docinfo['attrs']['@groupby']] = $docinfo['attrs']['@count']; Is there anything wrong with this line? php syntax-error share|improve this question edited Aug 7 '14 at 20:24 Eric Leschinski 47.1k23221191 asked Sep 23 '09 at 9:26 http://stackoverflow.com/questions/1464919/what-is-unexpected-t-variable-in-php omg 34.5k103235315 X-Ref: PHP Parse/Syntax Errors; and How to solve them? - Unexpected T_VARIABLE for the other common causes and context-specific fixes. –mario Aug 18 '15 at 14:56 add a comment| 2 Answers 2 active oldest votes up vote 89 down vote accepted There might be a semicolon or bracket missing a line before your pasted line. It seems fine to me, every string is allowed as array index. share|improve this answer edited Aug 7 '14 at 20:09 Eric Leschinski 47.1k23221191 answered Sep 23 '09 at 9:30 knittl 107k26167227 Oh you reminded me,it's a bracket missed.Why it's called T_VARIABLE? –omg Sep 23 '09 at 9:32 1 The error message tells you what's there (unexpected), not what's missing. And there's a variable, so it tells you exactly that. –OregonGhost Sep 23 '09 at 9:34 1 Because the unexpected $list is a variable. –Michael Krelin - hacker Sep 23 '09 at 9:34 2 because php was expecting a bracket and found a variable, that's why it tells you ‘unexpected variable’ –knittl Sep 23 '09 at 9:3
here for a quick overview of the site Help Center Detailed answers to any questions http://stackoverflow.com/questions/27970836/parse-error-syntax-error-unexpected-t-variable-on-line-107 you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring http://board.phpbuilder.com/showthread.php?10384011-RESOLVED-Syntax-Error-Unexpected-T_Variable-on-Line-18 developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is syntax error a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Parse error: syntax error, unexpected T_VARIABLE on line 107 [duplicate] up vote -3 down vote favorite 1 This question already has an answer here: Reference - What does this error mean in syntax error unexpected PHP? 29 answers The line 107 in the below code is $sql="INSERT INTO " $table_name " (confirm_code,name,password,email,address,phone,education,date_of_birth) VALUES ('".$confirm_code."','".$name."','".$pwd."','".$email."','".$adres."','".$phno."','".$educon."','".$dob."') "; " i am getting unexpected T_VARIABLE; Email '.$email.' Already exists
'; } else { $sql="INSERT INTO " $table_name "(confirm_code,name,password,email,address,phone,education,date_of_birth) VALUES ('".$confirm_code."','".$name."','".$pwd."','".$email."','".$adres."','".$phno."','".$educon."','".$dob."') "; $result = mysql_query($sql, $con) or die(mysql_error()); if($result) { $to=$email; echo ''.$name.' Your Registration Success
'; $subject = "your confirmation link here"; $headers = 'MIME-Version: 1.0' . "\r\n"; $headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n"; $header = 'From: ShareLibrary <'.ADMIN_MAIL.'>' . "\r\n"; $admMesg = $email." is registered "; $message = "your confrimation link \r\n"; $message = "click on this link to activae your account \r\n";
18 If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. Results 1 to 4 of 4 Thread: [RESOLVED] Syntax Error, Unexpected T_Variable on Line 18 Tweet Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Search Thread Advanced Search Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 04-07-2012,06:29 PM #1 Minecraft_iPod View Profile View Forum Posts Member Join Date Apr 2012 Posts 33 [RESOLVED] Syntax Error, Unexpected T_Variable on Line 18 Hi, I am a TOTAL newbie at PHP, and I am building off a tutorial website. But, to my utter disappointement () I can't figure out what went wrong with my code. I keep getting this exact error (I took out personal information): "Parse error: syntax error, unexpected T_VARIABLE in /xxxx/xxxxxxxx/xxxxxx_xxxx/members.php on line 18" Here is my code (again, without personal information): PHP Code:
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//Connecttothedatabaseserver
mysql_connect("xxxxxx.xxxxxxxxxx.xxx","xxxxxxxx_xxxxx","xxxxxxxx")ordie(mysql_error());
//Selectdatabase
mysql_select_db("xxxxxxxx_xxxxx"