Postgresql Syntax Error At Or Near Create
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Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it create table if not exists postgres only takes a minute: Sign up PostgreSql ERROR: 42601: syntax error at or near “CREATE” up vote 0 down vote favorite I am using method ApplyToDatabase(string statements) The statements I am taking from one of the folders, opening, reading, executing using ExecuteNonQuery and the Problem is that after some SQL statements I got ERROR: 42601: syntax error at or near foreign key postgres "CREATE".. Firstable that works and suddenly stops giving me again ERROR: 42601: syntax error at or near "CREATE". For example this two in a row: CREATE TABLE sd_cookies ( ========>>>>>> this works ) CREATE TABLE sd_groups ( id integer DEFAULT nextval('groups_serials'), grpname varchar(40) not null, grptype char(1) DEFAULT 'C', ======>>>> this not PRIMARY KEY(id) ) postgresql share|improve this question edited Oct 23 '14 at 18:41 a_horse_with_no_name 187k24236312 asked Oct 23 '14 at 18:23 Xrama 111 2 You need to terminate each statement with a ;. Did you do that? –a_horse_with_no_name Oct 23 '14 at 18:41 Actually there is no need to terminate Statement in this case,but thanks anyway :) –Xrama Oct 23 '14 at 22:12 add a comment| 1 Answer 1 active oldest votes up vote 0 down vote There is nothing wrong with this definition. The problem must be in parts not shown here. Test: str@s131-intel:~> psql psql (9.2.7) str=# create sequence groups_serials; CREATE SEQUENCE str=# CREATE TABLE sd_groups ( str(# id integer DEFAULT nextval('groups_serials'), str(# grpname varchar(40) not null, str(# grptype char(1) DEFAU
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at or near "createuser" From: <2athep+5ud7717ssvxx4(at)guerrillamail(dot)com> To: "pgsql-general(at)postgresql(dot)org"
8.1 / 8.2 / 8.3 / 8.4 / 9.0 PostgreSQL 8.0.26 Documentation Prev Fast Backward Chapter 31. Extending SQL Fast Forward Next https://www.postgresql.org/docs/8.0/static/xfunc-sql.html 31.4. Query Language (SQL) Functions SQL functions execute an arbitrary list of SQL statements, returning the result of the last query in the list. In the simple (non-set) case, the first row https://codedump.io/share/rUSXsVxTL3vK/1/postgresql-syntax-error-at-or-near-quot-then-quot of the last query's result will be returned. (Bear in mind that "the first row" of a multirow result is not well-defined unless you use ORDER BY.) If the last query happens syntax error to return no rows at all, the null value will be returned. Alternatively, an SQL function may be declared to return a set, by specifying the function's return type as SETOF sometype. In this case all rows of the last query's result are returned. Further details appear below. The body of an SQL function must be a list of SQL statements separated by syntax error at semicolons. A semicolon after the last statement is optional. Unless the function is declared to return void, the last statement must be a SELECT. Any collection of commands in the SQL language can be packaged together and defined as a function. Besides SELECT queries, the commands can include data modification queries (INSERT, UPDATE, and DELETE), as well as other SQL commands. (The only exception is that you can't put BEGIN, COMMIT, ROLLBACK, or SAVEPOINT commands into a SQL function.) However, the final command must be a SELECT that returns whatever is specified as the function's return type. Alternatively, if you want to define a SQL function that performs actions but has no useful value to return, you can define it as returning void. In that case, the function body must not end with a SELECT. For example, this function removes rows with negative salaries from the emp table: CREATE FUNCTION clean_emp() RETURNS void AS ' DELETE FROM emp WHERE salary < 0; ' LANGUAGE SQL; SELECT clean_emp(); clean_emp ----------- (1 row) The syntax of the CREATE FUNCTION command requires the function body to be written as a string const
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SELECT
P.POSIZIONE_DEVICE_ID AS MONITOR_DEVICE_ID,
P.VALID AS VALID,
[...]
IF (VALID == FALSE THEN 'Valid' ELSE P.REASON_FOR_INVALID) AS DESCRIPTION,
[...]
FROM public.TA_POSIZIONI_DEVICE P
JOIN ...
TA_POSIZIONI_DEVICE VALID (Boolean not null) wingedpanther Answer Email {} Share You should use CASE The SQL CASE expression is a generic conditional expression, similar to if/else statements in other programming languages CASE WHEN condition THEN result [WHEN ...] [ELSE result] END So, CREATE OR REPLACE VIEW VW_MONITOR_DEVICE AS SELECT P.POSIZIONE_DEVICE_ID AS MONITOR_DEVICE_ID, P.VALID AS VALID, [...] CASE WHEN VALID = false THEN 'Valid' ELSE P.REASON_FOR_INVALID END AS DESCRIPTION, [...] FROM public.TA_POSIZIONI_DEVICE P JOIN ... Source (Stackoverflow) http://stackoverflow.com/questions/35427991/postgresql-syntax-error-at-or-near-then Comments Please enable JavaScript to view the comments powered by Disqus. × Email codedump link for Postgresql Syntax error at or near " THEN " Email has been send. To emailaddress: To name: From name: Extra information in the email body (optional): Email: I am sending you the codedump of Postgresql Syntax error at or near " THEN " that you can see here: https://codedump.io/share/rUSXsVxTL3vK/1 Close Send email Share Sign up Sign up with GitHub Email: Displayname Password: Repeat password: Tags sql postgresql syntax-error create-view Latest added CategoricalPredictor How to access nested JSON with Alamofire and Swift 3? Please help me out to Generate SMSGATEWAYHUB API with PHP to Send OTP SMS quadtree 3d (2) quadtree 3d © 2016 CodeDump |Terms Privacy Rss API Sign in -Sign up For programmers by programmers Tag v2.2.4