Prototype Syntax Error
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instancesPropertiesMethodsExamplesCatching a SyntaxErrorCreating a SyntaxErrorSpecificationsBrowser compatibilitySee also The SyntaxError object represents an error when trying to interpret syntactically invalid code. Description A SyntaxError is thrown when the JavaScript engine encounters tokens or token order that does not conform to the syntax of the language when parsing code. Syntax new SyntaxError([message[, fileName[, lineNumber]]]) Parameters message Optional. Human-readable description of the error fileName Optional. The name of the file containing the code that caused the exception lineNumber Optional. The line number of the code that caused the exception Properties SyntaxError.prototype Allows the addition of properties to a SyntaxError object. Methods The global SyntaxError contains no methods of its own, however, it does inherit some methods through the prototype chain. SyntaxError instances Properties SyntaxError.prototype.constructor Specifies the function that created an instance's prototype. SyntaxError.prototype.message Error message. Although ECMA-262 s
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Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/SyntaxError it only takes a minute: Sign up Syntax Error in creating javascript constructor function up vote 0 down vote favorite I am trying to create a constructer function as follows in javascript. But i get the error: SyntaxError: Unexpected token ILLEGAL I am getting this when i run the following in chrome developer tools console: function People () { this.superstar http://stackoverflow.com/questions/28993090/syntax-error-in-creating-javascript-constructor-function = "Michael Jackson"; } Is there any syntax error in the same. If not then whats causing the error. javascript prototype function-constructor share|improve this question asked Mar 11 '15 at 17:13 jsbisht 1,73212028 3 There's a non-printng \u200b in front of this at line two. See a red dot at jsFiddle. –Teemu Mar 11 '15 at 17:16 Oh yes. Now i get it. –jsbisht Mar 11 '15 at 17:23 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted You probably have a weird invisible character there, but rewriting it works fine: function People(){ this.superstar = "Michael Jackson"; } share|improve this answer answered Mar 11 '15 at 17:16 juvian 9,1842916 Oh man. I should have thought of that. Thx :) –jsbisht Mar 11 '15 at 17:21 1 Well, just thought about it because it has happened to me before ;). Usually faster to rewrite than finding the wrong character. Now you already know for next time! –juvian Mar 11 '15 at 17:22 certainly. I will
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings http://stackoverflow.com/questions/31274760/isdouble-function-prototype-syntax-error-warning-data-definition-has-no-type and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags https://courses.cs.washington.edu/courses/cse142/info/syntaxErr.html Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only syntax error takes a minute: Sign up IsDouble function prototype syntax error & warning (data definition has no type or storage class) up vote 1 down vote favorite Been playing around with c trying to parse a csv file. Right now I'm trying to implement a function to check where or not a string is only a double so I can then prototype syntax error convert it. However I'm having some problems in the .h file getting "syntax error before bool" and "data definition has no type or storage class" #ifndef MSGR_H #define MSGR_H #include
cause(s) and a possible fix. Please note that you may get the same error or warning for totally different reasons. If you got one or more of the listed warnings, do NOT ignore them. fatal error C1004: unexpected end of file found error C2001:newline in constant error C2017: illegal escape sequence error C2059: syntax error : 'type' / syntax error : ';' error C2059: syntax error : '}' error C2059: syntax error : ')' error C2143: syntax error : missing ';' before 'type' error C2146: syntax error : missing ')' before identifier 'i' (at printf statements) error C2296: '%' : illegal, left operand has type 'const double ' error C2297: '%' : illegal, right operand has type 'const double ' error C2100: illegal indirection error C2106: '=' : left operand must be l-value error C2371: 'func' : redefinition; different basic types warning C4029: declared formal parameter list different from definition warning C4013: 'func' undefined; assuming extern returning int warning C4715: 'func' : not all control paths return a value warning C4700: local variable 'i' used without having been initialized warning C4047: '=' : differs in levels of indirection warning C4005: macro redefinition fatal error C1004: unexpected end of file found This usually means that you are missing a close curly bracket ( }) near the end of the file. Double check that your curly brackets are matching. error C2001: newline in constant This error is usually caused by syntax error at printf statements. Possibilities: 1) missing a close quotation ( " ) at the end of the string that you want to print. example: printf ( " string I want to print ); 2) the string is span over 2 or more lines (separated by return character, or you have hit return to break the string into 2 or more lines) example: printf ( " continue printing, don't want a wrap around on printout " ) ; fix: a) add in quotation marks printf ( " constinue printing, " " don't want to wrap around on printout " ) ; b) 2 separate printfs printf ( " continue printing, " ) ; printf ( " don't want to wrap around on printout " ) ; error C2017: illegal escape sequence Chances are you have a misplaced escape character like " \n " or " \t ". example: "\n" is placed outside quotation of a printf statement. printf ( " printing " \n ); fix: printf ( " printing \n " ); error C2059:syntax error : 'type' / syntax error : ';' The cause that I kn