Python Operationalerror Near Syntax Error
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Sqlite3 Operationalerror Near Text Syntax Error
like you, helping each other. Join them; it only takes a minute: Sign up sqlite3 “OperationalError: near ”(“: syntax error” python up vote 2 down vote favorite simply put i am trying to make a sql database table and input data into it. I have it working in a simpler way, but when I put it into sqlite3.operationalerror unable to open database file my script it results in this error. I'm hoping its something simple I missed. Any help/advice would be greatly appreciated. conn = sqlite3.connect('Data1.db') c = conn.cursor() # Create table c.execute('''CREATE TABLE Data_Output6 (date text, output6MV real)''') Averages_norm = [] for i, x in enumerate(Averages): Averages_norm.append(x*output_factor) c.execute("INSERT INTO Data_Output6 VALUES (%r,%r)" %(xdates[i],Averages_norm[-1])) conn.commit() results in the error: 57 for i, x in enumerate(Averages): 58 Averages_norm.append(x*output_factor) ---> 59 c.execute("INSERT INTO Data_Output6 VALUES (%r,%r)"%(xdates[i],Averages_norm[-1])) 60 conn.commit() 61 OperationalError: near "(": syntax error python sqlite3 share|improve this question edited May 15 '15 at 11:01 Martijn Pieters♦ 502k7513181473 asked May 15 '15 at 10:59 Ciaran 86111 So what data do you have in xdates? –Martijn Pieters♦ May 15 '15 at 11:02 3 Also, why are you using string interpolation instead of SQL parameters? –Martijn Pieters♦ May 15 '15 at 11:02 1 Try printing the statement before executing it. I'm sure you'll immediately spot the error. –Andrea Corbellini May 15 '15 at 11:57 2 You're inviting Booby Tables
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Sqlite3.operationalerror No Such Table
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Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like http://stackoverflow.com/questions/30257826/sqlite3-operationalerror-near-syntax-error-python you, helping each other. Join them; it only takes a minute: Sign up sqlite3.OperationalError: near “X”: syntax error up vote 2 down vote favorite This code: conn = connect('emails.db') curs = conn.cursor() curs.execute('''create table items (integer primary key, X, Y)''') curs.execute("INSERT INTO items (integer primary key, X, Y) VALUES ('today', 'X', 'Y')") connection.commit() returns: sqlite3.OperationalError: near "primary": http://stackoverflow.com/questions/5203703/sqlite3-operationalerror-near-x-syntax-error syntax error How come? I don't see what I'm doing wrong. The values I'm putting in there are all variables btw. python sqlite3 share|improve this question asked Mar 5 '11 at 12:05 HankSmackHood 1,05741829 The SQLite "railroad" syntax diagrams are very helpful e.g. sqlite.org/lang_createtable.html ... the top level is here: sqlite.org/lang.html –John Machin Mar 5 '11 at 12:57 add a comment| 1 Answer 1 active oldest votes up vote 6 down vote accepted Your CREATE TABLE is incorrect: it doesn't specify a name for the first ('integer primary key') column. SQLite now thinks that the field is named integer, and has no data type defined. You probably wanted to have an INTEGER PRIMARY KEY field, because that is very efficient. To do so, respect the CREATE TABLE syntax, and give it a name: CREATE TABLE items ( id INTEGER PRIMARY KEY , x DOUBLE , y DOUBLE ); As a side note: I've defined X and Y as doubles, since specifying the type is just good prac
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About http://stackoverflow.com/questions/38577182/python-sqlite3-operationalerror-near-syntax-error Us Learn more about Stack Overflow the company Business Learn more about hiring developers http://stackoverflow.com/questions/22871143/sqlite3-operationalerror-near-syntax-error or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Python sqlite3 OperationalError: near “?”: syntax error syntax error up vote 1 down vote favorite Trying to let users update column values on existing records for a specific table named "Scenario." The record being updated is identified by an index column called "Scenario_Key", unique to each instance of this class. The code I already have produces a dictionary of key, value pairs where key is the name of the column being updated and value is near syntax error the value being inserted into it. To update the sqlite database I'm trying the following: cursor.execute("""UPDATE Scenario SET ?=? WHERE Scenario_Key=?;""", (key, new_val, self.scenario_key)) But when I try to execute by clicking the "Save and Close" button, I get the following: Traceback (most recent call last): File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-tk/Tkinter.py", line 1536, in __call__ return self.func(*args) File "/Users/xxx/Documents/Consulting/DCA/Damage Control Assistant/EditScenarioWindow.py", line 91, in
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up sqlite3.OperationalError: near “,”: syntax error up vote 2 down vote favorite i tried to run an sql code (shown below) and this wont work, i get an error for the 'CREATE TABLE' line: sqlite3.OperationalError: near ",": syntax error the code is as follows: con = lite.connect('Records.db') with con: cur = con.cursor() cur.execute("CREATE TABLE Progress(Id INTEGER PRIMARY, Username STRING, Topic1 STRING, Topic2 STRING, Topic3 STRING, Topic4 STRING, 1Result STRING, 2Result STRING, 3Result STRING, 4Result STRING, TResut STRING, TCorrect INTEGER, TWrong INTEGER, TAttempted INTEGER)") cur.exectue("INSERT INTO Progress VALUES(1, 'Admin', 'Algebra', 'Number', 'Shape, Space and Measures', 'Handling Data', '100%', '100%', '100%', '100%', '100%', 10, 0, 10)") python sql sqlite sqlite3 share|improve this question asked Apr 4 '14 at 19:08 Hamzah Akhtar 130315 add a comment| 1 Answer 1 active oldest votes up vote 2 down vote accepted Two kinds of errors: Replace INTEGER PRIMARY with INTEGER PRIMARY KEY. This is what causes the error message you're seeing. After fixing that, rename identifiers starting with a number with something starting with a letter. For example, rename 1Result to e.g. Result1. share|improve this answer answered Apr 4 '14 at 19:11 laalto 91.8k23126169 Thanks, that worked!! –Hamzah Akhtar Apr 4 '14 at 19:16 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email