Java Error Unhandled Exception Type
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the unhandled exception type exception eclipse company Business Learn more about hiring developers or posting ads with us Stack Overflow unhandled exception java lang exception android Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 java unhandled exception handler million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Why do I get the “Unhandled exception type IOException”? up vote 19 down vote favorite 6 I have the
Ioexception Cannot Be Resolved To A Type
following simple code: import java.io.*; class IO { public static void main(String[] args) { BufferedReader stdIn = new BufferedReader(new InputStreamReader(System.in)); String userInput; while ((userInput = stdIn.readLine()) != null) { System.out.println(userInput); } } } And I get the following error message: ---------- 1. ERROR in io.java (at line 10) while ((userInput = stdIn.readLine()) != null) { ^^^^^^^^^^^^^^^^ Unhandled exception type IOException ---------- 1 problem (1 error)roman@roman-laptop:~/work/java$ mcedit io.java Does anybody have any ideas why? mockito when unhandled exception I just tried to simplify the code given on the sum web site (here). Did I oversimplify? java stdin readline ioexception share|improve this question asked Feb 21 '10 at 13:14 Roman 14.2k94199287 add a comment| 4 Answers 4 active oldest votes up vote 24 down vote accepted You should add "throws IOException" to your main method: public static void main(String[] args) throws IOException { You can read a bit more about checked exceptions (which are specific to Java) in JLS. share|improve this answer answered Feb 21 '10 at 13:18 Marcin 4,91352946 add a comment| up vote 31 down vote Java has a feature called "checked exceptions". That means that there are certain kinds of exceptions, namely those that subclass Exception but not RuntimeException, such that if a method may throw them, it must list them in its throws declaration, say: void readData() throws IOException. IOException is one of those. Thus, when you are calling a method that lists IOException in its throws declaration, you must either list it in your own throws declaration or catch it. The rationale for the presence of checked exceptions is that for some kinds of exceptions, you must not ignore the fact that they may happen, because their happening is quite a regular situation, not a program error. So, the compiler helps
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Unhandled Exception Type Sqlexception
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Unhandled Exception Type Unsupportedencodingexception
4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Error - Unhandled exception type Exception? up vote 2 down vote favorite I made a method which http://stackoverflow.com/questions/2305966/why-do-i-get-the-unhandled-exception-type-ioexception throws an Exception(). It causes an error - Unhandled exception type Exception public void temp(){ throw new Exception(); } However, if I replace Exception with any other Exception such as NullPointerException, i don't get any error. Why is this happening ? java exception share|improve this question asked Mar 17 '13 at 4:21 Korg 4819 1 docs.oracle.com/javase/tutorial/essential/exceptions –Brian Roach Mar 17 '13 at 4:24 Please tell me why you down http://stackoverflow.com/questions/15457486/error-unhandled-exception-type-exception voted me :-| –Korg Mar 17 '13 at 4:25 1 My guess is the downvoter thought that; checked vs unchecked exceptions is basic Java coding. You should be able to search for the answer. –Peter Lawrey Mar 17 '13 at 4:34 add a comment| 2 Answers 2 active oldest votes up vote 5 down vote accepted That's the difference between a "checked" exception and an "unchecked" exception. Anything that extends RuntimeException, including NullPointerException, are "unchecked" which means they don't need to be explicitly handled via a try/catch or by declaring that the method throw them. Checked exceptions are those that do not extend RuntimeException and must be handled either by try/catch or by declaring your method throw it. So your code fails to compile because you are not handling it either way. share|improve this answer answered Mar 17 '13 at 4:25 Blake 381110 Thanks. Link with class hierarchy diagram at - docs.oracle.com/javase/tutorial/essential/exceptions/… –Korg Mar 17 '13 at 4:27 add a comment| up vote 1 down vote I got stuck with a strange situation with this error. Namely, my Eclipse built the code without warnings, but for two of my colleagues compiler was giving this error. It took us a while to figure out, mainly because there is an easy remedy of
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn http://stackoverflow.com/questions/31095326/unhandled-exception-type-exception more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Unhandled exception type Exception up vote 0 down vote unhandled exception favorite This is a simplified class that describes my problem: public class Main { enum Test{ First(method()){ // Unhandled exception type Exception // ... }; Test(Object obj){ //... } } static Object method() throws Exception{ // ... if (someCondition){ throw new Exception(); } } } Above someCondition depends on device and some situations and I can not decide in about it now, also as you can see, I unhandled exception type do not want to catch Exception in method. java exception enums share|improve this question edited Jun 28 '15 at 1:46 asked Jun 28 '15 at 1:39 hasanghaforian 8,51243885 1 what's the question? you don't want it throw? i think java does initialization when the first time you reference to the class, so it could look like throwing exception in random places. –HuStmpHrrr Jun 28 '15 at 1:44 @HuStmpHrrr It is a compile error. –hasanghaforian Jun 28 '15 at 1:45 oh, yeah. since it's checked exception so it's not going to compile. you need to wrap it over a RuntimeException to allow it throw silently. –HuStmpHrrr Jun 28 '15 at 1:47 add a comment| 2 Answers 2 active oldest votes up vote 0 down vote accepted Yes. It is a compilation error. No. There is no special syntax to deal with this. I do not want to catch Exception in method. Unfortunately if you throw a checked exception, it has to be caught further up the call stack. That is a fundamental design principal for the Java language, and one that the compiler enforces strictly. In this, case there is no way to catch the checked exception. Hence