Mysql Error Code 1005 Error No 150
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or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow error 1005 archeage Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up MySQL Foreign Key Error 1005 errno 150 up error 1005 access denied vote 31 down vote favorite 8 I'm doing a small DataBase with MySQL Workbench. I have a main table, called "Immobili", which has a Primary Key composed by four columns: (Comune, Via, Civico, Immobile). Now, I also have three other tables, wich have the same primary key (Comune, Via, Civico, Immobile), but these fields are also referenced to the table Immobili. First question: Can I make a
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Primary Key that is also a Foreign Key? Second Question: When I try to export the changes it says: Executing SQL script in server # ERROR: Error 1005: Can't create table 'dbimmobili.condoni' (errno: 150) CREATE TABLE IF NOT EXISTS `dbimmobili`.`Condoni` ( `ComuneImmobile` VARCHAR(50) NOT NULL , `ViaImmobile` VARCHAR(50) NOT NULL , `CivicoImmobile` VARCHAR(5) NOT NULL , `InternoImmobile` VARCHAR(3) NOT NULL , `ProtocolloNumero` VARCHAR(15) NULL , `DataRichiestaSanatoria` DATE NULL , `DataSanatoria` DATE NULL , `SullePartiEsclusive` TINYINT(1) NULL , `SullePartiComuni` TINYINT(1) NULL , `OblazioneInEuro` DOUBLE NULL , `TecnicoOblazione` VARCHAR(45) NULL , `TelefonoTecnico` VARCHAR(15) NULL , INDEX `ComuneImmobile` (`ComuneImmobile` ASC) , INDEX `ViaImmobile` (`ViaImmobile` ASC) , INDEX `CivicoImmobile` (`CivicoImmobile` ASC) , INDEX `InternoImmobile` (`InternoImmobile` ASC) , PRIMARY KEY (`ComuneImmobile`, `ViaImmobile`, `CivicoImmobile`, `InternoImmobile`) , CONSTRAINT `ComuneImmobile` FOREIGN KEY (`ComuneImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`ComuneImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `ViaImmobile` FOREIGN KEY (`ViaImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`ViaImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `CivicoImmobile` FOREIGN KEY (`CivicoImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`CivicoImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `InternoImmobile` FOREIGN KEY (`InternoImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`InternoImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE ) ENGINE = InnoDB Showing the Engine Status: Error in foreign key constraint of table dbimmobili/valutazionimercato:
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Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up MySQL ERROR 1005: Can't create table (errno: 150) up vote 6 down http://stackoverflow.com/questions/4063141/mysql-foreign-key-error-1005-errno-150 vote favorite I am trying to create the following table create table messaInScena ( data date, ora time, spazio varchar(20), spettacolo varchar(40), postiDisponibili smallint, prezzoIntero decimal(5,2), prezzoRidotto decimal(5,2), prezzoStudenti decimal(5,2), primary key (data, ora, spazio), foreign key (spazio) references spazio(nome) on update cascade on delete set null, foreign key (spettacolo) references spettacolo(titolo) on update cascade on delete set null, constraint RA3_1 check (postiDisponibili >= 0) ) ; but I http://stackoverflow.com/questions/17812616/mysql-error-1005-cant-create-table-errno-150 get the following error: Error Code: 1005 Can not create table 'teatrosql.messainscena' (errno: 150) The tables that are referenced by foreign keys are: create table spazio ( nome varchar(20) primary key, indirizzo varchar(40) not null, pianta varchar(20), capienza smallint ); create table spettacolo ( titolo varchar(40) primary key, descrizione LONGBLOB, annoProduzione char(4) ); I have already verified that the fk are unique and that there are no typos (but given a control also you that you never know :D). As you can see the reference fields are primary keys. between fields and fk reference types and dimensions coincide .. where am I wrong?? the the other tables of DB create table teatro ( nome varchar(20) primary key, telefono varchar(15), fax varchar(15), indirizzo varchar(40) not null, email varchar(30), url varchar(30) ); create table biglietteria ( nome varchar(20) primary key, indirizzo varchar(40) not null, email varchar(30), telefono varchar(15), teatro varchar(20), foreign key (teatro) references teatro(nome) on update cascade on delete set null ); create table orario ( biglietteria varchar(20), giorno varchar(10), inizio time, fine time, primary key(biglietteria, giorno, inizio), foreign key (biglietteria) references biglietteria(nome) on update cascade on delete cascade ); create table notizia ( data date, ora time, oggetto varchar(100), testo LONGBLOB, primary key(data, ora, o
Communication Skills Training Interpersonal Skills Training Blog About Blog Troy Fawkes / Archives / Solved: MySQL ERROR 1005: Can't create table (errno: 150) (Foreign Key) Nov 27 Solved: MySQL ERROR 1005: Can't create table (errno: 150) (Foreign Key) November 27, https://www.troyfawkes.com/solved-mysql-error-1005-cant-create-table-errno-150/ 2011 Troy Fawkes 8 Comments Archives Share on Facebook Share 0 Share on TwitterTweet http://dba.stackexchange.com/questions/80435/mysql-create-table-shows-error-1005-errno-150 0 Share on Google Plus Share 0 Share on Pinterest Share 0 Share on LinkedIn Share 0 This is another stupid error. It has to do with trying to successfully set foreign keys in MySQL. ERROR 1005: Can't create table (errno: 150) Great, that's fantastic. Here's an example of where this error will occur. CREATE TABLE main(
id error 1005 INT UNSIGNED NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id)
);
CREATE TABLE other(
id INT UNSIGNED NOT NULL AUTO_INCREMENT,
main_id INT NOT NULL,
PRIMARY KEY(id),
FOREIGN KEY(main_id) REFERENCES main(id)
); So I'm trying to make the table "other" reference the table "main" through the foreign key "main_id" and, if you try it, it'll throw an Error 150. Want the solution? The foreign key "main_id" has to have the exact same type as the primary key error code 1005 that it references. In the example, "main_id" in the table "other" has the type INT NOT NULL while "id" in the table "main" has the type "INT UNSIGNED NOT NULL" and also AUTO_INCREMENT, but that isn't something we have to worry about. To make things incredibly clear, here's the working example. CREATE TABLE main( id INT UNSIGNED NOT NULL AUTO_INCREMENT, PRIMARY KEY(id) ); CREATE TABLE other( id INT UNSIGNED NOT NULL AUTO_INCREMENT, main_id INT UNSIGNED NOT NULL, PRIMARY KEY(id), FOREIGN KEY(main_id) REFERENCES main(id) ); To solve ‘MySQL ERROR 1005: Can't create table (errno: 150)‘ you likely just have to ensure that your foreign key has the exact same type as the primary key. Hope it helps. Share on Facebook Share 0 Share on TwitterTweet 0 Share on Google Plus Share 0 Share on Pinterest Share 0 Share on LinkedIn Share 0 Facebook Twitter Tumblr Pinterest Google+ LinkedIn E-Mail About The Author My name is Troy Boileau but I go by Troy Fawkes. I'm a digital marketer working in Toronto. On top of that, my passions include social skills, networking and dating; subjects that I've been semi-professionally involved with for almost five years. Top LinksGet The Conversation Handbook How To Improve Conversation Skills How to Speak Clearly & Confidently Communication Skills Training Categories Archives Development Romance SEO S
log in tour help Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Database Administrators Questions Tags Users Badges Unanswered Ask Question _ Database Administrators Stack Exchange is a question and answer site for database professionals who wish to improve their database skills and learn from others in the community. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top Mysql Create table shows ERROR 1005 errno 150 up vote 0 down vote favorite I am trying to make a junction table, but I getting a ERROR 1005 errno 150 CREATE TABLE 61furiousFistPokemon( cardNumber int NOT NULL PRIMARY KEY, pokemonName VARCHAR(12), type VARCHAR(10), stage VARCHAR(10), evolvesFrom VARCHAR(12), HP INT, retreatCost INT, weakness VARCHAR(10), weaknessAmount VARCHAR(5), resistance VARCHAR(5), resistanceAmount VARCHAR(5) ); CREATE TABLE cardTags ( tagId int NOT NULL AUTO_INCREMENT PRIMARY KEY, tagName VARCHAR(60) NOT NULL ); CREATE TABLE 61furiousFistPokemonTags ( tagId int NOT NULL AUTO_INCREMENT PRIMARY KEY, pokemonCardNumber int, tagName VARCHAR(60), FOREIGN KEY (pokemonCardNumber) REFERENCES 61furiousFistPokemon(cardNumber), FOREIGN KEY (tagName) REFERENCES cardTags(tagName) ); Any help would be greatly appreciated. mysql innodb foreign-key table share|improve this question edited Oct 17 '14 at 15:23 RolandoMySQLDBA 108k15139276 asked Oct 17 '14 at 3:43 user50479 add a comment| 3 Answers 3 active oldest votes up vote 1 down vote tagName column in table cardTags is not defined as primary key and you are declaring foreign key FOREIGN KEY (tagName) REFERENCES cardTags(tagName). share|improve this answer answered Oct 17 '14 at 8:13 Nawaz Sohail 611314 Although you did not provide a solution, +1 for revealing root cause. –RolandoMySQLDBA Oct 17 '14 at 15:19 add a comment| up vote 0 down vote Very often it happens, when the foreign key and the reference key don't have same type or same length. Click here for more details. share|improve this answer answered Oct 17 '14 at 7:30 Musakkhir Sayyed 240314 add a comment| up vote 0 down vote Here is the quick fix: Just add a UNIQUE KEY on tagName in the cardTags table SAMPLE SCRIPT DROP DATABASE IF EXISTS te