Mysql Error No 1005
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other. Join them; it only takes a minute: Sign up MySQL Foreign Key Error 1005 errno 150 up vote 31 down vote favorite 8 I'm doing a small DataBase with MySQL Workbench. I have a main table, called "Immobili", which has a Primary Key composed by four columns: (Comune, Via, Civico, Immobile). Now, I also have three other
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tables, wich have the same primary key (Comune, Via, Civico, Immobile), but these fields are also referenced to the table Immobili. First question: Can I make a Primary Key that is also a Foreign Key? Second Question: When I try to export the changes it says: Executing SQL script in server # ERROR: Error 1005: Can't create table 'dbimmobili.condoni' (errno: 150) CREATE TABLE IF NOT EXISTS `dbimmobili`.`Condoni` ( `ComuneImmobile` VARCHAR(50) NOT NULL , `ViaImmobile` VARCHAR(50) NOT NULL , `CivicoImmobile` VARCHAR(5) NOT NULL , `InternoImmobile` VARCHAR(3) NOT NULL , `ProtocolloNumero` VARCHAR(15) NULL , `DataRichiestaSanatoria` DATE NULL , `DataSanatoria` DATE NULL , `SullePartiEsclusive` TINYINT(1) NULL , `SullePartiComuni` TINYINT(1) NULL , `OblazioneInEuro` DOUBLE NULL , `TecnicoOblazione` VARCHAR(45) NULL , `TelefonoTecnico` VARCHAR(15) NULL , INDEX `ComuneImmobile` (`ComuneImmobile` ASC) , INDEX `ViaImmobile` (`ViaImmobile` ASC) , INDEX `CivicoImmobile` (`CivicoImmobile` ASC) , INDEX `InternoImmobile` (`InternoImmobile` ASC) , PRIMARY KEY (`ComuneImmobile`, `ViaImmobile`, `CivicoImmobile`, `InternoImmobile`) , CONSTRAINT `ComuneImmobile` FOREIGN KEY (`ComuneImmobile` ) REFERENCES `dbimmobili`.`Immobile` (`ComuneImmobile` ) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `ViaImmobile` FOREIGN KEY (`ViaImmobile` ) REFERENCES `dbimmobili`.`Immobile` (
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Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, error 1005 cloudflare just like you, helping each other. Join them; it only takes a minute: Sign up MySql Error Code: 1005 Can't create table errno: 150 up vote 1 down vote favorite 2 MySql workbench reports that my syntax http://stackoverflow.com/questions/4063141/mysql-foreign-key-error-1005-errno-150 is error free. I can't figure out what's wrong with my database. Any ideas? CREATE TABLE `users` ( `id` INT NOT NULL AUTO_INCREMENT PRIMARY KEY, `login` VARCHAR(35) NOT NULL UNIQUE, `pass` VARCHAR(35) NOT NULL, `fname` VARCHAR(35), `lname` VARCHAR(35), `gender` VARCHAR(1), `phone` VARCHAR(12), `appointments` INT, `groups` INT(1) NOT NULL, FOREIGN KEY (`groups`) references `groups`(`gnumber`) ); CREATE TABLE `groups` ( `gname` VARCHAR(25) NOT NULL, `gnumber` INT(1) NOT NULL ); INSERT INTO `groups`(`gname`, `gnumber`) values ('user', 0); INSERT http://stackoverflow.com/questions/19880103/mysql-error-code-1005-cant-create-table-errno-150 INTO `groups`(`gname`, `gnumber`) values ('admin', 1); INSERT INTO `users`(`login`, `pass`, `groups`) values ('admin', 'secret', 1); mysql database syntax share|improve this question edited Nov 9 '13 at 17:54 fthiella 32.9k114372 asked Nov 9 '13 at 17:50 user2973522 614 1 Reverse the order of table creation –Sashi Kant Nov 9 '13 at 17:57 add a comment| 1 Answer 1 active oldest votes up vote 2 down vote accepted Error Code 150 means: If the error message refers to error 150, table creation failed because a foreign key constraint was not correctly formed. To fix this, simply create the groups Table before the users Table. Edit: You'll also need to make gnumber a key in the groups table for this to work. CREATE TABLE `groups` ( `gname` varchar(25) NOT NULL, `gnumber` int(1) NOT NULL, PRIMARY KEY (`gnumber`) ); I don't know whether you want it to be the primary key, you'll have to play around with the available settings but this works for me locally insofar that I can create the tables and execute the inserts. share|improve this answer edited Nov 9 '13 at 18:26 answered Nov 9 '13 at 17:56 Nikolas Grottendieck 2,4281918 I do so and it will create groups fine, but I get the same error when creating users. –user2973522 Nov 9 '13 at 18:15 @user2
log in tour help Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn http://dba.stackexchange.com/questions/80435/mysql-create-table-shows-error-1005-errno-150 more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Database Administrators Questions Tags Users Badges Unanswered Ask Question _ Database Administrators Stack Exchange is a question https://www.quora.com/MySQL-Workbench-How-can-I-solve-the-General-error-code-1005-Cant-create-table-errno-150-error-message and answer site for database professionals who wish to improve their database skills and learn from others in the community. Join them; it only takes a minute: Sign up Here's how it works: Anybody error 1005 can ask a question Anybody can answer The best answers are voted up and rise to the top Mysql Create table shows ERROR 1005 errno 150 up vote 0 down vote favorite I am trying to make a junction table, but I getting a ERROR 1005 errno 150 CREATE TABLE 61furiousFistPokemon( cardNumber int NOT NULL PRIMARY KEY, pokemonName VARCHAR(12), type VARCHAR(10), stage VARCHAR(10), evolvesFrom VARCHAR(12), HP INT, retreatCost INT, error 1005 iphone weakness VARCHAR(10), weaknessAmount VARCHAR(5), resistance VARCHAR(5), resistanceAmount VARCHAR(5) ); CREATE TABLE cardTags ( tagId int NOT NULL AUTO_INCREMENT PRIMARY KEY, tagName VARCHAR(60) NOT NULL ); CREATE TABLE 61furiousFistPokemonTags ( tagId int NOT NULL AUTO_INCREMENT PRIMARY KEY, pokemonCardNumber int, tagName VARCHAR(60), FOREIGN KEY (pokemonCardNumber) REFERENCES 61furiousFistPokemon(cardNumber), FOREIGN KEY (tagName) REFERENCES cardTags(tagName) ); Any help would be greatly appreciated. mysql innodb foreign-key table share|improve this question edited Oct 17 '14 at 15:23 RolandoMySQLDBA 108k15139276 asked Oct 17 '14 at 3:43 user50479 add a comment| 3 Answers 3 active oldest votes up vote 1 down vote tagName column in table cardTags is not defined as primary key and you are declaring foreign key FOREIGN KEY (tagName) REFERENCES cardTags(tagName). share|improve this answer answered Oct 17 '14 at 8:13 Nawaz Sohail 611314 Although you did not provide a solution, +1 for revealing root cause. –RolandoMySQLDBA Oct 17 '14 at 15:19 add a comment| up vote 0 down vote Very often it happens, when the foreign key and the reference key don't have same type or same length. Click here for more details. share|improve this answer answered Oct 17 '14 at 7:30 Musakkhir Sayyed 240314 add a comment| up vote 0 down vote Here is the quick fix