Excel Vba Find Type Mismatch Error
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Excel Vba Type Mismatch Error Handling
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Excel Vba Type Mismatch Array
mismatch while using FIND function up vote 3 down vote favorite I am using the below code snippet to retrieve a value from my "Data Summary" sheet and find that data in "QG Summary" sheet, if there exists a match I retrieve the data stored in the first column of "QG Summary" sheet for the row identified by my aCell variable. Dim str1 As String
Excel Vba Type Mismatch Date
Dim aCell As Range str1 = Worksheets("Data Summary").Cells(aCell.Row, 3).Value If (str1 <> "") Then Set aCell = Worksheets("QG Summary").Columns(3).Find(What:=str1 _ , LookIn:=xlValues, LookAt:=xlWhole, SearchOrder:=xlByRows, _ SearchDirection:=xlNext, MatchCase:=False) If Not aCell Is Nothing Then str1 = Worksheets("QG Summary").Cells(aCell.Row, 1).Value End If End If This code works fine for all case except for cases where my variable str1 has a big value (326 characters). When my str1 variable comes across a big value, this code breaks with a Runtime error '13': Type mismatch. Why? vba share|improve this question edited Sep 23 '13 at 18:18 Jean-Francois Corbett 23.9k1678113 asked Sep 23 '13 at 18:09 user2808276 1612 On what line does the error occur? –Jean-Francois Corbett Sep 23 '13 at 18:18 Yeah string longer than 255 characters will give that problem. Let me search if there is an explanation or bug report for this. –Siddharth Rout Sep 23 '13 at 18:23 2 Perhaps this can explain it :) –Siddharth Rout Sep 23 '13 at 18:27 Jean, The error occurs while executing "Find". –user2808276 Sep 24 '13 at 16:38 Thanks Siddharth for your help. I think the work ar
Forums Excel Questions Type Mismatch from VBA .Find Results 1 to 10 of 10 Type Mismatch from VBA .FindThis is a discussion on Type Mismatch from VBA .Find within excel vba type mismatch string the Excel Questions forums, part of the Question Forums category; This is likely
Excel Find Type Mismatch
Y.A. pathetically useless/misleading/incorrect error message. Anyone know what the real problem might be? XL03 on XP. Run-time ... LinkBack excel vba type mismatch LinkBack URL About LinkBacks Bookmark & Share Digg this Thread!Add Thread to del.icio.usBookmark in TechnoratiTweet this thread Thread Tools Show Printable Version Display Linear Mode Switch to Hybrid Mode Switch to http://stackoverflow.com/questions/18965971/runtime-error-13-type-mismatch-while-using-find-function Threaded Mode Jan 16th, 2007,05:17 PM #1 Gates Is Antichrist Board Regular Join Date Aug 2002 Location Earth (on working assignment from Hell) Posts 1,961 Type Mismatch from VBA .Find This is likely Y.A. pathetically useless/misleading/incorrect error message. Anyone know what the real problem might be? XL03 on XP. Run-time error '13': Type Mismatch Code: dim c as Range ... Set c = .Find(what:="LIQ", _ http://www.mrexcel.com/forum/excel-questions/242660-type-mismatch-visual-basic-applications-find.html LookIn:=xlFormulas, _ LookAt:=xlPart, _ SearchOrder:=xlByRows, _ SearchDirection:=xlNext, _ After:=ActiveCell, _ MatchCase:=False) ActiveCell is a single cell on an unhidden sheet - cell A279. I can Control-F at this point in Excel, and it finds "LIQ" just fine. Now here comes the queer part. At least at THIS moment, if activecell is on rows 1 through 26, NO PROBLEM. If it's on rows 28+, death message shown above. J27 is the point where death begins. I've cleared i27:k27 and there's nothing notable there. L279 is the end of UsedRange. Since this clearly is a bug, I'll really reach far now: there is a "drawing symbol" (a big "right brace") that begins at J34, if that's a clue. (I'm mystified as to what worksheet cells are connected to big drawing symbols like this.) If anyone recognizes this and can "succint-ize" it down to a simple reproducible example, that would be useful too, if we need to go to Usenet on this. Thanks. Share Share this post on Digg Del.icio.us Technorati Twitter Outlook 2007: Try to find undo and redo now in the menus and icons. I'm not kidding. Microsoft, you CLUELESS ***TARDS. Reply With
Way | Trading Add-ins For Excel | Convert Excel Into Calculating Web Pages Excel Web Pages | Produce Clean Efficient VBA Code Every Time | http://www.ozgrid.com/forum/showthread.php?t=60112 Build Automated Trading Models In Excel | Excel Web Pages | https://bytes.com/topic/access/answers/947783-type-mismatch-error13-find-string-excel-sheet-store-cell-address-array Excel Video Training Forum New Posts FAQ Calendar Forum Actions Mark Forums Read Quick Links Today's Posts What's New? Advanced Search Forum HELP FORUMS Excel General Find Method: Type Mismatch Error Excel Training / Excel Dashboards Reports If this is your first visit, be sure to check out the FAQ type mismatch by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. If you don't like Google AdSense in the posts, register or log in above. Click here to view the relaunched Ozgrid newsletter. Results 1 to excel vba type 4 of 4 Thread: Find Method: Type Mismatch Error Thread Tools Show Printable Version Search Thread Advanced Search November 14th, 2006 #1 KathyC View Profile View Forum Posts I agreed to these rules Join Date 23rd October 2005 Location NJ Posts 16 Find Method: Type Mismatch Error Hi.... I'm attempting to do a backwards search, but I keep getting a mismatch error on the Find function and don't know why. VB: formstring = "=MIN(V$15:INDIRECT(AE$25))" ' min(first:last) Range("H3").Formula = formstring Dim foundcell As Range Range("V616").Select Set foundcell = Range("V:V").Find(What:=lowcagr, after:=ActiveCell, LookIn:=xlValues, LookAt _ :=xlPart, SearchOrder:=xlByRows, SearchDirection:=xlPrevious, MatchCase _ :=False, SearchFormat:=False) LR3 = foundcell.Row The formula in H3 is =MIN(V$15:INDIRECT(AE$25)) and it's value shows up as: -2.62130736985065E-02. The cell is formatted as a percentage with 2 decimals. The variable lowcagr is defined as double and it's value shows up as -2.62130736985065E-02 LR3 is defined as double. The values in column V were calculated by : ActiveCell.Value = ((tempprice / Fromprice) ^ (1 / nyears)) - 1 where tempprice, Fromprice, and nyears are all defined as double. The column V is formatted as number with 4 decim
address in array + Ask a Question Need help? Post your question and get tips & solutions from a community of 418,548 IT Pros & Developers. It's quick & easy. Type Mismatch(Error13): find a string in excel sheet and store cell address in array P: 3 andy1989 I am trying to find a string in excel sheet and store the string cell address in an array. This string appears several times. By storing every cell address where the string is located, im checking if the string is located one below another (in row) or one beside another (in column). But I am having a type mismatch error 13, please someone help me. Code is as following: Sorry for such a long code: Expand|Select|Wrap|Line Numbers SubFind() Dimfind1,find2,find3,find4AsRange DimFirstFoundAsString DimiAsInteger Dimy(),z()AsLong i=1 Application.FindFormat.Clear Setfind1=Cells.Find(What:=Trim("Amplifiertype"),_ After:=Cells(1,1),_ LookIn:=xlValues,_ LookAt:=xlPart,_ SearchOrder:=xlByRows,_ SearchDirection:=xlNext,_ MatchCase:=False,_ SearchFormat:=False) IfNotfind1IsNothingThen 'iffound,rememberlocation FirstFound=find1.Address 'y(i)=cl.Row 'z(i)=cl.Column Do find1.Font.Bold=True find1.Interior.ColorIndex=3 Setfind1=Cells.FindNext(After:=find1) ReDimPreservey(i) ReDimPreservez(i) y(i)=find1.Row z(i)=find1.Column i=i+1 LoopUntilFirstFound=find1.Address EndIf Fori=1ToUBound(y) If((y(i)=y(i+1))&(z(i+1)-z(i)=1))Then MsgBox"Horizontal" EndIf If((z(i)=z(i+1))&(y(i+1)-y()=1))Then MsgBox"Vertical" Nexti EndSub Some one let me know even if there is a better solution. Thank you. Mar 14 '13 #1 Post Reply Share this Question 5 Replies Expert Mod 2.5K+ P: 4,994 zmbd andy1989: Your first step is to put a "Stop" command at line #7 and step thru your code until you find which line it is erroring out on. Then take a look at your data and that line... If you like, I can merge your two posts and delete the duplicate code. Simply stating that your code "doesn't work," and posting code that appears to have had very little if any troubleshooting performed, and expecting someone to help doesn't usually result in much of an answer and may result in your thread being deleted. Mar 14 '13 #2 reply P: 3 andy1989 yeah sure zmbd.. nd thanks for your reply. Mar 14 '13 #3 reply Expert Mod 2.5K+ P: 4,994 zmbd Just noticed line 6: Dim y(), z() As Long Depending on which version of VB/VBA you are using, this might be your issue. With the latest release, that construct is nolonger allowed in that what you get is "y()" as a variant and "z()" as Long type cast. Instead the new construct requires the explicit declaration so that you now have: Dim y() As Long, z() As Long You should make that change. Sorry I missed tha