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Vba Error 2015 Vlookup

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Excel Error 2015 Evaluate

vote 1 down vote favorite I have to following code snippet ... Public Sub FindText(path As String, file As String) Dim Found As Range myText = "test(" MacroBook = ActiveWorkbook.Name ' Open the File Workbooks.Open path & file, ReadOnly:=True, UpdateLinks:=False For Each ws In Workbooks(file).Worksheets With ws Set Found = .UsedRange.Find(What:=myText, LookIn:=xlFormulas, _ LookAt:=xlPart, MatchCase:=False) If Not Found Is Nothing Then ' do stuff ' ... I see error 2029 vba evaluate in the debugger that Found contains Error 2015! The sheet contains the text I want in the formula. Any ideas why I'm getting the error? Thanks excel vba excel-vba find share|improve this question edited Feb 25 '14 at 13:15 asked Feb 25 '14 at 12:22 Rueful Rabbit 3127 1 it's because your formula in the sheet returns #VALUE! error. You can handle it using IsError: If Not IsError(Found) Then –simoco Feb 25 '14 at 12:36 is this a sub or function? please, show complete code. –KazimierzJawor Feb 25 '14 at 12:43 1 Bravo Simoco, nice catch! –Rueful Rabbit Feb 25 '14 at 13:21 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted As follow up from comments to the Q, Error 2015 occurs because your formula in the sheet returns #VALUE! error. You can handle it using IsError: If Not Found Is Nothing Then If Not IsError(Found) Then ' do sth End If End If share|improve this answer edited Feb 25 '14 at 16:41 answered Feb 25 '14 at 13:41 simoco 27.4k93552 is there a way of finding which formula is giving the error? –user3540466 Dec 30 '1

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack excel vba error 2029 Overflow the company Business Learn more about hiring developers or posting ads with us vba evaluate function Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a excel vba vlookup community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up VBA application.match error 2015 up vote 1 down vote favorite In my Main procedure I http://stackoverflow.com/questions/22014093/excel-vba-find-string-error-2015 want to write a quick if-statement which checks whether the user has made a valid input (user chooses number of project from list of data, see attached screenshot). For that I am checking whether the project number is not part of the list of projects. If that is true, an error message is displayed; if not then a number of other procedures are called. For some reason though I get error http://stackoverflow.com/questions/14188010/vba-application-match-error-2015 2015 when I run it, which means that the if-statement is always true, even on correct user entries. Can someone help me understand the error please? The project number input is a named cell called "IdSelect" and is on a sheet called "Invoice" The data against which this input is checked is on a sheet called "Input" The data is stored in column B and called "ProjectList" Code below (note: I have tried pasting it 5 times but the formatting still won't work this time for some reason - any idea what that could be? The code is properly formatted. Sorry for the messy display; if anyone can tell me what that problem might I would be very grateful!) Sub Main() 'Turn off screen updating Application.ScreenUpdating = False 'Define variable for currently active cell to reactivate it afterwards Dim OldActiveSheet As Object Dim OldActiveCell As Object Dim i As Integer Dim ProjectList As Range Set OldActiveSheet = ActiveSheet Set OldActiveCell = ActiveCell 'If-statement to check whether project number is valid or not Worksheets("Invoice").Activate 'Print to Immediate Window to check value - remove later Debug.Print Range("IdSelect").Value If IsError(Application.Match(Range("IdSelect").Value, "ProjectList", 0)) Then 'Print to Immediate Window to check value - remove later Debug.Print Application.Match(Range("IdSelect").Value, Worksheets("Input").Range("ProjectList"), 0) MsgBox "Invalid Choice: Project with

Forum Microsoft Office Application Help - Excel Help forum Excel Formulas & Functions Workaround for Error 2015 when function too long using Application.Evaluate? To get replies by our experts at nominal charges, follow this link to buy points and post http://www.excelforum.com/showthread.php?t=1025551 your thread in our Commercial Services forum! Here is the FAQ for this forum. + Reply to Thread Results 1 to 4 of 4 Workaround for Error 2015 when function too long using Application.Evaluate? Thread Tools Show Printable Version Subscribe to this Thread… Rate This Thread Current Rating ‎ Excellent ‎ Good ‎ Average ‎ Bad ‎ Terrible Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 07-18-2014,11:49 AM #1 error 2015 jprealini View Profile View Forum Posts Registered User Join Date 07-11-2014 Location Buenos Aires MS-Off Ver 2010 Posts 16 Workaround for Error 2015 when function too long using Application.Evaluate? Hi... I have been trying to find a solution for this error with no luck. I am executing a PERCENTILE function using a custom function in vba. I am passing the parameters (different ranges to filter data and return the array that will be excel vba error used to calculate the percentile). The problem is that sometimes, depending on the parameters, the function gets too long. I already learned that Error 2015 is caused because the function string it longer than 255 characters, and Application.Evaluate has that limit. Now... is there a simple workaround for this? Thanks Register To Reply 07-18-2014,12:52 PM #2 ben_hensel View Profile View Forum Posts Forum Expert Join Date 01-26-2012 Location Rocester, New York, USA MS-Off Ver Excel 2007:10 Posts 1,502 Re: Workaround for Error 2015 when function too long using Application.Evaluate? Isn't Error 2015 caused by incorrectly formatted dates, not an over-long string? So in that case you should check the format of your input. Well, if it's just that your string reference is too long, couldn't you slice it up into two+ nested references? Register To Reply 07-18-2014,03:50 PM #3 jprealini View Profile View Forum Posts Registered User Join Date 07-11-2014 Location Buenos Aires MS-Off Ver 2010 Posts 16 Re: Workaround for Error 2015 when function too long using Application.Evaluate? Thank you Ben_Hensel... I am possitive this has to do with string length, since I am creating a string variable to assign it the function, and then pass it to the ActiveSheet.Evaluate method, and when I check the variable, the function is truncated always at 251 c

 

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