Excel Vba Application.evaluate Error 2015

formulas as strings and have Excel VBA compute them for you. Only recently I discovered that some of the cells in a workbook contained #VALUE? instead of a sound value. After some investigation I found error 2015 vba out that, without raising any error at application level (in VBA), the Application.Evaluate function

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failed consistently with this error whenever a particular condition occurred. This condition is related to limits in the underlying software layer

Excel Error 2015 Evaluate

of Excel, the one that runs Application.Evaluate. Apparently this particular error occurs when the parsed function returns a string value having a length above 255 characters. As long as the length of the string is

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less than or equal to 255 characters, the return value is the desired string. Above 255 characters, the function "crashes". In my case, I was not immediately attended on this error because I used a Variant to store the returned value from Application.Evaluate (sample code): Dim vValue As Variant vValue = Application.Evaluate("GetData()") ' Error 2015 saved in vValue if GetData returns 255+ characters ActiveCell.Value = vValue If I would have application.evaluate vba used a String to store the value, I would probably have gotten a "Runtime Error 13 - Type Mismatch" with Excel booming out of my routine without any debugging possibility (sample code): Dim sValue As String sValue = Application.Evaluate("GetData()") ' Run-time error if GetData() returns 255+ characters ActiveCell.Value = sValue To catch problems, I now completed code with an If statement (sample code): Dim vValue As Variant vValue = Application.Evaluate("GetData()") If (VBA.VarType(vValue) = vbError) Then ActiveCell.Value = "String Overflow on GetData()" Else ActiveCell.Value = vValue End If There seem to be more Excel functions that suffer from this 255 character limit, but could not establish which. For the moment, I will apply some workarounds until it gets solved by Microsoft. Dutch Like this:Like Loading... Related Comments (3) 3 Comments » Thanks for this, I was passing through a #value error as I was resetting a combo control Cell link to 0, by defining the field as String trapped the error allowing the "on error goto XXXX" to work as required Comment by John Allott -- June 21, 2012 @ 11:42 pm | Reply The error trapping in your post was very helpful for me, although for a different error type. This line of code was my aid: If (VBA.VarType(v

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow iserror vba the company Business Learn more about hiring developers or posting ads with us Stack vba error handling Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Excel VBA failure of repeated Evaluate method up vote 2 down vote favorite I have written a https://dutchgemini.wordpress.com/2009/08/07/error-2015-using-application-evaluate-in-excel-vba/ little tool in VBA that charts a function you pass it as a string (e.g. "1/(1+x)" or "exp(-x^2)"). I use the built-in Evaluate method to parse the formula. The nub of it is this function, which evaluates a function of some variable at a given value: Function eval(func As String, variable As String, value As Double) As Double eval = Evaluate(Replace(func, variable, value)) End Function This works fine, e.g. eval("x^2, "x", 2) http://stackoverflow.com/questions/23718381/excel-vba-failure-of-repeated-evaluate-method = 4. I apply it element-wise down an array of x values to generate the graph of the function. Now I want to enable my tool to chart the definite integral of a function. I have created an integrate function which takes an input formula string and uses Evaluate to evaluate it at various points and approximate the integral. My actual integrate function uses the trapezoidal rule, but for simplicity's sake let's suppose it is this: Function integrate(func As String, variable As String, value As Double) As Double integrate = value * (eval(func, variable, 0) + eval(func, variable, value)) / 2 End Function This also works as expected, e.g. integrate("t", "t", 2) = 2 for the area of the triangle under the identity function. The problem arises when I try to run integrate through the charting routine. When VBA encounters a line like this eval("integrate(""t"",""t"",x)", "x", 2) then it will stop with no error warning when Evaluate is called inside the eval function. (The internal quotes have to be doubled up to read the formula properly.) I expect to get the value 2 since Evaluate appears to try and evaluate integrate("t", "t", 2) I suspect the problem is with second call on Evaluate inside integrate, but I've been going round in circles trying t

Forum Microsoft Office Application Help - Excel Help forum Excel Programming / VBA / Macros Error 2015 with Application.Evaluate To get replies by our experts at nominal charges, follow this link to buy points and post your thread in our http://www.excelforum.com/showthread.php?t=548937 Commercial Services forum! Here is the FAQ for this forum. + Reply to Thread Results 1 to 4 of 4 Error 2015 with Application.Evaluate Thread Tools Show Printable Version Subscribe to this Thread… Mark this thread as http://www.pcreview.co.uk/threads/error-2015-with-application-evaluate.2584009/ solved… Rate This Thread Current Rating ‎ Excellent ‎ Good ‎ Average ‎ Bad ‎ Terrible Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 06-06-2006,09:10 AM #1 Jeff Guest Error 2015 with Application.Evaluate Hello, error 2015 If someone could help me correct my VBA procedure. I'm lost and I don't know how to fix it. I get #value error. Here's an example of my spreadsheet: A B C D E F G 20 6 F E Escada 1,940 495,866 Here's my VBA procedure: Dim mtchValue As Variant Dim getvalue As Variant Dim sh As String Dim fname As Variant fname = Application.GetOpenFilename If fname = False Then Exit Sub excel vba application.evaluate 'cancel End If sh = MakeReferenceNicer(fname) Workbooks.Open Filename:=fname mtchValue = ("MATCH(1,(" & sh & "A1:A10000=20)*" & _ "(" & sh & "B1:B10000=6)*" & "(" & sh & _ "C1:C10000=""F"")*" & "(" & sh & _ "E1:E10000=""Escada""),0)") If Not IsError(mtchValue) Then getvalue = Application.Evaluate("Index(" & sh & "F1:F10000" & mtchValue & ")") End If Range("S1").Select ActiveCell.Value = getvalue End Sub Function MakeReferenceNicer(fname) As String 'taking '"C:\My Documents\excel\book5.xls" 'shooting for: '"'C:\My Documents\excel\[book5.xls]May'!" Dim iCtr As Long Dim myStr As String For iCtr = Len(fname) To 1 Step -1 If Mid(fname, iCtr, 1) = "\" Then 'found that last backslash myStr = "'" & Left(fname, iCtr) & _ "[" & Mid(fname, iCtr + 1) & "]May'!" Exit For End If Next iCtr MakeReferenceNicer = myStr End Function -- Regards, Jeff Register To Reply 06-06-2006,10:40 AM #2 Dave Peterson Guest Re: Error 2015 with Application.Evaluate Without testing.... getvalue _ = Application.Evaluate("Index(" & sh & "F1:F10000" & mtchValue & ")") needs an extra comma: getvalue _ = Application.Evaluate("Index(" & sh & "F1:F10000" & "," & mtchValue & ")") Jeff wrote: > > Hello, > > If someone could help me correct my VBA procedure. I'm lost and I don't know > how to fix it. I get #value error. > > Here's an example of my spreadsheet: > > A B C D E

help me correct my VBA procedure. I'm lost and I don't know how to fix it. I get #value error. Here's an example of my spreadsheet: A B C D E F G 20 6 F E Escada 1,940 495,866 Here's my VBA procedure: Dim mtchValue As Variant Dim getvalue As Variant Dim sh As String Dim fname As Variant fname = Application.GetOpenFilename If fname = False Then Exit Sub 'cancel End If sh = MakeReferenceNicer(fname) Workbooks.Open Filename:=fname mtchValue = ("MATCH(1,(" & sh & "A1:A10000=20)*" & _ "(" & sh & "B1:B10000=6)*" & "(" & sh & _ "C1:C10000=""F"")*" & "(" & sh & _ "E1:E10000=""Escada""),0)") If Not IsError(mtchValue) Then getvalue = Application.Evaluate("Index(" & sh & "F1:F10000" & mtchValue & ")") End If Range("S1").Select ActiveCell.Value = getvalue End Sub Function MakeReferenceNicer(fname) As String 'taking '"C:\My Documents\excel\book5.xls" 'shooting for: '"'C:\My Documents\excel\[book5.xls]May'!" Dim iCtr As Long Dim myStr As String For iCtr = Len(fname) To 1 Step -1 If Mid(fname, iCtr, 1) = "\" Then 'found that last backslash myStr = "'" & Left(fname, iCtr) & _ "[" & Mid(fname, iCtr + 1) & "]May'!" Exit For End If Next iCtr MakeReferenceNicer = myStr End Function -- Regards, Jeff Guest, Jun 6, 2006 #1 Advertisements Dave Peterson Guest Without testing.... getvalue _ = Application.Evaluate("Index(" & sh & "F1:F10000" & mtchValue & ")") needs an extra comma: getvalue _ = Application.Evaluate("Index(" & sh & "F1:F10000" & "," & mtchValue & ")") Jeff wrote: > > Hello, > > If someone could help me correct my VBA procedure. I'm lost and I don't know > how to fix it. I get #value error. > > Here's an example of my spreadsheet: > > A B C D E F G > 20 6 F E Escada 1,940 495,866 > Here's my VBA procedure: > Dim mtchValue As Variant > Dim getvalue As Variant > Dim sh As String > Dim fname As Variant > > fname = Application.GetOpenFilename > If fname = False Then > Exit Sub 'cancel > End If > > sh = MakeReferenceNicer(fname) > > Workbooks.Open Filename:=fname > > mtchValue = ("MATCH(1,(" & sh & "A1:A10000=20)*" & _ > "(" & sh & "B1:B10000=6)*" & "(" & sh & _ > "C1:C10000=""F"")*" & "(" & sh & _ > "E1:E10000=""Escada""),0)") > > If Not IsError(mtchValue) Then > getvalue = Application.Evaluate("Index(" & sh & "F1:F10000" & > mtchValue & ")") > End If > Range("S1").Select > ActiveCell.Value = getvalue > > > End Sub > > > Function MakeReferenceNicer(fname) As String > > 'taking > '"C:\My Documents\excel\book5.xls" > 'shooting for: > '"'C:\My Documents\excel\[book5.xls]May'!" > > Dim iCtr As Long > Dim myStr As String > > For iCtr = Len(fname) To 1 Step -1 > If Mid(fname, iCtr, 1) = "\" Then > 'found that last backslash > myStr = "'" & Left(fname,