Excel Vb Error 2015
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Excel Vba Error 2029
2015 up vote 1 down vote favorite In my Main procedure I want to write a quick if-statement which checks whether the user has made a valid input (user chooses number of project from list of data, see attached screenshot). For that I am checking whether the project number is not part of the list of projects. If that is true, an error message application.evaluate vba is displayed; if not then a number of other procedures are called. For some reason though I get error 2015 when I run it, which means that the if-statement is always true, even on correct user entries. Can someone help me understand the error please? The project number input is a named cell called "IdSelect" and is on a sheet called "Invoice" The data against which this input is checked is on a sheet called "Input" The data is stored in column B and called "ProjectList" Code below (note: I have tried pasting it 5 times but the formatting still won't work this time for some reason - any idea what that could be? The code is properly formatted. Sorry for the messy display; if anyone can tell me what that problem might I would be very grateful!) Sub Main() 'Turn off screen updating Application.ScreenUpdating = False 'Define variable for currently active cell to reactivate it afterwards Dim OldActiveSheet As Object Dim OldActiveCell As Object Dim i As Integer Dim ProjectList As Range Set OldActiveSheet = ActiveSheet Set OldActiveCell = ActiveCell 'If-statement to check whether project number is valid or not Worksheets("Invoice").Act
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Vba Error Handling
company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only http://stackoverflow.com/questions/14188010/vba-application-match-error-2015 takes a minute: Sign up Excel VBA - Array Formula returns #VALUE! (Error 2015) in case a cell contains more than 255 characters up vote 2 down vote favorite 1 Dear all I am using an array formula and pass the result to a VBA macro, which means the result of the formula is passed as array to my macro. In http://stackoverflow.com/questions/35436777/excel-vba-array-formula-returns-value-error-2015-in-case-a-cell-contains-m some cases I get in the array a #VALUE (error 2015) and I have no clue why. When I play arround with the affected cell where it gets the data from then it is happening when the cell has quite an amount of characters (~3000 chars). Has anyone a clue what I can try to solve the isuse? formula: {=arrayToCSV(removeElementsFrom2DimArray(IF('sheet'!$G$1:$G$2000=A1;'sheet'!$F$1:$F$2000)))} the IF('sheet'!$G$1:$G$2000=A1;'sheet'!$F$1:$F$2000) part returns an array like {FALSE, FALSE, FALSE... Value, Value, FALSE , ...}. This one I pass to my mVBA function removeElementsFrom2DimArray to remove the FALSE elements Now it seems that the IF('sheet'!$G$1:$G$2000=A1;'sheet'!$F$1:$F$2000) return in some cases #VALUE(Error 2015) for some of the elements i.e. {FALSE, FALSE, FALSE... #VALUE!, Value, FALSE , ...} Function removeElementsFrom2DimArray(ByRef arr() As Variant, Optional value As Variant = False) As String() On Error GoTo ErrorHandler Dim coll As New Collection Dim i As Integer If (IsArray(arr)) Then For i = 1 To UBound(arr, 1) If (arr(i, 1) <> value) Then --> Here happens the error that arr(i, 1) return #VALUE! Error 2015. Why? coll.Add (arr(i, 1)) End If Next i End If re
Way | Trading Add-ins For Excel | Convert Excel Into Calculating Web Pages Excel Web Pages | Produce Clean Efficient VBA Code Every Time | Build Automated Trading Models In Excel | Excel Web Pages | Excel Video Training Forum New http://www.ozgrid.com/forum/showthread.php?t=54231 Posts FAQ Calendar Forum Actions Mark Forums Read Quick Links Today's Posts What's New? Advanced Search http://answers.microsoft.com/en-us/msoffice/forum/msoffice_excel-mso_winother/vba-weird-evaluate-and-msgbox-error-2015-but-no/ee9fd29f-bc1d-4772-8566-db5092e53bff Forum HELP FORUMS Excel General error 2015 Excel Training / Excel Dashboards Reports If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. If error 2015 you don't like Google AdSense in the posts, register or log in above. Click here to view the relaunched Ozgrid newsletter. Results 1 to 6 of 6 Thread: error 2015 Thread Tools Show Printable Version Search Thread Advanced Search July 19th, 2006 #1 jetted View Profile View Forum Posts Senior Member Join Date 16th June 2004 Location Canada Quebec Posts 260 error 2015 Hi everyone I am getting an "error 2015" and I don't why! Can anyone help excel vba error me? resultat= Error 2015 VB: Range("c2").Select newvalue = " " newvalue1 = " " For Each rngC In rngJbn rngC = Trim(rngC) If rngC.Value <> newvalue And rngC.Value <> "ab-" Then 'MsgBox "****" & rngC & "***" Resultat = Application.CountIf(Range("C2:C" & Range("C" & Rows.Count).End(xlUp).Row).SpecialCells(xlCellTypeVisible), rngC) Last edited by jetted; July 19th, 2006 at 21:00. Excel Video Tutorials / Excel Dashboards Reports Reply With Quote July 19th, 2006 #2 Batman View Profile View Forum Posts Super Moderator Join Date 8th September 2004 Location Northampton, England Posts 3,368 Re: error 2015 Hi jetted, Without being able to see all your code, I suspect that the problem relates to the use of SpecialCells within the CountIf function. SpecialCells is likely to return a range of non-contiguous cells, assuming that you have hidden rows in the range, but CountIf can't cope with anything other than a single range of cells, e.g. A1:A10 will work, but not A1, A5:A6, A8. Hope this helps. Regards, Batman. Reply With Quote July 19th, 2006 #3 jetted View Profile View Forum Posts Senior Member Join Date 16th June 2004 Location Canada Quebec Posts 260 Re: error 2015 Hi Batman I appreciate your input. However, this was working until now. I have attached the entire code. The content of cell is 4087. Therefor it is trying to count of many time it find 4087 for a particular date. As I mention before this was working find la
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