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company Business Learn more about hiring developers or posting ads with us Stack Overflow excel vba application.match error 2042 Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 vba error 2015 vlookup million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up VBA application.match error 2015 up vote 1 down vote favorite In my Main procedure I want to write a https://support.microsoft.com/en-us/kb/211601 quick if-statement which checks whether the user has made a valid input (user chooses number of project from list of data, see attached screenshot). For that I am checking whether the project number is not part of the list of projects. If that is true, an error message is displayed; if not then a number of other procedures are called. For some reason though I get error 2015 when I run it, which http://stackoverflow.com/questions/14188010/vba-application-match-error-2015 means that the if-statement is always true, even on correct user entries. Can someone help me understand the error please? The project number input is a named cell called "IdSelect" and is on a sheet called "Invoice" The data against which this input is checked is on a sheet called "Input" The data is stored in column B and called "ProjectList" Code below (note: I have tried pasting it 5 times but the formatting still won't work this time for some reason - any idea what that could be? The code is properly formatted. Sorry for the messy display; if anyone can tell me what that problem might I would be very grateful!) Sub Main() 'Turn off screen updating Application.ScreenUpdating = False 'Define variable for currently active cell to reactivate it afterwards Dim OldActiveSheet As Object Dim OldActiveCell As Object Dim i As Integer Dim ProjectList As Range Set OldActiveSheet = ActiveSheet Set OldActiveCell = ActiveCell 'If-statement to check whether project number is valid or not Worksheets("Invoice").Activate 'Print to Immediate Window to check value - remove later Debug.Print Range("IdSelect").Value If IsError(Application.Match(Range("IdSelect").Value, "ProjectList", 0)) Then 'Print to Immediate Window to check value - remove later Debug.Print Application.Match(Range("IdSelect").Value, Worksheets("Input").Range("ProjectList"), 0) MsgBox "Invalid Choice: Project with this number does not exist!" Exit Sub Else 'Call procedures to execute Call

this is your first visit, be sure to check out the FAQ by clicking the link above. You may http://www.vbforums.com/showthread.php?668611-VBA-error-2015-for-Match-method have to register before you can post: click the register link http://www.mrexcel.com/forum/excel-questions/493350-using-excel-search-visual-basic-applications-error-2015-a.html above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. Results 1 to 4 of 4 Thread: VBA error 2015 for Match method Tweet Thread Tools Show Printable Version Subscribe to this Thread… Display Linear Mode error 2015 Switch to Hybrid Mode Switch to Threaded Mode Dec 30th, 2011,05:49 AM #1 Silvio View Profile View Forum Posts Thread Starter New Member Join Date Dec 2011 Posts 1 VBA error 2015 for Match method when comparing two cells with each other I am getting error 2015. I realized that this is due to the error 2015 vba number of characters stated within the cells. The error occurs when comparing more than 255 characters. Please see coding below. The line in italic is where the error occurs. VB: Sub test() Dim accR As Long Dim res As Variant 'Set Account to check details Workbooks("File_B.xlsx").Worksheets("Group").Activate accCol = "A" startRow = "1" endRow = "4" Set Rng_Accs = Range(accCol & startRow, accCol & endRow) 'Compare accounts For Each acc In Rng_Accs accR_B = acc.Row Workbooks("File_A.xlsx").Worksheets("Group").Activate res = Application.Match(acc, Range("A1:A100"), 0) If IsError(res) Then MsgBox "Account " & acc & " could not be found" Workbooks("File_B.xlsx").Worksheets("Group").Range(accCol & accR_B).Interior.Color = 255 End If Next acc End Sub Reply With Quote Dec 31st, 2011,11:58 AM #2 incidentals View Profile View Forum Posts Frenzied Member Join Date Nov 2010 Posts 1,448 Re: VBA error 2015 for Match method what do you think for each acc in rng_accs return? what is an acc? Reply With Quote Dec 31st, 2011,12:01 PM #3 maricharm View Profile View Forum Posts New Member Join

Forums Excel Questions Using Excel SEARCH in VBA (Error 2015) Results 1 to 6 of 6 Using Excel SEARCH in VBA (Error 2015)This is a discussion on Using Excel SEARCH in VBA (Error 2015) within the Excel Questions forums, part of the Question Forums category; Hello All, I have this macro... Code: Sub Indent() Dim value As Variant Dim cell As range Dim range As ... LinkBack LinkBack URL About LinkBacks Bookmark & Share Digg this Thread!Add Thread to del.icio.usBookmark in TechnoratiTweet this thread Thread Tools Show Printable Version Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Sep 7th, 2010,03:39 PM #1 dehinson New Member Join Date Sep 2010 Posts 2 Using Excel SEARCH in VBA (Error 2015) Hello All, I have this macro... Code: Sub Indent() Dim value As Variant Dim cell As range Dim range As range Dim source As range Dim sourcecell As range Set source = ActiveSheet.range("A:A") ActiveCell.EntireColumn.Select Set range = Selection Dim SearchText As String Dim SearchCell As String SearchText = "." For Each cell In range Set sourcecell = source.Cells(cell.Row) SearchCell = sourcecell.Address SearchCell = Replace(SearchCell, """", "") searchformula = "=SEARCH(""" & SearchText & """," & SearchCell & ",1)" value = Application.Evaluate(searchformula) cell.IndentLevel = cell.Offset(0, -1) Next End Sub It is not done yet. However, as I debug it, I am receiving an error 2015 on the Application.Evaluate line. The value of the searchformula is: "SEARCH(".",$A$1,1)". This looks like the same formula I would use in an Excel cell. Why am I getting this error? Share Share this post on Digg Del.icio.us Technorati Twitter Reply With Quote Sep 7th, 2010,05:02 PM #2 Scott Huish MrExcel MVPModerator Join Date Mar 2004 Location Oregon Posts 18,412 Re: Using Excel SEARCH in VBA (Error 2015) Why don't you just use InStr? Share Share this post on Digg Del.icio.us Technorati Twitter Office 2010/2016 Reply With Quote Sep 7th, 2010,05:45 PM #3 MrKowz Board Regular Join Date Jun 2008 Location St. Louis, MO Posts 6,119 Re: Using Excel SEARCH in VBA (Error 2015) Or even Application.Find Share Share this post on Digg Del.icio.us Technorati Twitter - Posting guidelines, forum rules and terms of use - Try searching for your answer first, see how - Read the FAQs - List of BB codes - Please use [CODE] [/CODE] tags when posting your VBA code. It retains spacing, so your code is easier to read, and therefore ea