Error 2015 Vb Excel

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Excel Vba Error 2015 Vlookup

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Excel Vba Fehler 2015

down vote favorite In my Main procedure I want to write a quick if-statement which checks whether the user has made a valid input (user chooses number of project from list of data, see attached screenshot). For that I am checking whether the project number is not part of the list of projects. If that is true, an error message is displayed; if not then a excel vba erreur 2015 number of other procedures are called. For some reason though I get error 2015 when I run it, which means that the if-statement is always true, even on correct user entries. Can someone help me understand the error please? The project number input is a named cell called "IdSelect" and is on a sheet called "Invoice" The data against which this input is checked is on a sheet called "Input" The data is stored in column B and called "ProjectList" Code below (note: I have tried pasting it 5 times but the formatting still won't work this time for some reason - any idea what that could be? The code is properly formatted. Sorry for the messy display; if anyone can tell me what that problem might I would be very grateful!) Sub Main() 'Turn off screen updating Application.ScreenUpdating = False 'Define variable for currently active cell to reactivate it afterwards Dim OldActiveSheet As Object Dim OldActiveCell As Object Dim i As Integer Dim ProjectList As Range Set OldActiveSheet = ActiveSheet Set OldActiveCell = ActiveCell 'If-statement to check whether project number is valid or not Worksheets("Invoice").Activate 'Print to Immediate Window to check value - remove later Debug.Print Range("IdSe

formulas as strings and have Excel VBA compute them for you. Only recently I discovered that some of the cells in a vba error 2015 vlookup workbook contained #VALUE? instead of a sound value. After some investigation application.evaluate error 2015 I found out that, without raising any error at application level (in VBA), the Application.Evaluate function failed consistently excel error 2015 evaluate with this error whenever a particular condition occurred. This condition is related to limits in the underlying software layer of Excel, the one that runs Application.Evaluate. Apparently this http://stackoverflow.com/questions/14188010/vba-application-match-error-2015 particular error occurs when the parsed function returns a string value having a length above 255 characters. As long as the length of the string is less than or equal to 255 characters, the return value is the desired string. Above 255 characters, the function "crashes". In my case, I was not immediately attended on this error https://dutchgemini.wordpress.com/2009/08/07/error-2015-using-application-evaluate-in-excel-vba/ because I used a Variant to store the returned value from Application.Evaluate (sample code): Dim vValue As Variant vValue = Application.Evaluate("GetData()") ' Error 2015 saved in vValue if GetData returns 255+ characters ActiveCell.Value = vValue If I would have used a String to store the value, I would probably have gotten a "Runtime Error 13 - Type Mismatch" with Excel booming out of my routine without any debugging possibility (sample code): Dim sValue As String sValue = Application.Evaluate("GetData()") ' Run-time error if GetData() returns 255+ characters ActiveCell.Value = sValue To catch problems, I now completed code with an If statement (sample code): Dim vValue As Variant vValue = Application.Evaluate("GetData()") If (VBA.VarType(vValue) = vbError) Then ActiveCell.Value = "String Overflow on GetData()" Else ActiveCell.Value = vValue End If There seem to be more Excel functions that suffer from this 255 character limit, but could not establish which. For the moment, I will apply some workarounds until it gets solved by Microsoft. Dutch Like this:Like Loading... Related Comments (3) 3 Comments »

Way | Trading Add-ins For Excel | Convert Excel Into Calculating Web Pages Excel Web Pages | Produce Clean Efficient VBA Code Every Time | Build Automated Trading Models In Excel | Excel Web Pages http://www.ozgrid.com/forum/showthread.php?t=54231 | Excel Video Training Forum New Posts FAQ Calendar Forum Actions Mark Forums Read Quick Links Today's Posts What's New? Advanced Search Forum HELP FORUMS Excel General error 2015 Excel Training / Excel Dashboards Reports If http://www.cpearson.com/excel/ReturningErrors.aspx this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, error 2015 select the forum that you want to visit from the selection below. If you don't like Google AdSense in the posts, register or log in above. Click here to view the relaunched Ozgrid newsletter. Results 1 to 6 of 6 Thread: error 2015 Thread Tools Show Printable Version Search Thread Advanced Search July 19th, 2006 #1 jetted View Profile View Forum Posts Senior Member Join Date 16th June 2004 Location Canada Quebec evaluate error 2015 Posts 260 error 2015 Hi everyone I am getting an "error 2015" and I don't why! Can anyone help me? resultat= Error 2015 VB: Range("c2").Select newvalue = " " newvalue1 = " " For Each rngC In rngJbn rngC = Trim(rngC) If rngC.Value <> newvalue And rngC.Value <> "ab-" Then 'MsgBox "****" & rngC & "***" Resultat = Application.CountIf(Range("C2:C" & Range("C" & Rows.Count).End(xlUp).Row).SpecialCells(xlCellTypeVisible), rngC) Last edited by jetted; July 19th, 2006 at 21:00. Excel Video Tutorials / Excel Dashboards Reports Reply With Quote July 19th, 2006 #2 Batman View Profile View Forum Posts Super Moderator Join Date 8th September 2004 Location Northampton, England Posts 3,368 Re: error 2015 Hi jetted, Without being able to see all your code, I suspect that the problem relates to the use of SpecialCells within the CountIf function. SpecialCells is likely to return a range of non-contiguous cells, assuming that you have hidden rows in the range, but CountIf can't cope with anything other than a single range of cells, e.g. A1:A10 will work, but not A1, A5:A6, A8. Hope this helps. Regards, Batman. Reply With Quote July 19th, 2006 #3 jetted View Profile View Forum Posts Senior Member Join Date 16th June 2004 Location Canada Quebec Posts 260 Re: error 2015 Hi Batman I appreciate your input. However, this was work

page describes how to return errors from VBA User Defined Functions. Returning Errors From VBA Functions If you use VBA or another COM language to create User Defined Functions (functions that are called directly from worksheet cells) in a module or add-in, you likely will need to return an error value under some circumstances. For example, if a function requires a positive number as a parameter and the user passes in a negative number, you should return a #VALUE error. You might be tempted to return a text string that looks like an error value, but this is not a good idea. Excel will not recognize the text string, for example #VALUE, as a real error, so many functions and formulas may misbehave, especially ISERROR, ISERR, and IFERROR, and ISNA. These functions require a real error value. VBA provides a function called CVErr that takes a numeric input parameter specifying the error and returns a real error value that Excel will recognize as an error. The values of the input parameter to CVErr are in the XLCVError Enum and are as follows: xlErrDiv0 (= 2007) returns a #DIV/0! error. xlErrNA (= 2042) returns a #N/A error. xlErrName (= 2029) returns a #NAME? error. xlErrNull (= 2000) returns a #NULL! error. xlErrNum (= 2036) returns a #NUM! error. xlErrRef (= 2023) returns a #REF! error. xlErrValue (= 2015) returns a #VALUE! error. The only legal values of the input parameter to CVErr function are those listed above. Any other value causes CVErr to return a #VALUE. This means, unfortunately, that you cannot create your own custom error values. In order to return an error value, the function's return data type must be a Variant. If the return type is any other data type, the CVErr function will terminate VBA execution and Excel will report a #VALUE error in the cell. Note