Python Subprocess Error 5
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Windowserror Error 5 Access Is Denied Python
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Python Subprocess Windows Access Denied
Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: python windows error 5 Sign up Python script works fine on Linux, on Windows, causes WindowsError: [Error 5] Access is denied up vote 3 down vote favorite 1 I have a simple python script that works fine on Linux, I moved it to a Windows machine and when I attempt to run it, I get the following exception message: Traceback (most recent call last): File "C:\path\to\my\script.py", windowserror error 5 access is denied pip line 57, in
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Python Windowserror
million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up WindowsError: [Error 5] Access is denied up vote 2 down vote favorite I've been trying to kill a process http://stackoverflow.com/questions/11835873/python-script-works-fine-on-linux-on-windows-causes-windowserror-error-5-ac but all my options give me a Windows Access Denied Error. I open the process(a python script) through test= subprocess.Popen([sys.executable, "testsc.py"]) and I want to kill that process. So far, I've tried os.kill(pid, signal.SIGILL) , os.kill(pid, 9), test.Terminate() and simply test.kill(). All of these give me the error. I am using Python 2.7.1.4 on a Windows 7 x86 machine. I would appreciate the help! Thanks! python share|improve this question edited Jul 14 http://stackoverflow.com/questions/6688815/windowserror-error-5-access-is-denied '11 at 5:35 mac 22.4k1288104 asked Jul 14 '11 at 5:26 dawnoflife 57923155 We need more code. Maybe the process is already done when you are trying to kill it. –Jacob Jul 14 '11 at 5:40 There seem to be a number of such reports, e.g. this one with the same title minus a colon and with a lowercase E and this one with a decent name ("Terminate subprocess in Windows, access denied"). –Chris Morgan Jul 14 '11 at 5:45 Observing the documentation for os.kill, "New in version 2.7: Windows support". But you say you're using Python 2.7 so that shouldn't be a problem. –Chris Morgan Jul 14 '11 at 5:55 What process are you trying to kill? Did you spawn it? If it's a SYSTEM process, you won't be able to kill it as a local admin. –Josh Jul 14 '11 at 6:14 @Josh: did you read? subprocess.Popen([sys.executable, "testsc.py"]). He should be able to kill that! –Chris Morgan Jul 14 '11 at 8:27 | show 1 more comment 1 Answer 1 active oldest votes up vote 1 down vote Funnily enough, it means that access is denied. (I think I deserve upvotes for that piece of added intelligence ;-).) You don't have permission to k
New in version 2.4. The subprocess module allows you to spawn new processes, connect to their input/output/error pipes, and obtain their return codes. This module intends to replace https://docs.python.org/2/library/subprocess.html several older modules and functions: os.system os.spawn* os.popen* popen2.* commands.* Information about how this module can be used to replace the older functions can be found in the subprocess-replacements section. See also POSIX users (Linux, BSD, etc.) are strongly encouraged to install and use the much more recent subprocess32 module instead of the version included with python 2.7. error 5 It is a drop in replacement with better behavior in many situations. PEP 324 - PEP proposing the subprocess module 17.1.1. Using the subprocess Module¶ The recommended way to launch subprocesses is to use the following convenience functions. For more advanced use cases when these do not meet your needs, use the underlying Popen interface. subprocess.call(args, *, error 5 access stdin=None, stdout=None, stderr=None, shell=False)¶ Run the command described by args. Wait for command to complete, then return the returncode attribute. The arguments shown above are merely the most common ones, described below in Frequently Used Arguments (hence the slightly odd notation in the abbreviated signature). The full function signature is the same as that of the Popen constructor - this functions passes all supplied arguments directly through to that interface. Examples: >>> subprocess.call(["ls", "-l"]) 0 >>> subprocess.call("exit 1", shell=True) 1 Warning Using shell=True can be a security hazard. See the warning under Frequently Used Arguments for details. Note Do not use stdout=PIPE or stderr=PIPE with this function as that can deadlock based on the child process output volume. Use Popen with the communicate() method when you need pipes. subprocess.check_call(args, *, stdin=None, stdout=None, stderr=None, shell=False)¶ Run command with arguments. Wait for command to complete. If the return code was zero then return, otherwise raise CalledProcessError. The CalledProcessError object will have the return code in the