Access Error 6 Overflow
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Runtime Error 6 Overflow Vba Access
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Error Messages Error Messages Overflow (Error 6) Overflow (Error 6) Overflow (Error 6) #Else clause must be preceded by a matching #If #Else If, #Else, or #End If must be preceded runtime error 6 overflow vb6 by a matching #If #ElseIf must be preceded by a matching #If or #ElseIf and followed by an #ElseIf, #Else, or #End If
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Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up runtime error https://msdn.microsoft.com/en-us/library/office/gg278733.aspx 6 overflow up vote 2 down vote favorite I am getting a Runtime error 6 'overflow' message on the following code upon arriving at the line starting with 'minimo'. It was working fine until recently. After providing some cosmetic-type updates to its underlying form this message has arrived and I can't understand why. 'Dim rs As ADODB.Recordset Set rs = New ADODB.Recordset rs.Open "select http://stackoverflow.com/questions/28053343/runtime-error-6-overflow min(autonumerazione) from tblDashboard01", CurrentProject.Connection Do While Not rs.EOF minimo = rs.Fields(0) rs.MoveNext Loop minimo = minimo - 1 st_Sql = "update tbldashboard01 set MasterLevel = autonumerazione - " & minimo & "" Application.DoCmd.RunSQL (st_Sql) access-vba ms-access-2010 share|improve this question edited Jan 20 '15 at 19:16 HansUp 79.1k114371 asked Jan 20 '15 at 19:11 Marchese Il Chihuahua 4551826 How is minimo declared? If it's Integer, it can't accept a value larger than 32,767. What is the value of rs.Fields(0) when you hit that error? –HansUp Jan 20 '15 at 19:14 add a comment| 1 Answer 1 active oldest votes up vote 3 down vote accepted Try inserting the following line at the start of the program: Dim minimo as Long share|improve this answer answered Jan 20 '15 at 19:23 miroxlav 5,58121743 bravo. Thank you –Marchese Il Chihuahua Jan 20 '15 at 19:39 3 @MarcheseIlChihuahua – My practice is to insert Option Explicit as the first line of every program module (file). This forces me to declare every variable using Dim statement and this way I can avoid many errors similar to this one. –miroxlav Jan 20 '15
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