Call To A Member Function Bind_param On A Non-object Error
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Call To A Member Function Bind_param() On A Non-object Mysqli
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Fatal Error: Call To A Member Function Bind_param() On A Non-object In Php
programmers, just like you, helping each other. Join them; it only takes a minute: Sign up (Fatal error: Call to a member function bind_param() on a non-object) up vote 4 down vote favorite I get an error
Fatal Error: Call To A Member Function Bind_param() On Boolean
with this text:(sorry for my bad english I am from germany!) Error:Fatal error: Call to a member function bind_param() on a non-object in /users/ftf/www/ccache.php on line 44 A part of the Code from ccache.php // Neues Datenbank-Objekt erzeugen $db = @new mysqli( 'localhost', 'ftf', '***', 'ftf' ); // Pruefen ob die Datenbankverbindung hergestellt werden konnte if (mysqli_connect_errno() == 0) { $sql = "INSERT INTO cache ('name', 'user', 'veroefentlichung', 'beschreibung', 'FTFcode', 'STFcode', 'TTFcode', 'type', 'lat', call to a member function bind_param() on a non-object insert 'lon', 'address', 'link') VALUES ('?', '?', '?', '?', '?', '?', '?', '?', '?', '?', '?')"; $eintrag = $db->stmt_init(); $eintrag = $db->prepare( $sql ); $eintrag->bind_param($titel, $user, $datum, $desc, $FTF, $STF, $TTF, $type, $Lat, $Lon, $shortdesc, $genlink); // line 44 $eintrag->execute(); // Pruefen ob der Eintrag efolgreich war if ($eintrag->affected_rows == 1) { echo 'Der neue Eintrage wurde hinzugefügt.'; } else { echo 'Der Eintrag konnte nicht hinzugefügt werden.'; } } php mysqli sqlbindparameter share|improve this question edited Sep 20 '13 at 16:50 asked Sep 20 '13 at 16:34 Jonas Franz 1671110 stackoverflow.com/… –Mike B Sep 20 '13 at 16:41 add a comment| 4 Answers 4 active oldest votes up vote 3 down vote accepted $eintrag->bind_param($titel, $user, $datum, $desc, $FTF, $STF, $TTF, $type, $Lat, $Lon, $shortdesc, $genlink); // line 44 You need to the define the type of parameters as this: $eintrag->bind_param("ssssssiiss", $titel, $user, $datum, $desc, $FTF, $STF, $TTF, $type, $Lat, $Lon, $shortdesc, $genlink); // line 44 s - string i - int Also check documentation: http://php.net/manual/en/mysqli-stmt.bind-param.php share|improve this answer answered Oct 12 '13 at 11:53 Robert Iulian 735 add a comment| up vote 5 down vote Check your return values! Bad: $eintrag = $db->prepare( $sql ) Good: if( ! $eintrag = $db->prepare( $sql ) ) { echo 'Error: ' . $db->error; return false; // throw exception, die(), ex
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings fatal error: call to a member function bindparam() on a non-object and policies of this site About Us Learn more about Stack Overflow call to a member function bind_param() on a non-object slim the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation call to undefined method mysqli_stmt::bindparam() Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it http://stackoverflow.com/questions/18921670/fatal-error-call-to-a-member-function-bind-param-on-a-non-object only takes a minute: Sign up Call to a member function bind_param() on a non-object MySQLi up vote 3 down vote favorite Okay, so I'm trying to update a blog entry, and I'm getting Call to a member function bind_param() on a non-object when I try to run the script. I have done extensive research to see if I could http://stackoverflow.com/questions/17768200/call-to-a-member-function-bind-param-on-a-non-object-mysqli fix it myself, but I must be missing something. prepare("UPDATE blogentries SET headline = ?, image = ?, caption = ?, article = ? WHERE id = ?"); $stmt->bind_param('ssssi', $_POST['headline'], $_POST['image'], $_POST['caption'], $_POST['article'], $_POST['id']); $stmt->execute(); $stmt->close(); ?> Thanks in advance, Austen Update: Here's the db connect I added the extra $mysqli connection for debugging purposes, and the error occurs even without it. php mysqli share|improve this question edited Jul 22 '13 at 0:24 asked Jul 21 '13 at 1:18 Austen 1421215 can show full code of that file? where is database connection? –user1646111 Jul 21 '13 at 1:25 The full code is a few thousand lines long, so I won't do that, but the DB connection is outside of the public_html folder, I'll update main post to show the db connection. –Austen Jul 21 '13 at 1:30 how are you calling/including the db connection file that is outside the public_html folder? –Sean Jul 21 '13 at 6:57 1 Possible duplicate of Call to a member function bind_param() on
here for a quick overview of the site Help Center Detailed answers to any questions you might http://stackoverflow.com/questions/19244705/php-fatal-error-call-to-a-member-function-bind-param-on-a-non-object have Meta Discuss the workings and policies of this site About http://stackoverflow.com/questions/6659882/call-to-a-member-function-bind-param-on-a-non-object-unable-to-solve-despite Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million call to programmers, just like you, helping each other. Join them; it only takes a minute: Sign up PHP: Fatal error: Call to a member function bind_param() on a non-object up vote 0 down vote favorite The error occurs on line 42: $result->bind_param("ssssisssss", $Firma, $Partner, $Abteilung, $Strasse, $PLZ, $Ort, $Telefon, $Email, $Website, $Info ); This is the call to a whole prepared statement: $sql = "INSERT INTO `firmen` (`Firma`, `Ansprechpartner`, `Abteilung`, `Strasse`, `PLZ`, `Ort`, `Telefon`, `Email`, `Website`, `Zusatzinfos`) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?)"; $result = $db->prepare( $sql ); $result->bind_param("ssssisssss", $Firma, $Partner, $Abteilung, $Strasse, $PLZ, $Ort, $Telefon, $Email, $Website, $Info ); $result->execute(); I can't find the mistake, I already read almost every question with the same mistake an I also compared my Code with a lot of Tutorial and it looks exactly the same... Thanks in advance! php function member share|improve this question asked Oct 8 '13 at 10:03 Chrisis 112 Put $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); in front of $db->prepare() and see what's wrong. –Kontrollfreak Oct 8 '13 at 10:08 add a comment| 5 Answers 5 active oldest votes up vote 1 down vote ...usually this occurs when you have an error in prepare statement, It might happen that you have a typo in sql prepare. to verify that. check the error with this $stmt = $this->db->prepare("INSERT INTO ".TB_ADMINISTRATION."
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Call to a member function bind_param() on a non-object (unable to solve despite research) up vote 4 down vote favorite 1 $stmt = $mysqli->prepare('select Un from member where Lock = ? and Activated = ?'); $stmt -> bind_param("ss", 'N', 'Y');//This line gave the error $stmt -> execute(); $stmt->store_result();//apply to prepare statement $numRows = $stmt->num_rows; if ($numRows > 0)//if have result while ($row = $stmt->fetch()) my above code gave me a "Call to a member function bind_param() on a non-object" error. I really don't get it why i getting this error. I have correct cols name. I am new to mysqli and would like to learn how to debug such error. what is the problem with my prepare statement or bind_param()? Please teach me how to debug such error php share|improve this question edited Sep 3 '12 at 11:59 j0k 17.4k114960 asked Jul 12 '11 at 5:36 Jerry 21112 add a comment| 3 Answers 3 active oldest votes up vote 14 down vote Call to a member function bind_param() on a non-object means that $stmt, which you're trying to call bind_param on, is not an object. Why is it not an object? Because $mysqli->prepare did not return an object. Why did it not return an object? mysqli_prepare() returns a statement object or FALSE if an error occurred. http://www.php.net/manual/en/mysqli.prepare.php So that means an error must have occurred. You should turn on error_reporting, which will probably tell you, or examine $mysqli->error(), which may tell you as well. share|improve this answer answered Jul 12 '11 at 5:41 deceze 301k42382528 Error turn on and it said " You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Lock = ? and Activated = ?'" I still can't see why my sql is wrong. –Jerry Jul 12 '11 at 6:11 1 @Jerr