Call To Super Must Be First Statement In Constructor Error
Contents |
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us java call to super must be first statement in constructor Learn more about Stack Overflow the company Business Learn more about hiring developers
Call To Super Must Be First Statement In Constructor Body
or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack super constructor in java Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Call to super must be first statement
Super Constructor In Java Example
in the constructor, but it is up vote 7 down vote favorite I keep getting an error saying that "call to super must be the first statement in the constructor". The problem is that it is the first statement in my constructor. public void CheckingAccountCustomer(int a){ super(n, p, b); accountNo = a; } And here is my superclass for this as well. public void customer(String n, int this and super can be used in same method p, double b){ name = n; pin = p; balance = b; } What am I doing wrong here? java constructor super share|improve this question edited Jan 28 at 12:56 R O M A N I A 12.2k116575 asked May 6 '13 at 21:19 Phil Meyer 38113 2 The interesting thing here is that, since these aren't constructors, the call to super() is trying to call the constructor of the parent class from inside a method in the child. The error message says "Its not the first line in the child's constructor." That is true but not terribly helpful. Maybe a message like "Call to super not in constructor" would be nice. –Lee Meador May 6 '13 at 21:24 I was definitely not expecting to have answers this quickly. Of course, it was a simple fix that I was too blind to see. But still, thank you to all. –Phil Meyer May 6 '13 at 21:25 add a comment| 5 Answers 5 active oldest votes up vote 23 down vote accepted This code public void customer(String n, int p, double b){ is not a constructor. Constructors don't have return types, e.g. void. Assuming your c
tu nombre de usuario, contraseña y pulsa "Iniciar sesión". Noticias: Aprende Joomla con el libro "Creación y administración web con Joomla.
This() And Super() Calls Can Be Used In Methods Other Than A Constructor
Curso paso a paso" 2ª Edición. 168 pgs. Editorial aprenderaprogramar.com.
Java Super Constructor With Arguments
Disponible en formato papel y ebook. Inicio Ayuda Buscar en los foros Iniciar sesión Registrarse when implementing a method, use the class's set and get methods to access the class's ________ data. Foros aprenderaprogramar.com - Didáctica y divulgación de la programación » Aprender a programar » Aprender a programar desde cero » call to super must be first http://stackoverflow.com/questions/16407455/call-to-super-must-be-first-statement-in-the-constructor-but-it-is statement in constructor Java herencia CU00686B « anterior próximo » Imprimir Páginas: [1] Autor Tema: call to super must be first statement in constructor Java herencia CU00686B (Leído 1495 veces) fedegaray Principiante Mensajes: 81 call to super must be first statement in constructor Java herencia CU00686B « : 24 de Abril 2015, http://www.aprenderaprogramar.com/foros/index.php?topic=2440.0 21:59 » Hola comunidad. Aquí presento mi intento por resolver este ejercicio. CitarEJERCICIOSe plantea desarrollar un programa Java que permita la gestión de una empresa agroalimentaria que trabaja con tres tipos de productos: productos frescos, productos refrigerados y productos congelados. Todos los productos llevan esta información común: fecha de caducidad y número de lote. A su vez, cada tipo de producto lleva alguna información específica. Los productos frescos deben llevar la fecha de envasado y el país de origen. Los productos refrigerados deben llevar el código del organismo de supervisión alimentaria. Los productos congelados deben llevar la temperatura de congelación recomendada. Crear el código de las clases Java implementando una relación de herencia desde la superclase Producto hasta las subclases ProductoFresco, ProductoRefrigerado y ProductoCongelado. Cada clase debe disponer de constructor y permitir establecer (set) y recuperar (get) el valor de sus atributos y tener un método que permita mostrar la información del o
New Topic programming forums Java Java JSRs Mobile Certification Databases Caching Books Engineering Languages Frameworks Products This Site Careers Other all forums Forum: Java in General Avoiding the "call to super must be first statement in constructor" message Floyd Montgomery Greenhorn Posts: 7 posted 6 years https://coderanch.com/t/512408/java/java/Avoiding-call-super-statement-constructor ago Hi, I'd like to have something like that: public MyClass() { if (foo == 1) super(1); else super(2); } but I get the call to super must be first statement in constructor message... Any way I can avoid that? Thanks! Floyd Montgomery Greenhorn Posts: 7 posted 6 years ago By the way, I can't modify the super class... Wouter Oet Saloon Keeper Posts: 2700 I like... posted 6 years ago Where are you getting foo from? If it's an call to instance variable then the value will always be the default value. "Any fool can write code that a computer can understand. Good programmers write code that humans can understand." --- Martin Fowler Please correct my English. Campbell Ritchie Sheriff Posts: 50355 81 posted 6 years ago You can't write super() twice, but you can get an if . . . then . . . else into a single statement, quite easily. Floyd Montgomery Greenhorn Posts: 7 posted 6 years ago Wouter call to super Oet wrote:Where are you getting foo from? If it's an instance variable then the value will always be the default value. I'm getting it from the session. I should have written JSFUtil.getSession.getBean(...) Floyd Montgomery Greenhorn Posts: 7 posted 6 years ago Campbell Ritchie wrote:You can't write super() twice, but you can get an if . . . then . . . else into a single statement, quite easily. Well yeah, I can use the ? and : symbols if I have two cases... but actually have four of them... Mike Simmons Ranch Hand Posts: 3090 14 posted 6 years ago 1 Well, it's possible to chain multiple ? : together. But many people would consider that hard to read. You can also call a static method as part of the super constructor call: public MyClass() { super(method(foo)); ... } private static int method(int foo) { ... } Put whatever you want inside the method, as long as it doesn't access instance variables. That's why only static methods are allowed here; instance variables can't possibly have been meaningfully initialized at this point. Floyd Montgomery Greenhorn Posts: 7 posted 6 years ago Mike Simmons wrote:Well, it's possible to chain multiple ? : together. But many people would consider that hard to read. You can also call a static method as part of the super constructor call: public MyClass() { super(method(foo)); ... } private static int method(int foo) { ... } Put whatever you want inside the