Compile Error Access 2000
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Access Compile Error Method Or Data
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Access Compile Error Variable Not Defined
Compile error.in query expression Error This MSAccess tutorial explains how to fix a compile error.in query expression error in Access 2003 (with access compile error argument not optional screenshots and step-by-step instructions). Question: In Microsoft Access 2003/XP/2000/97, I tried using the Left function in a query and I get the following error: "Compile error.in query expression" I've seen this function work in other Access databases. https://support.microsoft.com/en-us/kb/241709 How come it does not work in mine? Answer: This error can be caused by multiple scenarios. Let's look at two of the most common causes. Option #1 This error can occur when there is a broken Reference in your Access database and you've tried to use one of the built-in Access functions such as Left, Instr, Len, Year, Mid, etc. To correct the problem, you need to open your Access database. Press Alt+F11 https://www.techonthenet.com/access/questions/compile_error.php to open the Microsoft Visual Basic window. When the Microsoft Visual Basic window appears, select References under the Tools menu. When the References window appears, check to see if there are any References checked that start with "MISSING:". If there are any, uncheck these References. Then click on the OK button. In this example, we want to uncheck the reference called "MISSING: Microsoft Word 9.0 Object Library". If you, in fact, need this Reference, go back to the References window (Tools > References) and re-check the reference. Click on the OK button. Now your Access database should have fixed the broken references and the error message should disappear. In the event that there were no References that start with "MISSING:", uncheck one or more of the existing References. Make sure that you record the References that you are unchecking. Then click on the OK button. Then go back to the References window (Tools > References) and re-check the references that you just unchecked. Access will update its references and the error message should now disappear. Option #2 This error can also be the result of a module in your Access database having two lines with "Option Compare Database" at the top of the module. For example: You can fix this error by removing one of the "Option Compare Database"
Office Applications Databases Compile error: Can't find project or library (Access 2000/SP3) If this is your first visit, be sure to check out the FAQ. You may have to Register before you can post. Results 1 http://windowssecrets.com/forums/showthread.php/70954-Compile-error-Can-t-find-project-or-library-(Access-2000-SP3) to 5 of 5 Thread: Compile error: Can't find project or library (Access 2000/SP3) Tweet Thread Tools Show Printable Version Subscribe to this Thread… 2005-02-02,23:49 #1 Mulk View Profile View Forum Posts Lounger Join Date Jan 2005 Location Jacksonville, North Carolina, USA Posts 29 Thanks 0 Thanked 0 Times in 0 Posts Compile error: Can't find project or library (Access 2000/SP3) Hello again, I'm trying to use Dev Ashish's "Get compile error Login Name" in a form. I built the form using Windows XP and Access 2003. On the XP computer, it works fine; when I run the form (click a new record button) on a WIndows 2000 computer (with Access 2000 sp/3), I get an error: Compile error: Can't find project or library. The biggest difference (besides installed software) is that the XP computer is on a workgroup and the 2000 computer access compile error is on a domain. The code is: '******************** Code Start ************************** ' This code was originally written by Dev Ashish. ' It is not to be altered or distributed, ' except as part of an application. ' You are free to use it in any application, ' provided the copyright notice is left unchanged. ' ' Code Courtesy of ' Dev Ashish ' Private Declare Function apiGetUserName Lib "advapi32.dll" Alias _ "GetUserNameA" (ByVal lpBuffer As String, nSize As Long) As Long Function fOSUserName() As String ' Returns the network login name Dim lngLen As Long, lngX As Long Dim strUserName As String strUserName = String$(254, 0) lngLen = 255 lngX = apiGetUserName(strUserName, lngLen) If ( lngX > 0 ) Then fOSUserName = Left$(strUserName, lngLen - 1) Else fOSUserName = vbNullString End If End Function '******************** Code End ************************** The line "Function fOSUserName() As String" (found on line 14) is highlighted in yellow and the word "String$" (found on line 18) is highlighted in dark blue. I hope I've given enough information to ask for help ... but not overloaded it either. Thank you for your time and help, 2005-02-03,00:10 #2 HansV View Profile View Forum Posts Plutonium Lounger Join Date Mar 2002 Posts 84,353 Thanks 0 Thanked 28 Times in 28