Compile Error Argument Not Optional Vba Access
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Vba Compile Error Sub Or Function Not Defined
not optional" Microsoft ISV Community Center > Visual Basic for Applications (VBA) Question 0 Sign in to vote I have written a program, using VBA in Excel 2007, and it runs perfect. I have been reading that it is good practice to 'compile' your program, not something I have previously done. When I click compile, vba compile error method or data member not found I get the following error: "Complie Error: Argument not optional". What does this mean? The error occurs on this line of code: Call InsertVaRSummaryFigure Which calls this function (which works fine): Function InsertVaRSummaryFigure(SummarySheet As String) Worksheets(SummarySheet).Select strFindAddressClearSection = Range("C1:C1000").Find("Total Core Rates GB", Range("C1"), xlValues, xlWhole, xlByColumns, xlNext).Address Range(strFindAddressClearSection).Offset(0, 2).Formula = "=-VaRData!D11" End Function Can anyone enlighten me? Wednesday, September 29, 2010 9:33 AM Reply | Quote Answers 0 Sign in to vote Hi Gazza101, If you write this: Function InsertVaRSummaryFigure(SummarySheet As String) This means, that the parameter SummarySheetis not optional. You must give that to the function. And if you write that: Call InsertVaRSummaryFigure you have no transfer parameter, so the compiler said: "Complie Error: Argument not optional" You can try this: Function InsertVaRSummaryFigure(Optional SummarySheet As String = "NameOfYourSheet") or this: Call InsertVaRSummaryFigure("NameOfYourSheet") or both if you want a standard Sheet, or another different: Function InsertVaRSummaryFigure(Optional SummarySheet As String = "Sheet1") Call InsertVaRSummaryFigure or Call InsertVaRSummaryFigure("SecondSheetInBla") So, try and have a l
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you, helping each other. Join them; it only takes a minute: Sign up Access Compile Error: Argument not Optional up vote 0 down vote favorite I have an access Database, this is similar to a previous question https://social.msdn.microsoft.com/Forums/en-US/4c7402a2-de68-4dce-8a1b-b433e708c87a/excel-vba-complie-error-argument-not-optional?forum=isvvba I asked, with a dropdown and a subform. I want to be able to choose an option from the dropdown and have it open a corresponding subform in the subform below. Here is my code... Option Compare Database Option Explicit Private Sub btnCloseHRForms_Click() DoCmd.Close End Sub Private Sub cmbSelectFrms_AfterUpdate() Select Case selectSubform Case 1 Forms!frm_HRForms!subformHRForms.Form!subform1.Visible = True Case 2 Forms!frm_HRForms!subformHRForms.Form!subform2.Visible = True Case 3 Forms!frm_HRForms!subformHRForms.Form!subform3.Visible = True End Select End Sub Private Sub Form_Load() Dim dba http://stackoverflow.com/questions/14042449/access-compile-error-argument-not-optional As Database Dim rst As Recordset Dim SQL As String Set dba = CurrentDb Set rst = dba.OpenRecordset("tbl_Forms", dbOpenDynaset, dbSeeChanges) SQL = "SELECT ListName FROM tbl_Forms" Set rst = dba.OpenRecordset(SQL, dbOpenDynaset, dbSeeChanges) Set rst = Nothing Set dba = Nothing End Sub Function selectSubform(ID) Dim dbacurrent As Database Dim rstcurrent As Recordset Dim SQL As String Set dbacurrent = CurrentDb SQL = "SELECT * FROM tbl_Forms WHERE ID = " & ID Set rstcurrent = dbacurrent.OpenRecordset(SQL, dbOpenDynaset, dbSeeChanges) selectSubform = rstcurrent.Fields("ID") Set dbacurrent = Nothing Set rstcurrent = Nothing End Function Any suggestions? New to Access VBA forms function vba access-vba subform share|improve this question asked Dec 26 '12 at 15:14 designspeaks 95118 where does the error occur? –SeanC Dec 26 '12 at 15:17 at the cmbSelectFrms_AfterUpdate event –designspeaks Dec 26 '12 at 15:19 Did you manually write out the cmbSelectFrms_AfterUpdate or did you just the drop-down (or form properties) to create the event trigger? Sometimes event triggers have arguments (that are not optional .. hence your error message!) that you wouldn't realize if you didn't build them either from the drop downs in the VBE or the Event handlers in the properties box –Scott Holtzman Dec 26 '12 at 15:25 I used the event handler in the Properties box to locate the event. I tr
here for a quick overview of the site Help Center Detailed answers to any questions you might http://stackoverflow.com/questions/23574083/vba-function-argument-not-optional have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million compile error programmers, just like you, helping each other. Join them; it only takes a minute: Sign up VBA Function - Argument Not Optional up vote 3 down vote favorite Public Function RETURN_Equipment(Optional category As String) As Collection Dim config As classConfiguration Set config = New classConfiguration Dim item As classItem Set item = New classItem Dim vba compile error myCollection As Collection Set myCollection = New Collection For Each config In Configurations For Each item In config.colItems If IsMissing(category) Then myCollection.add item ElseIf InStr(category, "mainframe") <> 0 And item.category = "mainframe" Then myCollection.add item MsgBox "Fired!" ElseIf category = "accessory" And item.category = "accessory" Then Else End If Next Next RETURN_Equipment = myCollection End Function I keep getting Compile error: Argument not optional I get the error on the last line RETURN_Equipment = myCollection I understand the error message, its telling me I did not fill out a parameter. But I only have one parameter, and I've declared it optional. It looks like the code thinks I'm trying to call the function from the function? What gives? excel vba share|improve this question edited May 9 '14 at 21:22 GSerg 47.8k775128 asked May 9 '14 at 21:14 user3403175 32117 possible duplicate of What does the keyword Set actually do in VBA? –Brad May 9 '14 at 21:18 stackoverflow.com/q/5965593/11683