Compile Error End With Without With
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Compile Error End If Without Block If
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Compile Error End Of Statement
#Else If, #Else, or #End If must be preceded by a matching #If #ElseIf must be preceded by a matching #If or #ElseIf and followed by an #ElseIf, #Else, or #End If
Compile Error End Sub
while minimized or maximized A module is not a valid type A procedure of that name already exists A procedure with a ParamArray argument cannot be called with named arguments A property or method call cannot include a reference to a private object, either as an argument or as a return value (Error 98) ActiveX component can't create object or return reference to this object (Error 429) ActiveX Component did not run correctly (Error 338) ActiveX component not correctly registered (Error 336) ActiveX control 'item' not found (Error 363) Add-in can't reference project Ambiguous name detected Application-defined or object-defined error Argument not optional (Error 449) Argument required for Property Let or Property Set Array already dimensioned Array argument must be ByRef Assignment to constant not permitted Automation error (Error 440) Automation object doesn't have a default value (Error 443) Bad DLL calling convention (Error 49) Bad file mode (Error 54) Bad file name or number (Error 52) Bad interface for Implements: interface contains data fields Bad interface for Implements: interface is derived from another pure interface with non-restricted methods Bad i
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Compile Error Expected End Of Statement Visual Basic
Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with compile error next without for us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just https://msdn.microsoft.com/en-us/library/office/gg264572.aspx like you, helping each other. Join them; it only takes a minute: Sign up Compile error: End with without with. BUT THE WITH IS THERE up vote 0 down vote favorite To my working code, I had to ad a new With EndWith. No I can't run it anymore and the second EndWith causes the Error. Compile http://stackoverflow.com/questions/33367173/compile-error-end-with-without-with-but-the-with-is-there error: End with without with. I tried as well to do e nested With EndWith, it didn't work. Any idea? Thanks for any help! This is the required part of the code: With wsSrc LastRow = .Cells.Find("*", SearchOrder:=xlByRows, SearchDirection:=xlPrevious).Row For j = 0 To UBound(SearchValues) For i = 2 To LastRow If .Cells(i, 1).Value = SearchValues(j) Then wsDest.Range("A" & z).Value = .Range("A" & i).Value wsDest.Range("B" & z).Value = .Range("N" & i).Value wsDest.Range("C" & z).Value = .Range("O" & i).Value wsDest.Range("D" & z).Value = .Range("AM" & i).Value wsDest.Range("G" & z).Value = .Range("AH" & i).Value wsDest.Range("I" & z).Value = .Range("P" & i).Value wsDest.Range("J" & z).Value = .Range("E" & i).Value wsDest.Range("K" & z).Value = .Range("F" & i).Value z = z + 1 End If Next i Next j End With With wsSrc2 LastRow2 = .Cells.Find("*", SearchOrder:=xlByRows, SearchDirection:=xlPrevious).Row For k = 2 To LastRow2 If .Cells(i, 1).Value = "724" Then wsDest.Range("B" & z).Value = .Range("N" & k).Value wsDest.Range("C" & z).Value = .Range("O" & k).Value wsDest.Range("D" & z).Value = .Range("AM" & k).Value wsDest.Range("G"
Way | Trading Add-ins For Excel | Convert Excel Into Calculating Web Pages Excel Web Pages | Produce Clean Efficient VBA Code Every Time | Build Automated Trading Models In Excel | Excel http://www.ozgrid.com/forum/showthread.php?t=182131 Web Pages | Excel Video Training Forum New Posts FAQ Calendar Forum Actions Mark http://www.dreamincode.net/forums/topic/216259-end-with-without-with/ Forums Read Quick Links Today's Posts What's New? Advanced Search Forum HELP FORUMS Excel General Compile Error End With Without with Excel Training / Excel Dashboards Reports If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register compile error link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. If you don't like Google AdSense in the posts, register or log in above. Click here to view the relaunched Ozgrid newsletter. Results 1 to 7 of 7 Thread: Compile Error End With Without with Thread Tools Show Printable Version Search Thread Advanced Search August 27th, 2013 #1 kelpot View compile error end Profile View Forum Posts Member Join Date 15th May 2013 Posts 67 Compile Error End With Without with Hello, I keep getting this error but I can't work out why? Could someplease explain? Many Thanks in advance. VB: Sub Prepayjnlpastevalues() ' ' Prepayjnlpastevalues Macro ' Dim LR As Long With Sheets("Schedule") LR = .Range("A" & Rows.Count).End(xlUp).Row .Range("A6:A" & LR).Copy Sheets("Journal").Range("A1").PasteSpecial Paste:=xlPasteValues LR = .Range("B" & Rows.Count).End(xlUp).Row .Range("B6:B" & LR).Copy Sheets("Journal").Range("C1").PasteSpecial Paste:=xlPasteValues LR = .Range("AB" & Rows.Count).End(xlUp).Row .Range("AB6:AB" & LR).Copy Sheets("Journal").Range("D1").PasteSpecial Paste:=xlPasteValues LR = .Range("AF" & Rows.Count).End(xlUp).Row .Range("AF6:AF" & LR).Copy Sheets("Journal").Range("E1").PasteSpecial Paste:=xlPasteValues Dim LastRow As Long, n As Long With Sheets("Journal") LastRow = Range("D1000").End(xlUp).Row For n = LR To 1 Step -1 If Cells(n, 4).Value = 0 Then Cells(n, 4).EntireRow.Delete End With End Sub Excel Video Tutorials / Excel Dashboards Reports Reply With Quote August 27th, 2013 #2 cytop View Profile View Forum Posts . Join Date 1st September 2010 Posts 10,902 Re: Compile Error End With Without with The lines: VB: For n = LR To 1 Step -1 If Cells(n, 4).Value = 0 Then Cells(n, 4).EntireRow.Delete End With Should have and 'End If' rather than an 'End With'. However, you still need the 'End With' to close the 'With sheets...' statement VB: With Sheets("Journal") LastRow = Range("D1000").End(xlUp).Row For n =
14 Replies - 3261 Views - Last Post: 22 February 2011 - 01:17 PM Rate Topic: #1 MonkeyBoy2194 D.I.C Regular Reputation: 3 Posts: 489 Joined: 09-February 09 "End with without with" Posted 15 February 2011 - 07:49 AM I keep getting an error message when I debug saying "End with without with" With pobjLB Do While (True) For intI = 0 To frmChat.lstUsers.ListCount - 1 For intJ = frmChat.lstUsers.ListCount To (intI + 1) Step -1 Do If frmChat.lstUsers.List(intJ) <> frmChat.lstUsers.List(intI) Then Exit Do Else MsgBox "Sorry but that displayname is already in use, please choose another" End If Loop Next Next [b]End With[/b] But as you's can see I do have an "End With", is it to do with the positioning of it? Help would be much appreciated This post has been edited by MonkeyBoy2194: 15 February 2011 - 07:50 AM Is This A Good Question/Topic? 0 Back to top MultiQuote Quote + Reply Replies To: "End with without with" #2 raziel_ Like a lollipop Reputation: 469 Posts: 4,265 Joined: 25-March 09 Re: "End with without with" Posted 15 February 2011 - 08:05 AM the problem is not the end with. lets examen your code. what you do is start with "with" statement: With pobjLB End With then you have a while With pobjLB Do While (True) Loop End With then you have 2 for cycels With pobjLB Do While (True) For intI = 0 To frmChat.lstUsers.ListCount - 1 For intJ = frmChat.lstUsers.ListCount To (intI + 1) Step -1 Next intJ Next intI Loop End With then you have Do With pobjLB Do While (True) For intI = 0 To frmChat.lstUsers.ListCount - 1 For intJ = frmChat.lstUsers.ListCount To (intI + 1) Step -1 Do Loop Next intJ Next intI Loop End With now check how your code looks like compare to this one This post has been edited by NoBrain: 15 February 2011 - 08:10 AM Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #3 motcom D.I.C Lover Reputation: 292 Posts: 1,371 Joined: 16-June 08 Re: "End with without with" Posted 15 February 2011 - 08:08 AM You are missing something, try this With pobjLB Do While (True) For intI = 0 To frmChat.lstUsers.ListCount - 1 For intJ = frmChat.lstUsers.ListCount To (intI + 1) Step -1 Do If frmChat.lstUsers.List(intJ) <> frmChat.lstUsers.List(intI) Then Exit Do Else MsgBox "Sorry but that displayname i